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I usually look at the posting history of members before I answer them.

Your posting history tells me that you ignore your answerers.

So for the moment at least, I will ignore you.

105=3*5*7

total : 3!=3*2*1=6

I'm not quite sure, but I think it could be about 11 percent, becuase if some of the knifes have been moved, then there is a 5 out of 45 percent chance to also have wanted the plate moved?

Perimeter = 231.4 cm

The points N, O, P and Q all lie on the same line segment, in that order, such that the ratio of NO:OP:PQ is equal to 5:2:1.  If NQ = 24, find NO.

NO = 5(24 / 8) = 15

Angle A = 5/6(90) = 75

Angle ACH = 180 - 90 - ∠A = 15

Angle HCL = 45 - 15

∠HCL = 30º

DB / 12 = 12 / 16

DB = 144 / 16

DB = 9

Area = 21[(2 * 15 + 20) / 2]

11x + 2 = 2(5x + 2)

11x + 2 = 10x + 4

x = 2

LW = 5x + 2 = 12

Angle ABE = 1/2(360 - 65 - 37)

To answer this, you will need to know a property about parallelograms.

The property states: The diagonals of a parallelogram bisect each other.

Bisect: To split into 2 equivalent parts.

We'll put that to the side for now, it will come handy later into this explanation.

We know that...

\(LW = LJ - WJ\)

\(5x + 2 = 11x + 2 - WJ\)

So, what's WJ?

Let's refer back to what we said earlier.

The diagonals of a parallelogram bisect each other.

Now we know that \(LW = WJ\).

We can change our equation to make it solvable.

\(5x + 2 = 11x + 2 - (5x + 2)\)

\(5x + 2 = 11x + 2 - 5x - 2\)

\(5x+2=6x\)

\(x=2\)

Now substitute the value of x into 5x+2.

\(5x+2=5(2)+2\)

\(5x+2=12\)

\(LW = 12\)

And you are done!

(3x+2)

draw it out it might help

The answer is $\frac{\sqrt{2} + \sqrt{6}}{6}$.

First, let the Orange ****s be o and the green ****s be g.

Then:

g = 8 + 2o

8 + 2o + o = 59

3o = 51

o = 17

g = 8 + 2 * 17 = 8 + 34 = 42

So theres 17 Orange ****s and 42 Green ****s.

I'm sorry, but that is incorrect. Thank you so much, and I appreciate your effort. You'll get it next time for sure!

Hey there!

Here I'm going to assume that the angles and lengths represented by the unknowns are equivalent. Thus we can let them equal eachother and solve for the unknowns. For \(x\)

\(3x+3=6x-18\)

\(3x=21\)

\(\therefore x=7\)

For \(y\):

\(7y-3=2x+4\)    we know what \(x\) is so we can sub that in and solve for \(y\)

\(7y=21\)

\(\therefore y=3\)

Hope this helped :)

Hey there!

From your definitions we know that there are 26 red cards in the deck. I'm assuming that there is no replacement when the first card is drawn. The chance of you drawing a red card first is \(\frac{26}{52}\) then, since a red card is removed from the deck, the chance of getting a second red card is \(\frac{25}{51}\). We then multiply this together to get the probability of this occurring:

\(\frac{26}{52}\times \frac{25}{51} \approx 0.2451 \approx 24.51\%\)

Hope this helped :)

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GA

I don't mean to criticize, because the work is very good, but an error in the first line messes up the total.  

The first line,   The Area of the bottom-most rectangle is 60 * 20 = 800 u².    should equal 1200. 

Hey there!

Since the first number cant be zero there are only 9 options (1 thru 9), however for the next seven they can be zero, thus there are 10 options (0 thru 9). for the letters, the first option will be 5 as and the second will be 4 as there is no replacement. This gives:
 

\(9\times 10^7\times 5\times 4=1800000000\)

Thus there are 1.8billion possible student numbers

I could be wrong here but I do believe this is how you do it... Hope this helped :)

Thankyou!

There are a total of 6 + 5 = 11 marbles in the bag.

The chance of not getting a red marble is 6/11 for one try.

With the second try, the chance of not getting a red marble is again 6/11.

Therefore, the probability of not getting a red marble on either try is 6/11 * 6/11 = 36/121

From here, the chance of getting a red marble on either try is 1 - (36/121) = 85/121.

Let x represent the length of DB.

AC =  √(16² + 12²) = √400 = 20

CB = √(x² + 12²)

AB = x + 16 

Note that △ABC is right, meaning that AC² + CB² = AB².

Substituting values for AC, CB, and AB, we get:

20² + [√(x² + 12²)]² = (x + 16)²

400 + x² + 12² = x² + 32x + 256

544 + x² = x² + 32x + 256

544 = 32x + 256

288 = 32x

x = 9

Therefore the length of DB is 9.

The answer is 2.