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$$\\\frac{5x+1}{x^2 + x -2}- \frac{3}{x+2} \\\\
\frac{5x+1}{(x+2)(x-1)}- \frac{3}{x+2} \\\\
\frac{5x+1}{(x+2)(x-1)}- \frac{3(x-1)}{(x+2)(x-1)} \\\\
\frac{5x+1}{(x+2)(x-1)}- \frac{3x-3}{(x+2)(x-1)} \\\\
\frac{5x+1}{(x+2)(x-1)}+ \frac{-3x+3}{(x+2)(x-1)} \\\\
\frac{5x+1-3x+3}{(x+2)(x-1)}\\\\
\frac{2x+4}{(x+2)(x-1)}\\\\
\frac{2(x+2)}{(x+2)(x-1)}\\\\
\frac{2}{x-1}\\\\$$

30,25,40,35,20,45,50,50 = (arranging them in ascending order) =

20,25,30,35,40,45, 50, 50

To find the mean (average), we just add the numbers and divde by the number of things we summed. So we have

(20 + 25 + 30 + 35 + 40 + 45 + 50 + 50) /  8 = 36.875

The median is the middle number in a group of ordered values. Here, we don't have a"middle number," so the convention is to  sum the middle two values and divide by 2. So we have ( 35 + 40)/2 = 75/2 = 37.5

The mode is the value that appears the greatest number of times......in this case.........50

FV=P(1+r)^n

6050=P(1+0.1)^2

solve for P

12.52*5.88*10^12

Dragon - this is a good one for you    (a nickel is 5 cents and a penny is 1 cent)

1.25miles in 124 seconds  or  (1+3/16)miles in 55seconds

Do the divisions and  find out  

It is just the normal 2nd button but inverse trig is the same as arc trig so 

instead of inverse tan it would be atan 

I like your question Rosala.  

$$27^{2/3}=(27^{1/3})^2=(\sqrt[3]{27})^2=3^2=9$$

thanks Dragon

$$10^1=10\qquad and \qquad 10^{-1}=\frac{1}{10^{+1}}=\frac{1}{10}$$

difference means subtract so.....

you can finish it.

a drag racer starts her car from rest and accelerates at 13.8 m/s^2 for the entire distance of 588m. how long did it take the car to travel this distance?

You can do this with physics formulas or with calculus.  I have used a physics formula

$$\\s=ut+\frac{1}{2}at^2\\\\
u=0,\;\;s=588m\;\;a=13.8m/s^2\\\\
s=ut+\frac{1}{2}at^2\\\\
588=\frac{1}{2}\times 13.8\times t^2\\\\
588*2/13.8=t^2\\\\
t=\sqrt{588*2/13.8}\\\\$$

2.9275/(1-1.00375^-24)   If that is what you mean.

$${\frac{{\mathtt{2.927\: \!5}}}{\left({\mathtt{1}}{\mathtt{\,-\,}}{{\mathtt{1.003\: \!75}}}^{-{\mathtt{24}}}\right)}} = {\mathtt{34.074\: \!391\: \!551\: \!659\: \!807}}$$

Have a look here

Example:

A straight line graph.

It is of the form 

y=mx+b

where m is the gradient and b is the y intercept 

LHS = Left Hand Side

$5-$3=$2

$2 are left.

YES arc sin or asin is the same as the inverse.

Google this.     "How do you turn a decimal number into scientific notation?"

There will be a mathsisfun site thrown up.

Go there and work through the page.

It will help.  

Let \displaystyle f(x) = \frac{1}{x-3} and \displaystyle g(x) = \frac{1}{x-7}. Then the domain of f\circ g is equal to all reals except for two values, a and b with a

$$\\Let \displaystyle f(x) = \frac{1}{x-3} \quad and \quad \displaystyle g(x) = \frac{1}{x-7}. \\\\
\mbox{Then the domain of $f\circ g$ is equal to all reals except for two values, a and b with a }$$

$$\\f \circ g=\dfrac{1}{\frac{1}{x-7}-3}\\\\
=\dfrac{1}{\frac{1-3(x-7)}{x-7}}\\\\\\
=\dfrac{1}{\frac{-3x+22}{x-7}}\\\\\\
=1 \div \frac{-3x+22}{x-7}\\\\
=1 \times \frac{x-7}{-3x+22}\\\\
=\frac{x-7}{22-3x}\\\\$$

NOW     x cannot equal to 7 or 22/3  because you cannot divide by zero!

$$x \in R \quad where \;x\ne7 \;and\;x\ne \frac{22}{3}$$

Ok thank you.

Ok thank you!

It means Left Hand Side   LHS

What is the LHS?