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The equation of the circle is (x + 1)^2 + y^2 = 64/25.

x * x * x = 342

3x*3x*3x = 27 x*x*x      second cube is 27 times first cube   difference is  26 times first cube = 26 * 343 = 8918 cm3

f(1) = 5

f(2) = 3

f(3) = 1

Let  y = f(f(x))

When  x = 2,    y  =  f(f(2))  =  f(3)  =  1

When  x = 3,    y  =  f(f(3))  =  f(1)  =  5

So the points  (2, 1)  and  (3, 5)  must be on the graph of  y = f(f(x))

ab + cd   =   2 * 1  +  3 * 5   =   2 + 15   =   17

You first try to find the missing angle on the smaller triangle which is 12 using the Pythagorean theorem(a^2+b^2=c^2)

With that knowledge you plug in 12 and 35 in the theorem which you get 144+1225 =sqrt1369. The squareroot of 1369 is 37 and that's your anwser.

if the "radius" of the square is \(16\) feet, then the length of the diagonal of the square would be \(16 \cdot 2 = 32\) feet. 

because of right triangle properties, \(32 = \sqrt2 \cdot s\), where \(s \) is the side length of the square. so, dividing \(\sqrt{2}\) from both sides, we get 

\(\frac{32}{\sqrt2} = s\)

the area of a square is just \(s^2\), so the area of this square would be \((\frac{32}{\sqrt2})^2\) = \(\frac{32^2}{\sqrt2^2}\) = \(\frac{1024}{2} \) = \(512\).

hope this helped! please let me know if you have any further questions 

if the cube has a volume of 343 cubic centimeters, that means that a side length of the cube is 7 (cube root of 343).

the edge length of the second cube would be 7 * 3 = 21, and the volume of that cube would be 21^3 = 9261.

the difference between the volume of the first cube and the volume of the second would be 9261 - 343 = 8918.

volume  =  area of base * height

First let's work on finding the area of the base. The shape of the base can be broken up into two rectangles, one with length 6 cm and width 4 cm, and the other with length 14 cm and width 12 cm. So the area of the base is the sum of the areas of these two recangles.

area of base   =   (6 cm)(4 cm)  +  (14 cm)(12 cm)

area of base   =   24 cm²  +  168 cm²

area of base   =   192 cm²

Now that we know the area of the base, we can find the volume

volume   =   area of base * height

volume   =   ( 192 cm² )( 2 cm )

volume   =   384  cm³

40/5 = 8 this is the length

5/8 is the ratio

10/16 is a ratio in greater terms

I hope this clearified things up!

First we can draw AC to create right triangle ACE

Since AB = 10 and CD bisects AB at the point E, we can see that AE = 5

Since CD = 10 the radius of the circle is 10, which means AC = 10

Now we have a right triangle where two of the sides are known.

We can use the Pythagorean theorem to find the length of the unknown side.

AE² + CE²  =  AC²

5²  +  CE²   =   10²

CE²   =   10²  -  5²

CE²   =   100 - 25

CE²   =   75

CE   =   √[ 75 ]

CE   =   5√3

in a parallelogram, the opposite sides are congruent.

so, we can create this equation:

2x - 11 = -1 + x

2x - x = -1 + 11

x = 10

now we can find VU by plugging our x value into the expression.

VU = -1 + 10

VU = 9

hope this helped! please let me know if you are confused about anything i did :)

ok, one thing to know. Putting 'homework' in your title will attract less people, because this is your homework, and its your job to solve it. So if you are asking for help, put what you have tried first

we have a sequence that goes \(5, -8, 11...\), so we have 5 + (-3)*50=-145

please confirm...

area of parrallelogram: b*h

square: a^2

triangle: bh/2

so we have 10*7=70

4^2=16

15*4/2=30

30+16+70=116

we have the hockeystick identity which gives you instantly the answer

we can prove the hockeystick identity by using trianglular numbers

good thing to note: sin(x)=cos(90-x)

we have 10*15=150 yds for an uncut rectangle

we then have (10-4)*6=36 for the cut out rectangle

150-36=114 yds squared

can you explain that answer?

thanks

formula for area of a trapezoid: a+b/2*h

so we plug in the bases and we have 70+65+1=136

136/2=68

1224/68=18

so our equation is 1224/((70 1/2+65 1/2)/2), or in Latex, \(\frac{1224}{\left(\frac{(141+131)}{2}\right)}\)

1 is correct!

there are multiple answers...

we have the cycle of powers for 7 for above 3 is:

4. 1

5.7

6. 9

7. 3

Area  of triangle   =  (1/2) base  * height

600 = (1/2)  base  * 20

600   =10 * base

600  /  10   = base   =    60 ft

sin 7A  =  cos  8A

7A  +  8A  =  90

15A  = 90

A = 90 /  15

A  =  6°

Check

sin (7 *6)°  = cos ( 8 * 6)°

sin  42°   = cos 48°       true

x + y = 44

y  = 3x  - 4

So  

x +  ( 3x - 4)  =  44

4x  -  4  =  44

4x   =   44 +  4

4x  =b48

x  =12      and y = 3x  4   =   3 (12)  - 4   =   32

Angle AOX  = 30°

sin AOX   = AX /  AO

sin 30°  AX /  20

20sin 30  =  AX

20 (1/2)  = AX  =  10

OX  = sqrt  ( AO^2  -  AX^2)  =   sqrt ( 20^2  - 10^2)  =  sqrt (300)   =  10sqrt (3)

XY  =  OY -  OX  =   20  -10sqrt(3)   =  10  ( 2  - sqrt (3) )  ≈  2.679