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Thanks so much Melody :D

That is an apppoximation but thanks Dragon.  

Rosala has treated this question like a proof.

And yes Rosala if it had been presented as 'prove' your answer would be 100% correct.

It is not wrong anyway - but there is not question here.  It is just a statement.    

(I've added this because Rosala has asked me to comment further)

I  can't say much more than this.  Sorry Rosala.     

$$cx^2+2x=x^3-cx\qquad $for $ x=2$$

sub in x=2 and solve the equation for c   

$$\\4c+4=8-2c\\
6c=4\\
c=2$$

We are talking real numbers here so the number under the square root must be positive.

$$\\2sinx-\sqrt3\ge0\\\\
2sinx\ge\sqrt3\\\\
sinx\ge\frac{\sqrt3}{2}\\\\$$

for starters  sinx must be positive so it must be 1st and 2nd quad only.

$$asin(\frac{\sqrt3}{2})=\frac{\pi}{3}$$       the second quadrant equivalent is   $$\pi-\frac{\pi}{3}=\frac{2\pi}{3}$$

$$\frac{\pi}{3}\le x \le \frac{2\pi}{3}$$

I know this because sin(pi/2)=1    and I know what the sine curve looks like so I know the answer will be between these two values.      

Woot woot!

This answer is good.  

Well, you would show the working the same as I did.

But the question actually asks you for where it is continuous.

So the answer would be

continuous when

x<-4, -4<x<0, 0<x<4, and x>4

OR

$$(-\infty,-4), (-4,0), (0,4), (4,+\infty)$$

Don't worry! I guess Admin has introduced this new feature! But this was from very before when some changes wre made in the site , i got to know bout it a long ago!

There is no number for the variable x.

$$x=?$$ Please put the given information.

$${\frac{{\mathtt{5}}}{{\mathtt{2\,800}}}}{\mathtt{\,\times\,}}{\mathtt{68.25}} = {\frac{{\mathtt{39}}}{{\mathtt{320}}}} = {\mathtt{0.121\: \!875}}$$

Standard Form is a number.

Example: 534

$${{\mathtt{e}}}^{{\mathtt{e}}} = {\mathtt{15.154\: \!262\: \!241\: \!479\: \!259}}$$

The Range is the difference between the lowest and highest values. Example: In {4, 6, 9, 3, 7} the lowest value is 3, and the highest is 9. So the range is 9-3 = 6. It is that simple! But perhaps too simple ... The Range Can Be Misleading The range can sometimes be misleading when there are extremely high or low values. Example: In {8, 11, 5, 9, 7, 6, 3616}: the lowest value is 5, and the highest is 3616, So the range is 3616-5 = 3611. The single value of 3616 makes the range large, but most values are around 10. So you may be better off using Interquartile Range or Standard Deviation. Range of a Function Range can also mean all the output values of a function, see Domain, Range and Codomain.

$$\frac{1}{3}*\frac{6}{11}=\frac{2}{11}$$

It is so large, that it is an never ending number

Example: 9999999999999999999999999999999999999999999999999999

999999999999999999999999999999999999999999999999999999999999 9999999999999999999999999999999999999999999999999999 999999999999999999999999999999999999999999999999999999999999 9999999999999999999999999999999999999999999999999999 999999999999999999999999999999999999999999999999999999999999 9999999999999999999999999999999999999999999999999999 999999999999999999999999999999999999999999999999999999999999 9999999999999999999999999999999999999999999999999999 999999999999999999999999999999999999999999999999999999999999 9999999999999999999999999999999999999999999999999999 999999999999999999999999999999999999999999999999999999999999 9999999999999999999999999999999999999999999999999999 999999999999999999999999999999999999999999999999999999999999 9999999999999999999999999999999999999999999999999999 999999999999999999999999999999999999999999999999999999999999 9999999999999999999999999999999999999999999999999999 999999999999999999999999999999999999999999999999999999999999 9999999999999999999999999999999999999999999999999999 999999999999999999999999999999999999999999999999999999999999 9999999999999999999999999999999999999999999999999999 999999999999999999999999999999999999999999999999999999999999 9999999999999999999999999999999999999999999999999999 999999999999999999999999999999999999999999999999999999999999 9999999999999999999999999999999999999999999999999999 999999999999999999999999999999999999999999999999999999999999 9999999999999999999999999999999999999999999999999999 999999999999999999999999999999999999999999999999999999999999 9999999999999999999999999999999999999999999999999999 999999999999999999999999999999999999999999999999999999999999 9999999999999999999999999999999999999999999999999999 999999999999999999999999999999999999999999999999999999999999 9999999999999999999999999999999999999999999999999999 999999999999999999999999999999999999999999999999999999999999 9999999999999999999999999999999999999999999999999999 999999999999999999999999999999999999999999999999999999999999 9999999999999999999999999999999999999999999999999999 999999999999999999999999999999999999999999999999999999999999 9999999999999999999999999999999999999999999999999999 999999999999999999999999999999999999999999999999999999999999

It wasn't a company, I guess. admin made the website, by himself I guess. It was not a company. But thanks for asking.

Correct me if I'm wrong somebody. I'm not 100% sure with my answer, but this is how I solved this:

$$[(1+x)^{200}]^{\frac{1}{200}}=2000^{\frac{1}{200}$$

$$1+x =1.03873592$$

$$x=0.03873592$$

--------------------------

When you plug .03873592 into the equation: (1+x)²⁰⁰ = 2000

you get the number 2000.000018 which is REALLY close to 2000. 

Again, I'm not sure of my answer so sorry guys if I'm wrong :/

Pure welcomness. At your service.

Ah, okay. So I can just list where the function is discontinuous as the answer for questions like this? I can't find any similar problems in my Calc textbook :/

Also, thanks for the helpful list DragonSlayer :)

gliu1, just say where and I will help.

In the LaTex Formula?

Dragon do you know how do I do the Fraction part at to upper right corner on the calculator? Help me. (I helped you so many times) :)

Your name makes me think of the book Eragon with the dragon Saphira