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That is still wrong can someonelse please try thank You. But still thanks for the effort!

By similar triangles, PQ = 5*sqrt(3).

tan = 2 cos tan     divide both sides by 2 tan

1 / 2 = cos

60 degrees and 300 degrees

AQ/QB = 5 / (7 - √24) 

f(f(f(f(1+i))))

f(i+1) = (i+1)² = 2i

f(f(i+1)) = f(2i) = -4

f(f(f(i+1))) = f(-4) = -64

f(f(f(f(i+1)))) = f(-64) = -262144

Guest power

Similar enough that you should be able to do this one:

https://web2.0calc.com/questions/help-please_99054

Use the law of sines

4 / sin45   =   xy/sin120        solve for xy

sin120 *   4 / sin45 = XY 

To find the conjugate of a z    just change the sign of the imaginary part

(-3+5i)(-3-5i) =  9 + 15i -15i- 25i²

                             = 9 - 25(-1) = 9+25 = 34

Thanks so much, hectictar!!! I really appreciate it! ;)

1. A Piano

2. A garbage truck

3. Lightning

4. A sausage

5. Stars

6. Fire

This is a similar question : https://web2.0calc.com/questions/a-right-triangle-has-legs-of-length-10-and-b-and

First, find the slope:

1--5/8--3=6/11.

Then we find the y-intercept:

So for every 11 spaces we go to the right, we go up 6 spaces.

To get an x value of zero, we want to go 3 spaces to the right and we go up 3/11*6 or 18/11 spaces up. 

-5+18/11 is - 3 4/11.

So our equation now is y=6/11x-37/11

Multiply both sides by 11 to get

11y=6x-37

Add 37 and subtract 11y from each side to get

37=6x-11.

37+6-11 is 32.

Find all complex number z such that \(z^4 = 1\).

\(\begin{array}{|rcll|} \hline z^4 &=& 1 \\ z^4-1 &=& 0 \\ (z^2-1)(z^2+1) &=& 0 \\ \hline z^2-1 &=& 0 \\ z^2 &=& 1 \quad | \quad \text{sqrt both sides} \\ z &=& \pm\sqrt{1} \\ \mathbf{z} &=& \mathbf{\pm 1} \\ \hline z^2+1 &=& 0 \\ z^2 &=& -1 \quad | \quad \text{sqrt both sides} \\ z &=& \pm \sqrt{-1} \quad | \quad \sqrt{-1}=i \\ \mathbf{z} &=& \mathbf{\pm i}\qquad\text{Complex solutions} \\ \hline \end{array}\)

1)   a piano  

2)   a garbage truck  

3)   lightning  

4)  

5)   darkness  

6)   fire  

No 4 has me stumped.  

1) 19

1+2+3.../10 = whole number. We can first check 9, where (1+9)+(2+8)... = 45 so that doesn't work. The next number that does work is 19.

2) A

3+6+9+12+15 = 45, 50-45 = 5.Since 15 has groups of 5, 18 has groups of 3, and A falls in as the 5th letter

3) 12345678987654321 (actually)

I did some experiments with smaller number (99*99, 999*999), and you get a pattern of 12321 and 1234321, so with 9, 9's on each side, we get... that number.

4) 306

0 is also an integer, and since we have an even number of terms, we can start from 17, and count back to -18 (where 17+(-17) cancels out). We get that -18 * -17 = 306.

5) 2

we can take out the 1+2 temporarily to get 3+4+5... +327 = (3+327)+(4+326)... (and 327-3 is even so they match up).

Putting back in the 1+2, and adding 2, we get 5.

Domian:

{2,4,5,6}

Thank you!

1. After x months, plant a grows 10x centimeters, and after x months, plant b grows x(x+1)/2 because of the formula for triangluar numbers. this means those two are equal, so 10x=x(x+1)/2 or 20x=x(x+1), which means 20=x+1 so x=19.

Correct! Its ok if you only do a few, just please post the numbers too so I can know if there right! JoLink I know you did post the numbers so you are good! :D

-Grace

By Pythagoras, AB = 10*sqrt(5).

Number 5 is...  Stars?

Number 6 is Fire!

Thats All i've Figured out...

Thank you Alan

As follows