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No problem

Rate of  change   =  slope between  ( 2010, 8)  and (2011, 26)   =     (26 - 8) / (2011 - 2010)   =   18 /  1   =   18

thank you so much!

Thank you so much for taking time out of your day to help me with this, but that was not the right answer

The smallest possible value of f(t) is 54.

I hope this is helpful but:

F=ma

f=200for the softball and f=150 for the baseball

Since they both have the same amount of force, then 200=150. This means that the ratio of the acceleration of the softball to the baseball is 150:200 or 3/4.

The image point is (-y,-x).

A + B + C = 14.

sqrt (16)  =  4

sqrt (10000)    = 100

So.....the  number  of positive integers  = 

9999  -  17  +  1   =    

9983

We  have  three  areas to  consider

A  3 x 2  rectangle at the bottom left =  6  units ^2

A 1 x 1   square in  teh middles  = 1 unit^2

A  2 x 3  rectangle  on the  right=  6 units^2

So

6 + 1 +  6     =     13 units^2

what the...

i think you did formula for direct not inverse

oof its incorrect

The rate of change the number of of students increased divided by the change in time. 

x = number of students increase from 2010 to 2011. 

y = years passed between 2010 and 2011. 

Then do x/y.

=^._.^=

I hope this is helpful🙃

I believe you can set up a proportion for this. So:
d/c = d/c or 8/9 = x/6
*cross multiply*
9x = 48
*divide both sides by 9 to get x by itself*
x = 5 1/3 

Slope  of  given line    =   -B/A =   -1/3

Equation of    line  with  this slope  passing through  (-7,2)

y = (-1/3) (x - - 7)  + 2

y = (-1/3)(x + 7)  + 2

y = (-1/3)x  - 7/3  + 2

y  = (-1/3)x   -  1/3         multiply through by  - 9

-9y  =  3x  + 3                rewrite as

-3x  - 9y  =  3

B = -3     A  =  -9

B - A    = 

-3 - (-9)  =   6

Writing 2x+3y=21 in slope-intercept form, we have y=-2/3x+7, meaning the slope is -2/3.  If the line mentioned is parallel, then it must have the same slope.  Thus, the line passes through the points (2, -9) and (j, 17) and has a slope -2/3, directly translating to \(\frac{17-(-9)}{j-2} = -\frac{2}{3}\).  Solving this equation, the solution is \(j = -37\)

\(N=25- \sqrt(561)/4 \)

\(N=(25+ \sqrt(561))/4\)

To  have  real roots, the discriminant must be  ≥  0

So

(2p+2)^2   - 4 (3/4) ( p^2 + 2)   ≥  0

4p^2  + 8p  + 4  -  3p^2  - 6 ≥  0

p^2  +  8p  - 2  ≥  0       complete  the square on p

p^2  + 8p   + 16 ≥   2  + 16

(p + 4)^2  ≥  18       take the positive root

p + 4 ≥  sqrt (18)

p ≥  sqrt (18)  -  4   ≈   .2426 =  the  smallest  approx.  +  value of p that will give real roots

I've read the question twice, but I couldn't find the word cone. 

Cylinder height    h = [216 - 2(r²pi)] / 2r*pi

                            h = 15.18873386 cm

\(\frac{5n}{n-4}+3=\frac{3n+8}{n-4}\)

\(\frac{2n-12}{n-4}=\frac{3n+8}{n-4}\)

\((2n-12)(n-4)=(3n+8)(n-4)\)

notice that I don't divide both sides by n-4. (because n-4 can equal 0)

\(2n^2-20n+48=3n^2-4n-32\)

\(n^2+16n-80=0\)

\((n+20)(n-4)=0\)

\(n=-20, n=4\)

JP

Try and use the quadratic formula. Remember that if: \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\) has real roots, which part of the formula must be positive? Then substitute all the terms in.  

Thank you so much :)