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Using Chinese Remainder Theorem + Modular Multiplicative Inverse, which are incorporated in this computer code, we have:

i=0;j=0;m=0;t=0;a=(9, 7, 5);r= (5, 3, 1);c=lcm(a); d=c / a[i];n=d % a[i] ;loop1:m++; if(n*m % a[i] ==1, goto loop, goto loop1);loop:s=(c/a[i]*r[j]*m);i++;j++;t=t+s;m=0;if(i< count a, goto4,m=m);printc,"m + ",t % c;return

315 m +  311, where m=0, 1, 2, 3.......etc.

The smallest 4-digit integer =[315 * 3 + 311] =1,256

We can just  solve this

[ y  -5 ]   / [  8 -  - 2  ]  =   -1/5

[ y - 5 ]  /  10  =  -1/5        multiply both sides  by 10

y  - 5   =     -2       add 5 to both sides

y =   3

Rounding to the  nearest  tenth  =   345. 7

Rounding to the nearest interger  =   346

Rounding to the nearest ten   =   350 =   largest possible  value

Which equation describes the line through the points (4, -3) and (5, 0)?

Answer Choices:

A= y - 0 = 1/3(x-5)

B= y - 4 = -3(x+3)

C= y +3 = 3(x-4)

D= y - 5 = -1/3(x-0)

This is posted 5 times today....scroll a bit down to find a good answer.....

\(y = -0.2x + 4.6\)

So,

\(y = -0.2*8 + 4.6\)

\(y = -1.6 + 4.6\)

\(y = 3\)

-hihihi

😎😎😎

Using 2 once  =   all arrangements of 5 different digits  =    5!  =   120

Using 2  twice  =   choose  any two  positions for the 2s,  = C(5,2).....choose any 3 of the remaining 4 digits =C(4,3)...and arrange them in 3! ways =  C(5,2) * C(4,3) * 3!   =   240

Using 2 three times =  choose any 3 poisitions for  the 2s  = C(5, 3) ....choose  any 2 of the  4  remaining digits  = C(4,2)  and arrange these in 2!  ways =  C(5,3) * C(4,2) * 2!   =  120

Using 2 four times  =   choose any  4 of 5 positions for the 2s =  C(5,4)   and  for the  other position,  choose  any  1 of the remaining  4 digits...C(5,4) * C(4,1)  = 20

Using all 5  2s =   1 

120  + 240  +  120  + 20  +  1  = 

501   numbers

CPhill that is correct

-hihihi

😎😎😎

start by squaring both sides.

How about doing some of your own homework rather than posting a string of questions obviously from the same set !

x^2  +  1/x^2        square both sides

(x^2  +  1/x^2)  ( x ^2   +  1/x^2)   =

x^4  +  x^2 (1/x^2)  + x^2(1/x^2)  +  1/x^4   =

x^4   +  1   +   1   +  1/x^4    

x^(4) + (1/x^4)   +  2   =   23  +  2   =   25

So

(x^2  + 1/x^)^2    =  25 

So

x^2/ + 1/x^2   =  5         (assuming x is real) 

1 / (1 + .6 + .6) = 1/2.2 = 5/11

Power property of logs

Quotient property of logs

Equality property of logs

1 / (1+.6+.6) = .4545         46/100th of the time     or     45.5 % of the original time

Call the  number  of  hours it takes the  carpenter to finish  the  job =  x

So......the fraction of the  job that he can finish   in   one hour is  1/x

So.....the fraction of the  job that  of the other two can do in one  hour   = .60 (1/x)

So....the total   fraction of work  done in one hour  by all three working together is

1/ x  +  .60 (1/x)  +  .60 (1/x)   =      (1 + .60 + .60) / x  =   (2.2) / x

So....the total time they take is the reciprocal of this  =   x / (2.2)

So....the fration of the time that they would  take  working together compared to  the carpenter working alone  is

( x/ 2.2)   / x   =

(x /2.2) * (1/x)  =   1 / 2.2   =  10/22 =   5/11  of the time

70%=70/100=7/10

So, 70/100 or 7/10 is the fraction version of 70%

-hihihi

😎😎😎

Note that we can  see that there is no solution to this....re-writing, we have

5/ (4x + 3)  = 4 / (4x + 3)

We can't divide 5  by someting and get the same result as dividing  4 by the same someting

So....no solution

https://web2.0calc.com/questions/plzzzzz-halp#r2

7 * 7 * 7 * 7 * 4 = ....... possibles

* * * edit  * * *

first digit    4   choices

   next digit   5 choices

     last digit    2 choices   (only 2 or 4 will make even)

4*5*2=......   possibles

There are 24 ways to choose 6 pies.

There is a link to the same problem