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By Vieta....

sum  of  the roots   a + b  =  - (-7)/ 2 =  7/2

product of the roots   ab   =  2/2  = 1

Note  that     

1/ (a - 1)  + 1/ (b - 1)  =    ( b - 1 + a - 1) / ( ab - a - b + 1)  =   ( a +b - 2)  / ( ab + 1 - ( a + b))

Filling  in what  we  know  we have

( 7/2 - 2)  / ( 1 + 1 - (7/2) )  =

( 3/2)  / ( -3/2)  = 

-1

Sorry but when I looked at it, it was locked so I couldn't answer it but thanks for the tip

It is a ASY, so the latex won't work

A note for next time:

If you know the answer is wrong you should say so on the original. (with your reason given)

And if you knew that the original quation was there, this one should have been done as a repost.

(With the address of the original)

I have answered on the original thread.

a and b have 7 prime factors in common.

a*b has 28 prime factors

so the number of prime factors of a or b that are not common to both is 21

a has less prime factors than b so at most 10 of these 21 extra prime factors belong to a

So the most prime factors that  a  can have is  7+10 =17

First, we observe that the graph of y=f(x) consists of line segments, connecting the points (-4, 4), (-1,0), (0,2),  and (4,-4).

So to plot the graph of y=g(x) we can apply the transformation  \((a,b) \to \left( 3a - 1, \frac{b}{2} \right)\) to each of these points, and then connect them. This gives us the points (-13,2), (-4,0), (-1,1), and (11,-2).  

 Hope this helps! 

I got it working.

Here is my solution:    mostly remember that angles of a triangle sum to 180     and a straight line is also 180 degrees.

Ok, if i can get the diagram working, I might be able to answer the questions.

Yeah... I looked at that one, I wasn't able to understand what they are saying though, thanks for the help!

This link might help a bit

https://web2.0calc.com/questions/help-pls-due-today-help-needed-asap

It's okay, I understand, can anyone else help? It's due tomorrow for me.

Sorry about that but thank you for letting me know. 

Yes, I think it is.

You can just use any right-angled triangle (and ignore the minus signs)

But you have to think about the minus afterwards to get the right quadrants.

Thank you so much, but that answer is incorrect. The correct answer is 17.

This is not all that hard.

Let x be  the number of students in the class

so  x/2  are less than 12

x/6 are  are older than 13

So what fraction are between 12 and 13?

Can you take it from there?  Show us what you can do?

Sorry that I can't do the problems (a) and (c) because the LaTeX code is too complicated for drawing the diagram. I hope you understand

https://web2.0calc.com/questions/help-asap_33

Check this link if the answer is right.

Hope this link helps!

(b): 

Take a point (a,b)  on the graph of y=f(x), so b=f(a). Since \(\left( 3a - 1, \frac{b}{2} \right)\) lies on the graph of y=g(x) we have that \(\frac{b}{2} = g(3a - 1). \)

Substituting b=f(a) we get \(\frac{f(a)}{2} = g(3a - 1).\)

In order to express g(x) in terms of f(x) we can let x = 3a-1 Then a=\(\frac{x + 1}{3}\), so

                                                       \(g(x) = \frac{f(a)}{2} = \frac{1}{2} f \left( \frac{x + 1}{3} \right).\)

We can start with cases

Case 1: How many of the one digit numbers have the digit 1? We easily know that there is only 1

Case 2: How many of the digit one is written from 10-19? We count that there are 10 digit ones in the first digit and one digit in the last digit. This gives us 11 digit 1 written.

Case 3: How many of the digit one is written from 20-49. There is only three which is 21, 31, and 41.

This gives us the total of 15 digit one written.

Hope this helped! 

1   10    11   21   31   41     12   13   14   15   16   17  18  19       15 times

7¹ x 7¹ x  7¹ x 7¹ = 7^(1+1+1+1) = 7⁴      so  z = 7    y = 4

8 x 8 = 8²       so x = 2

Solve for y

2y-3 = x

2y = x + 3

y = 1/2 x + 3/2

Solve for y: 2y = -3 - x, y = -3/x - x/2