All Answers 355923 Answers

3
4

5

6

what is the answerrrrrrrr

danke! (thanks in german)

8/10 = 80/100 because 80/10 simplified is also 8/10.

Oh! Sorry for the misunderstanding! 

lets say emmet has e points. this means Eric has 2e points.

2e$\cdot$2=e+30

3e=30

e=$\boxed{10}$

Prove that any triangle whose sides have lengths in the ratio 1:√3:2 is a right triangle. 

a² + b² = c²

1² + (√3)² = 2²

4 = 4 

lets say bert has b points, so ashton has 3b points.

3b$\cdot$2=b+35

5b=35

b=$\boxed{7}$

3.5+3.5-1.2+3.5+1.5=12-1.2=$\boxed{10.8 \ km}$

Is it .45?

There are 20 possible angles.

The probability is 1/8.

so it would be scores below 75?

1. if AB=12 then BC=12 so AC=12+12=24

2. call the point of dilation o for origin.

X'O=3XO

X'X=4XO

same goes for y

so

XY=1/4 of 2 = 1/2

6 x 4 / 7 = 24 / 7

42 / 7 - 24 / 7 = $\boxed{\dfrac{18}7}$ cups

Thank you

2 2/3 + 2 3/4 + 3 1/3= 5 3/3 + 2 3/4 = $\boxed{8\dfrac34}$

Set  the y's  equal

x^2 +  a  =  2ax

x^2  -  2ax  +  a  =  0

If  these   intersect once  then......

(2a)^2  -  4a  =   0

4a^2  - 4a  =  0

a^2  - a  =  0

a ( a - 1)  =  0

Set  each factor to 0   and  solve  for a  and we  get  that

a   = 0     and  a  = 1

The  sum is  1

sin GAC = 2/3.

720-100-110-149-91=720-450=270

so the sum of X and Y is 270. you cannot find the actual degrees.(well atleast in no way that I know of)

There are 158 ways to distribute the bracelets.

5 = 9a+3b+c

8 = 0 + 0 + c

c=8

-3 = 9a + 3b

m = 16a+4b+8

m-8 = 16a + 4b

m-5 = 7a +b

3b = -9a - 3
b=-3a-1

m = 5 + 4a-1 = 4a+4

m=a2^2+b2+8

2b+8=4

b=-2

a=1/3

m=4+4/3=$\boxed{\dfrac{16}3}$

THX, AnxiousLlama  !!!

I think  that  the  first one  isn't  4  separate problems.....I  think  it's supposed to be

(x^2 + 4x + 3)   /   (2x - 1)

____________________

(x^2 + x)  / (2x^2 - 3x + 1)

This  can be expressed  as

(x^2 + 4x + 3)          (2x^2  - 3x  + 1)

___________   x    ______________                   factor  where possible

    (2x - 1)                (   x^2  +  x )

(x + 3) ( x + 1)         (2x - 1) ( x  - 1)

___________   x     _____________                "cancelling"  we  get

    2x - 1                       x ( x + 1)

 (x +  3)  ( x - 1)            x^2  + 2x   - 3

_____________   =     ___________  

           x                              x

Let's assume the integers are a-2, a-1, a, a+1, a+2.

Now, according to question 

⇒\(a(a+2) =483\)

⇒\(a^2+2a-483 = 0\)

⇒\((a+23)(a-21)=0\)

∴ a = -23 or 21

Obviously, since a is negative,

⇒ a = -23

∴ 5 consecutive negative no.s are = -25, -24, -23, -22 and -21. 

~ Hope this helps :)