Let A be the top left vertex of the figure
B =the bottom left vertex of the figure
C = the bottom right vertex
D = top right vertex
E = the intersection of the diagonals
FE = the height we are looking for
Note that triangle ABE is similar to triangle CDE
So the altitude of ABE to the altitude of CDE =12 : 8
Therefore BF = (12)/ (12 + 8) BC = (12/20) BC
So FC = (8/20) BC
And triangle ABC is similar to triangle EFC
So
AB / BC = EF /FC
12 / BC = EF / FC
12/ BC = EF / [( 8/20) BC]
12 = EF / (8/20)
12 (8/20) = EF
96/20 = EF = 24/5 = 4.8 = ?