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:o I got the same answer!!

The sum of the central angles of a circe is  360^o.

--->   65^o  +  62^o  +  2x^o  +  (x + 50)^o =  360^o

                                        3x^o + 177^o  =  360^o

                                                    3x^o  =  183^o

                                                      x^o  =  61^o

Yeah, that makes sense.

The positive divisors of 12p are:  1p,  2p,  3p,  4p,  6p,  and  13p.

Summing these values (1 + 2 + 3 + 4 + 6 + 12) we get  28p.

hm..

wait but wouldn't you be able to get different factors with the factors of 12? 

I was confused on this but you might be right!

The sum of the divisors is 1 + 12 + p + 12p = 13p + 13.

I think they meant for both of them.

Привет, гость!

Сначала преобразуйте элемент в десятичную форму:

\(\sqrt{3}=1.73205\dots \)

\(0.95\cdot \:1.73205\dots \)

Умножьте числа:

1.64544444...

Надеюсь, это помогло! :)

( ﾟдﾟ)つ Пока

-5i^2 + 120 i = P     will be max at   i = -b/2a      where a = -5    b = 120

          max will be   at   i =  -120 / (2* (-5)) = 12 amps

Distance = x

x / [x/60 * 2/3    +   x/50 * 1/3  ]                  'cancel out' the x's  and simplify/reduce a bit

1/(1/90 + 1/150) = 56.25 m/hr average

Hey there, Guest!

So as we can see in the picture, the two sides are the same length; therefore, the two bottom angles are also the same.

And as previous knowledge tells us, the sides of a triangle always add up to 180º.

Now, the equation should be:

180°- (74°+74°)

Then, we simplify the equation:

180°- (148°)

And then again:

32

Can we simplify 32/A any further?

The answer is no; therefore, the final answer is 32/A.

Hope this helped! :)

( ﾟдﾟ)つ Bye

Triangle area = 1/2 b * h = 1/2  14 * 8

trapezoid area =   (4+14)/2 * 10                cm^2      add the two areas together

The x-coordinate of the center of the hyperbola is 5 + 2*sqrt(2).

I found them and thought they were perfect (╯◕_◕)╯

-wolfie!

That just proves it's not a quadratic? How does it prove anything else

Your trip would be shorter by 7/8 of a mile.

Yep got the same answer as you

180 different battalions can be sent.

My answers are way off 0-0 Im pretty sure yours is more reasonable though

There are 6!/(1*2*3) = 120 ways of arranging the balls.

Yeah Lol

Wait really?