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Wow everyone is so smart :o

It could've just glitched I guess?

Thank you so much!!!

The sum of the interior angles of any triangel is 180^o ... so, just add them up.   

(5x + 30) + (x + 52) + 62  =  180   

6x + 144  =  180  

          6x  =  36   

            x  =  6  

angle K    =   x + 52   =   6 + 52   =   58             The answer is B.   

_.

Hello Guest!

\(101^{4} - 4 \cdot 101^{3} + 6 \cdot 101^2 - 4 \cdot 101 + 1=\color{blue}100\ 000\ 000\)

  !

You can compute the probabilities of getting all red, all white, and all blue.  Adding them up, you get 144/455.

Yay! Thank you!

I don't know why your answer was flagged. Sometimes it just happens.

I have made it visible now.

They didn't clairify what movie their going to... BUT anyways, I can solve this for you.

3s + 7(s + 5) = 145

10s + 35 = 145

10s = 90

s = 9

9 + 5 = 14

I could tell that your on Delta math doing homework.

If you keep asking, you should rather ask what is Sin and Cos!

-WillBill

I could tell that your on Delta math doing homework.

If you keep asking, you should rather ask what is Sin and Cos!

-WillBill

NO = 7*6 / 14  = 3

6.5 * 10^10

-WillBill

= 700

-WillBill

Base Ate

Nice job!!

The CRUMS Hunt :D

Note that the decrease from FD to GH is proportional to the decrease from ED to EG.

Since GH is 1/2 of FD(6 is 1/2 of 12), we can deduce that  EG is 1/2 of GD:

1/2(ED) = EG

1/2((x+5)+9) = x+5

1/2(x+14) = x + 5

x + 14= 2x + 10

4 = x

Since HF is also 9, we can apply the same logic to EH, meaning that EH = x+5

EH = x + 5

EH = (4) + 5

EH = 9

I assume you meant odd numbers rather than odd-digit numbers.

For a number to be odd, it has to end with an odd digit; in your case, it has to end with either 1 or 3.

If the number ends with a 1, that leaves 2, 3 and 4 to "fill up" the first three spots of a four-digit number.

2, 3, and 4 can be arranged in 6 distinct ways, meaning there are 6 numbers that fit your criteria when the number ends with 1.

The same applies when the number ends with 3, for which exist another 6 distinct numbers that fit your criteria.

6+6 = 12 total numbers that fit your criteria.

So when you split up the shape into 1 rectangle and 1 triangle you can find out the area of the rectangle would be 11*48=528. Now for the triangle to the formula is H*B/2 so here the H = 10 and B = 48 so using the formula you get 240 and then you add 528+240 and you get 768 would be your answer.

The Area of the bottom-most rectangle is 60 * 20 = 800 u².

The Area of the "ring" is simply the difference of the two circles with the inner and outer radii.

Inner radius = 50 - 20 = 30u

Outer radius = 50u

Area = πr_outer² - 30πr_inner²

Area = π50² - π30²

Area = 2500π - 900π 

Area = 1600π u²

The Area of the "V" in the center can be simply divided up into two congruent parallelograms and a trapezoid.

Area_parrellogram= bh = 30*10 = 300 u²

Since we have 2 of these, the total is 300*2 = 600 u²

Area_trapezoid= h(a+b)/2 = 15(10+20)/2 = 15*30/2 = 225 u²

Area_"V"= 600 + 225 = 825 u²

Now the total area is the sum of the areas of the "V", the ring, and the rectangle. (Sum of everything underlined)

825 + 1600π + 800 = 1600π + 1625 u²

From above, we can deduce that a = 1600, and b = 1625.

Therefore a+b = 3225 u².