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No biggie....just a math mistake.....you  had  the correct approach   !!!!

Yeah sorry i messed up my math

CPhill, I don't think thats correct tho, the ans is 12.

Nice solution Awesomeguy   !!!!

single  digit primes    =   2, 3, 5, 7

2, 3   ⇒       31   not possible         

2  5   ⇒       31   not possible         

2, 7   ⇒       31  not possible                              

3, 5   ⇒       (3, 5, 6 ,8 ,9)

3 ,7  ⇒       (3 ,  4 , 7 , 8 , 9)

5 , 7 ⇒        (4, 5 , 6, 7 , 9 )

P   = (3/6)   = (1/2)

Area of equilateral triangle: $\frac{\sqrt{3}}{4}s^2$

Area of regular hexagon: $\frac{3\sqrt{3}}{2}s^2$

If the perimeter of the triangle is 18, then one side is 6, therefore the area of it is,

$\frac{\sqrt{3}}{4}\cdot36$

$area = 9\sqrt{3}$

Because their areas are equal,

$\frac{3\sqrt{3}}{2}s^2 = 9\sqrt{3}$

Simplify,

$3\sqrt{3}\cdot s^2 = 18\sqrt{3}$

$s^2 = 6$

$s = \sqrt{6}$

There are 6 sides in a hexagon, so the perimeter is, $\sqrt{6} \cdot 6 = 6\sqrt{6}$. 6 + 6 = 12, so that's the answer.

EDIT: I messed up my arithmetic

  Δ  =  5

3215₆   =    3(6)^3  +  2(6)^2  + 1(6)  +   5       =   731

540₆   =     5(6)^2  +   4(6)                               =   204

  52₆   =      5(6)   +  2                                        =   32

                                                                            _____

                                                                             967

4(6)^3  +  2(6^2)  + 5(6)  + 1  =   967

it's a system of equations:

$\frac{1}{p}+\frac{1}{q}=1$ and $pq=9$

$p=\frac{9+3\sqrt{5}}{2}$

$q=\frac{9-3\sqrt{5}}{2}$

the sum is 9

umm??? still the second line is not working. it says:

(1/3)t < t + 3

idk why the first 2 lines are not showing up, it's supposed to say:

$\frac{1}{3}\cdot \:t-5<\:t-2$

\(\frac{1}{3}t

In right triangle DEF, we have angle D =25 , angle E = 90, and EF = 8. Find to the nearest tenth all you can find... 

Angle D = 25º

Angle E = 90º

Angle F = 65º

EF = 8.0

DE = 17.2

DF = 18.9

[DEF] = 68.6 u²

Perimeter = 44.1

Semiperimeter = 22.0

Inradius = 3.1

Cicumradius = 9.5

\(\frac{1}{3}\cdot t-5

\(\frac{1}{3}t

$-\frac{2}{3}t<3$

$\frac{2}{3}t>-3$

$2t>-9$

$t>-\frac{9}{2}$

So in interval notation: $\left(-\frac{9}{2},\:\infty \:\right)$

YESSIR IT IS!!!! 

It's 100?

What is it equal to, and what is the question looking for, x and y? or which one of them

Im lazy to add it but can you sole it plz?? 🤗

7/10 * 7/10 * 7/10 * 3/10 * 3/10 * 3/10

red * red * red * blue * blue * blue

This equals 9261/1000000

But we also have to account for the cases for arranging

there are 6!/3! * 3! ways to arrange each of these, so

9261/1000000 * 20 = 0.18522, or 0.185 

Where is the equal sign?

Find what?

We can multiply the first equation by $pq$,

$1/p + 1/q = 1$

$q+p = pq$

We know that $pq$ is 9, therefore q + p, or p + q, is 9.

ab^5 is basically ab^4 * b. Plugging in known values and simplifying,

$ab^5 = ab^4 \cdot b$

$4608 = 384\cdot b$

$b = 12$

Plug b into one of the known equations,

$a \cdot 12^4 = 384$

$a \cdot 20736 = 384$

$a = 1/54$

So the value of a is 1/54.

15 kids and need to choose 3, 15c3 = 455

Note that if you make b = - 1/2         g(x) becomes   - x^14 - 1.5 x^10 +3 x^8 -x + 1/2   

   when you add this to f(x)   the    x^14  terms will  'cancel out'   and the result is a polynomial of degree  10

  For 'a' the largest degree would be   14  

Take 1/2 of the 'x' coeeficient     = 6       then

  (x+6)^2    will be the start   now expand it to:

   x^2 + 12 x + 36  <======   Note that this added 36 to the equation...so we need to subtract 36

(x+6)^2   -  36  + 9

(x+6)^2  - 27