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c=0;i=0;p=0;d=reverse(1,2,3,1,4,1,4,1,4,1,4);c=1/(d[i] +c);printc;p=p+1;i++;if(i >Total =",p

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8527 / 12298
 

ok thx pavlov

Here is a picture

The length of median AM of isosceles triangle ABC (AC=BC) is equal to the length of base AB. Find the ratio of AC/AB

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

If  AC = 4 then the altitude AD of a triangle ABM is √7 and BD = 1

AB = √8

AC/AB = √16/√8 = √2 : 1

10mph for 90 minutes = 10 x 1.5 = 15 miles

This means that it took 2 hours to bike 15 miles. This means you're going at 7.5mph

who told you

I think 80 is the hypotenuse......

total distance / total time = average        time = distance/rate

d = distance

d / 7  + d/11=   2d /average

1/7 + 1/11 = 2/average

average = 2 / (1/7 + 1/11) = 154/18 = 77/9 m/hr =   8.56  m/hr

can't it be 80 tan 11 = 15.55
 

With the given parameters, the mass of the hockey puck is NOT required to solve this problem.

However, intelligence slightly above that of a hockey puck IS required to solve this problem.

It’s great to have you back, EP. You are my favorite member to troll.  

GA

S = a / (1-r)

16 ( 1 -1/5) = a₁ = 12.8

80 sin 11 = 15.26 units         

Anther way you can solve this is by completing the square...

then you can use the general formula ...

y = (x-h)^2 + (y-k)^2     where (h,k) is the vertex, 

At first glance, it seems like Heron's formula is needed, but notice that \(\frac{15\cdot20}{2} = 150\). That means 15 and 20 are the length of the legs of a right triangle.

The hypotenuse of that triangle is \(\sqrt{15^2+20^2}=25\), using the Pythagorean theorem.

The perimeter of ABC is therefore equal to \(15+20+25=\boxed{60}\)

Force of friction =   coefficient of friction * NORMAL force      Normal force = m a     = mass * 9.81 m/s^2

    were you not given the mass of the hockey puck?

The number 42 is, in The Hitchhiker's Guide to the Galaxy by Douglas Adams, the "Answer to the Ultimate Question of Life, the Universe, and Everything", calculated by an enormous supercomputer named Deep Thought over a period of 7.5 million years. Unfortunately, no one knows what the question is.

    NOW we know what the question is !

when its about to explode >:33

Subtracct second  equation from the  first

a - b = - 4995        a = -4995 + b

 2009 ( -4995+b) + 2008 b  = 2007

        2008 b + 2009 b = 10036962

            b = 2498.621

  then a =   -2496.379

By similar triangles, CE = sqrt(3)/2.

Mathway is a pretty great website, but it's not for all types of problems.

If You Have Any Issue With Certain Math Problems Try To Use https://www.mathway.com

Because you have a reglular polygon, it can be inscribed in a circle.

The angle A₁A₄A₈ cuts off the arc A₈A₉A₁₀A1.

Thre are three sections to this arc:  A₈A₉, A₉A₁₀, and A₁₀A₁.

Since each portion of this arc is each to every other portion and there are 10 portions in the polygon, the 360^o circumference

of the circle is divided into 10 each parts, each 36^o.

The three sections have a total of 3 x 36^o  =  108^o.

The measure of the angle that you want is one-half of this intercepted arc or 54^o.

[There are other ways to solve this problem.]

I haven't gotten up to that part in my physics classes yet, but you should try using variables to sub for the values you don't know. 

Right now, what you have is this:

initial velocity: 6.0 m/s

final velocity: 0 m/s

Coefficiant of kinetic friction: 0.100

Draw a force diagram. Since it looks like you have more information on velocities, you might be able to find acceleration or something like that, use a few variables and more equations, and solve for the answer.

y = √(12 + x)² - 15²

y = √x² + 9²

This means:
√x² + 9² = √(12 + x)² - 15²

x² + 9² = (12 + x)² - 15²

x² + 81 = x² + 24x + 144 - 225

x² = x² + 24x - 162

162 = 24x

x = 6.75

y = √x² + 9²

   = √(6.75)² + 81

   = √(45.5625 + 81)

   = √126.5625

y = 11.25