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take the log of both sides.

look up logs in the formulary page to work out what to don next.

draw the rectangle

put the side lengths on

add them up

The answer is exactly -9.

$${\mathtt{2}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2}} = {\mathtt{4}}$$

is the g over -3 or -3+6?

Maybe this will help

I had no idea so I consulted Wolfram|Alpha

Well interesting question BARRY if teh two students on the balcon drop at an angle of 40 degrees they will be sweeped up by spiderman using his web on an axis of awesome. 

Hi i think i have an answer in the form of another question as you said, you need the to determine the rise over run by the anticapation via teh access code. Now i know you said to figuer out the value of the access code you need to x the rise by 4. The only problem is that the access code is encrypted via the run as you did not give us the value of the rise or run but using the alimony method we can fill in the blanks to decifer the same end result using the method. So yes i can help you to decipher this, using my own original values. My values of choice are 8 and 10. So using the 8 and ten we can see that the 8 is the rise off and the ten is the run down. Now in maths language this could be seen as a probability puzzle as where there is light there is magic in the darkness but this is not the case as it is a definitive code of conduct. Follow my steps to figure out how to figure out your problem. If we put the 8 on the ten we get the reversed symbol which we can then figure out using the alimony method the system failure. So we times the nutrients found in a white seeded roll which is on average about 42 nutrients divided by soil. Then using the original values create a systematic ROUTER value which acts as master code to figure out the problem. 

thank you so much CPhill!

2a/15-c

2(16)/15-7

32/8

4

l x - 42.04 l = 23.24

Just solve both of these equations:

x - 42.04 = 23.24          and        x - 42.04 = -23.24

You will have two different answers for "x"

it equals -132884

Im not sure, but I think you might be referring to something also known as the "vertical line" test. Basically, it says that a graph is a function only if a vertical line drawn at any point on the graph interesects the graph just once.

well the rise over run is y/x

it equals 3/12 which simplifies to 1/4

Perimeter of a rectangle = twice the sum of two consecutive sides = 2[(x) + (x + 3)] = 2 [2x + 3] = 4x + 6

The result = 0

When we subtract one "like" thing from another, this always happens..... (expect in the special case of infinity - infinity....!!!)

Disregard the whole number for a moment....we can always express a repeating decimal as a fraction thusly:

Write the non-repeating part and repeating part without the decimal ...here, we'll consider it to be 133   (we could make the repeating part any length, actually)

Subtract the non-repeating part  .....133 - 1  = 132

Put this result over a number that has the number of leading "9s" = the number of repeated digits  and the same number of trailing 0s =  the number of  non-repeating digit(s). So we have 2 repeated digits and one non-repeating digit, so our number is 990...and we have...

[133 -1] / 990 = 132/990  .......check for yourself that this gives us .1333333 etc.

So, apppending the whole number "2," we have  ....   2 + 132/990

Note......you could turn this into an improper fraction if you're so inclined !!!

I think that you mean  e^(-0.09)  and you can use the calc on the home page.

Here's a picture of the situation.......

Notice that, if we consider that each circle is tangent to two other circles at only two points, then the perimeter is formed by 6 half-circles (or alternatively, 3 full circles). And the perimeter of one circle is just pi x d  = pi x 2cm = about 6.28cm. And 3 times this  = 6.28 cm X 3 = about 18.84 cm

(Notice something else of interest.......the perimeter of the "4th" circle is "absorbed" into the interior of the diagram...!!!......thus the total perimeter of all 4 circles isn't "lost'...it's just been "split up")

$$\\\ddot y =9.8\;\;m/s^2\\
\dot y = 9.8t\;\; m/s\\
y=\frac{9.8t^2}{2}=4.9t^2\;\;m\\
\mbox{When y=49 find t}\\
49=4.9t^2\\
10=t^2\\
t=\sqrt{10}=3.16\;\;sec\;\; \quad (to \;2\;dec\;places)$$

We have, assuming the top of the well is at a height of "0,"

-49 = -4.9t²      divide both sides by -4.9

10 = t²              take the square root of both sides

t = √10 = about 3.16 sec

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