1.A 26-inch bicycle is pedaled so that the tires rotate at a rate of 200 revolutions per minute. A 20-inch bicycle is pedaled so that its tires rotate at a rate of 200 revolutions per minute, as well. What is the linear velocity of each bicycle? State your answers in inches per minute, rounded to the nearest tenth.
Linear velocity f 26 inch bike = 13 * 2pi * 200 = 16336.3 in /min
Linear velcity of 20 inch bike = 10 * 2pi *200 = 12566.5 in / min
2.Typically, the speed at which a bicycle moves is expressed in miles per hour. Convert the linear velocity of the 26-inch bicycle and the 20-inch bicycle to miles per hour. Round your answer to the nearest tenth.
26 in bike = 16336.3 in x 1 ft / 12 in x 1 mile / 5280 ft x 60 = 15.5 mph
20 in bike = 12566.5 in x 1 ft / 5280 x 1mile / 5280 ft x 60 = 11.9 mph
3.How many more revolutions must the 20-inch bicycle complete to have the same linear velocity as the 26-inch bicycle? Round your answer to the nearest tenth.
10 * 2pi * R = 16336.3
R = 16336.3 / ( 20pi) = 260
So....the 20 in bike must rotate 60 more revs per minute to have the same linear velocity as the 26 in bike
4.What is the angular velocity of each bicycle? Write your answer in exact form in radians per second.
Since each rotates 200 times in a minute....they have the same angular velocity
This is 200 * 2pi /60 = (20/3) pi rads /sec
5.How many complete rotations does either bike complete in one second?
(20/3) pi = 6 + 2/3 rotatations per sec = 6 full rotations per sec