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The question is:

\(\frac34\)   times what is  \(6\frac12\)    ?

\(\frac34x\ =\ 6\frac12\)

Divide both sides of the equation by  3/4

\(x\ =\ 6\frac12\div\frac34\\~\\ x\ =\ \frac{13}{2}\div\frac34\\~\\ x\ =\ \frac{13}{2}\times\frac43\\~\\ x\ =\ \frac{13}{1}\times\frac23\\~\\ x\ =\ \frac{13\times2}{1\times3}\\~\\ x\ =\ \frac{26}{3}\\~\\ x\ =\ 8\frac{2}{3}\)

So...

\(\frac34\)   times  \(8\frac23\)  is  \(6\frac12\)    ...in other words:

The number of times that  \(\frac34\)   goes into  \(6\frac12\)   is  \(8\frac23\)

A even number will have a factor of 2, and any number with 2 as a factor will be even. 

So if your multiply a number with another number that has the factor 2, it'll also have the factor 2, making it even. 

So if a even number has the factor 2, then if it's squared it has the factor 2^2 = 4, meaning that it's a multiple of 4. 

I hope this helped. :)))

=^._.^=

I need it fast I don't need an explanation 

Lateral suface  area  =     2pi * radius  * height

radius  =  5.8 /2  = 2.9   cm

So

2 pi   ( 2.9) ( 10.5 )     ≈  191.3 cm ^2 

X   takes     225/100  = 2.25  hrs =   2 + 1/4  hrs =   2 hrs 15 min to read the book

M takes    225/50   =  4.5  hrs  =  4  hrs 30 mi  to read the  book

M  takes   2hr 15 min more   =   2(60) + 15   =   135 min   more

We actually may have guessed this....since M  reads 1/2 as fast as X, she takes twice as  long  !!!!

225 p / 50 p/hr    -   225 p / 100 p/hr      *   60 m/hr = ............ minutes 

200 * 1.20 =   ???

Using the Law of Cosines

QS^2   = QR^2  +  RS^2    -2  ( 31.9 * 25.2)  cos  ( QRS)

(37.6^2   - 31.9^2  - 25.2^2)   /   [ -2 ( 31.9 * 25.2) ]   =   cos (QRS)

Taking the  cosine inverse  to find angle QRS  we have

arccos [ (37.6^2   - 31.9^2  - 25.2^2)   /   [ -2 ( 31.9 * 25.2) ] ]  = QRS  =  81.46°   =  81.5°

x^4  - 3x^3  + 10x^2 - 24  +   16     =  0

Note  that if we  can   add   the coefficients  and the   constant and  we  get 0 ,  then 1  is a root

1 + 10  + 16    - 3   - 24   =

27  - 27   = 0

So 1 is a root

Using  some synthetic division   to find the  reduced polynomial, we  have

1  [     1       - 3       10          -24         16    ]

                     1         -2            8         -16

        ________________________________

          1        -2        8            -16            0

So....the reduced polynomial is

x^2  - 2x^2  +  8x    -  16       =     0        this factors  as

x (x -2)  +  8 ( x -2)     = 0

(x + 8) ( x -2)     =   0

Setting each factor to 0  and  solving for  x  gives us

x = -8     and   x  = 2

So   the roots are

x =  -8       x  = 1      and     x  =    2

Good work, catmg !  

Very nice, catmg  !!!!

y =   3  / (2c   -3)

y (2c - 3)   = 3

y2c  - 3y    = 3

2yc  =  3 + 3y

c  = ( 3 +3y) / (2y)        "swap"  c  and y

y  = (3 + 3c)  / (2c)  =  the inverse  of  f(c)

f-1(c)   *  f(c)  *  c    =  [ (3 + 3c)  / (2c)]  [ 3  / (2c   -3) ]  * c   =  3(2c + 3)   / [ 2 (2c  -3) ]  =  (6c + 9)  /(4c - 6)

So

(6c + 9) / ( 4c  - 6)    =  (kc + l) / ( mc + n)

k  = 6       l =  9         m   = 4      n   =  -6

So

kn^2  / ( lm)   =    6* (-6)^2  / ( 9  * 4)  =      216  / 36    =    6

(s - x)(s - x) = s^2 + x^2 - 2sx 

We know some of the values so we can plug stuff in. 

(3)(3) = 29- 2sx 

9 = 29 - 2sx

2sx = 20

sx = 10

I hope this helped. :)))

=^._.^=

I had the idea to turn Log(x)^n into n * log(x), I also noticed you use I(n-2) as a part of the equation which I think is not belonging in the question

I was the poster, I just realized that having it as a seperate question was better to get an answer

See https://web2.0calc.com/questions/calc-help_14#r3

Similarto other Q's asked this day:

axis of symmetry is  x = -4    ( from vertex)

this is given by   x = -b/2a

                          -4 = -b/2   so b = 8

x^2 + 8x + c     has the point   -4,8     sub this in to calculate  'c'

(-4)^2 + 8 (-4) + c = 8

  16 -32 + c = 8

    c = 24                            Now  add   b + c .................

Need more info.....

  probably several if with a brush

     many more with a roller

        a WHOLE lot more with an airless sprayer !!

The vertex value of x will be given by    - b/2a     this will be the axis of symmetry 

    -b/2a = -3

     b/a = 6

The vertex defines tha axis of symmetry as   x = 12

    the other x-intercept will be the same distance from the vertex as the one given....only on the OTHER side of the vertex

               x = 9  

...another way to look at it...   the initial KE is all converted to Potential energy....then the arrow stops and begins to fall back down...

     now all of the PE is coverted to KE  (same as the origianal) ....so it will have the same magnituide velocity when it hits the ground as it had going up (though in opposite direction)     -70 m/s

With no air friction, the velocity magnitude up will = the velocity magnitude down

   70 m/s up   initially    will result in 70 m/s down   (or -70 m/s)

Connect OC

And a radius  meeting a tangent forms a 90°   angle

So in triangle   OCD     angle   DOC  = 180 -90  -34  = 56°

And this equals the measure  of  minor arc EC

And  by the tangent-chord theorem,  angle DCE  =(1/2)  the measure  of this arc  =(1/2)(56)  = 28°

*** edit ***

Note that 216 = 6³

(6³ )⁶ = 6¹⁸  =  6^x+6^x+6^x+6^x+6^x+6^x

             6¹⁸ = 6* 6^x  = 6 ^x+1                   Now equate the exponents......can you solve it now?

I answered it here. 

https://web2.0calc.com/questions/can-someone-plz-help-me-on-problem-2

=^._.^=