All Answers 357331 Answers

(a) See the graph below.

(b) g(x) = 2/3*f(3x - 1).

(c) We stretch the graph horiztonally by a factor of 3, then stretch the graph vertically by a factor of 1/2, then shift down 3 units.

Lol your welcome

Haha thanks :)

Wow how are you so good at this problem 

(y*0.2+x*0.05)/10=0.11
x+y=10
Where x cc of 5% solution, y cc of 20% solution.
Transform the rational equation to 20y+5x=10*11, divide by 5,
4y+x=22

Now you have the system
x+4y=22
x+y=10

Subtract second equation from first equation and obtain 3y=12, then y=4.
Because y=4 x has to equal 6.

med in ingredients   = final amount of med

x = 20% volume

10 - x  = 5% volume

.20 (x)   + .05 (10-x)  = .095 (10)       solve for x = the amount of 20%    then 5% = 20 - x   

I'm pretty sure C is the answer since in the passage it says "Slavery soon proved its ability to divest her of these heavenly qualities. Under its influence, the tender heart became stone.." Which shows after slavery her attidude chanhes from being nice and giving to cold and cruel.

Oops ! A is the surface area.

Because  X  and Y  are  midpoints of the  sides of the  triangle.....XY  is parallel to UW

Therefore....angles  XYV  and UWY  are  equal....so

 98 - 6x   = 63  -  x

98   -  63    =  6x   -  x

35  =   5x

x  =  35 /  5    = 7

So  UWY  =  63  - 7  =    56°

Let  the  width  =  w

Then  the  length  =  w  +  5

So.....  width * length  =  area

So

w ( w + 5)  =  36

w^2  +  5w   = 36          subtract  36 from each side

w^2  +  5w    - 36    =    0

9/11 are bored. 

122 aren't bored. 

This means 122 = 2/11

122 ÷ 2 = 61

61 * 11 = 671, which is the number of people at the convention

671 * 9/11 = 549, which is your answer :)

                  x^2        +   ax        +   1

x^2  - 1   [   x^4     +    ax^3       +     0x^2      +    3x        -    b   ] 

                   x^4                          -       x^2

               ____________________________________________

                                  ax^3       +      x^2      +    3x

                                  ax^3                           -   ax

                                 __________________________________

                                                      x^2    +  (3+ a) x

                                                      x^2                             -1

                                                   ____________________________

                                                                   (3 + a)x  + ( 1  - b)   =   0

If  a =  -3    and  b  =   1      we should have no remainder......as EP  found  !!!

Ok thx for the informtion

If you do the long division , you will find that  A has to be -3   and B =1  for there to be no remainder.....

x^2 -1 |  x^4   +   A x^3              +3x   - B              Give it a try....see if you get the same answer as I did ! 

This is a right triangle and you need to find the x-axis and y-axis intercepts

when y = 0    x -axis intercept becomes    2x + 0 = 8         x axis intercept = 4

  when x = 0   y -axis intercept is computed as   2(0) + y = 8         y -axis intercept = 8

so you have a right triangle with legs of 4 and 8    (these are the base and height of the triangle )  

area = 1/2 b * h

         = 1/2 4 * 8 = 16 units²

x^2/49  + y^2/b^2  = 1

a  = 7       =   length of semi-major  axis

c  = 5

b =   sqrt   (7^2  - 5^2)   = sqrt (24)  =   2sqrt (6)

Good job , WDIPT    !!!!

For A i got 7 by doing sqrt 48 but B im a bit confused. I did sqrt(a^2-c^2)=sqrt(7^2-5^2)=sqrt24=2sqrt6. So would the value of be just 2sqrt6 or do I need to do some other step?

A segment with endpoints at A(2, -2) and B(14, 4) is extended through B to point C. If BC = 3*AB, what are the coordinates for point C? Express your answer as an ordered pair.

To  find  C  we  have

[ 14   +  3  (14  - 2)  ,  4 + 3  ( 4 - - 2)  ]     = 

[  14  + 3(12) ,  4  + 3 (6)  ]    =

[ 14  + 36   ,   4  + 18  ]  = 

( 50, 22 )

Assuming  x  is  real.......

Note  that   4 l x  - 1l     can be written as   4sqrt  [ (x -1)^2   ]

So  we  have  that

(x  -1)^2  - 4sqrt [ (x - 1)^2 ]  +  3   =    0

(x - 1)^2  + 3  =    4sqrt [ (x - 1)^2 ]           square  both sides

(x - 1)^4   + 6 (x-1)^2    + 9   =   16 (x - 1)^2

(x - 1)^4  - 10(x - 1)^2  + 9   =  0

Let  (x  -1)^2   =    a.......so we have

a^2  - 10a  +  9  =  0         factor

(a - 9)  ( a  - 1)  = 0

Set  each  factor to 0  and  solve  for a

So

a  = 9        or          a   = 1

So

(x  -1)^2  = 9                   or        ( x  -1)^2    =   1        take  both roots

x - 1  = 3         x  - 1  =  -3              x  -1      =  1         x  -1  =  -1

x = 4                 x =  -2                   x  =  2                    x  =  0

4x  + 12y  =  4(x + 3y)

24  + 36  =   12  ( 2 + 3)

AB = √(10² + 9²) ≈ 13.45

x (x^2 -5x+4) >0

x (x-4)(x-1 ) >0 

roots   0   4    1      we have to determine what the value is between these roots to see if >0 

From 0 -1 it is positive (but = 0 at 0 and 1, so those points are not included)      and from  >  4  to infinity it is positive  

   it is <0 elsewhere

(0,1) U (4, +∞)