ur wrong
vertex is (2, -7)
The only cube that has no red paint is the one in the middle of the cube.
Since there are 27 cubes, (3 * 3 * 3), 27 - 1 = 26 cubes that have red paint.
The question is just asking how many ways to order the kids.
3! = 6
There are 6 ways.
Only ONE will NOT have a red face ...the one in the dead middle so 26 WILL have a red face
2 out of (3+2) are boys 2 out of 5 is 2/5 = 40 % are boys
The x coordinate of this dome shaped parabola's vertex will be given by x = - b/2a where b = 8 and a = - 2
x = 2
use this value in the equation to calculate the y coordinate as - 7
Notice that (x+y+z)2=x2+y2+z2+2xy+2yz+2zx. You could multiply the second equation by 2 and then add the equations up:
x2+y2+z2+2xy+2yz+2zx=9+6⋅2(x+y+z)2=21
Take the square root of both sides and you will arrive at the answer.
(notice that the negative square root is extraneous since x, y, and z are all nonnegative)
When you plug in x = -2, you get -39, so the vertex is (-2,-39).
There is only one 00 year between the dates given : 2000
2000 / 900 = 2 remainder 200 so the answer is ONE
Here is a Venn Diagram of the description: the students who took none will be: n - (sum of all numbers) (where n= 100)
Since f(x) is of a lesser degree than 8, it must be that g(x) is of degree 8
"You have linear functions p(x) and q(x). You know p(2) = 3, and p(q(x)) = 4x + 18 for all x. Find q(1). "
"kx^2 - 70x + 2k = 0
Find the maximum integral value of k for which the above quadratic equation has two distinct real roots."
First find the value of k that gives exactly one root, then take the nearest integer saller than that.
To find the value of k that gives exactly one root, set the discriminant to zero. In this case that is:
70^2 - 4*k*2*k = 0
I'll leave you to solve for k etc.
"integral of sin2x√(1-cosx) dx"
P, Q, R & S form the vertices of a quadrilateral. ∠PQR = 74° and ∠RSP = 121°. Find the value of ∠SPQ.
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Trapezoid is a quadrilateral!!!
If ∠PQR = 74° then ∠SPQ = 180 - 74
In the diagram, U = 30 degrees, arc XY is 170 degrees, and arc VW is 112 degrees. Find arc WY, in degrees.
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arc VX + arc WY = 360 - (170 + 112) = 78
30 = 1/2 [(78 - VX) - VX] arc VX = 9º
Arc WY = 69º
I'll be sure to keep an eye on this thread. Looking for the same issue. Bumped into your thread. Thanks for creating it. Looking forward for solution.
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In triangle ABC, angle B = 90 degrees and angle C = 30 degrees. Point D is on line segment BC such that angle ADB = 45 degrees, and DC=10. What is AB?
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∠B = 90º ∠C = 30º ∠ADB = 45º DC = 10
Let E be the point on BC so that DE ⊥ BC.
DE = 10(sin30)
EC = sqrt(102 - 52)
Angle DBE = 15º
BE = DE / tan15º
AB / BC = DE / EC
AB = 15.77350269
By Lagrange Interpolation Formula, p(7) = 49.
1356 leaves a remainder of 6 when divided by 27 (you can check using long division.
The problem reduces to: 3n≡6(mod 27). In other words, what is the smallest number that when multiplied by 3 is equal to 6?
DC = 10
BD = x
By 45 45 90 triangle side ratios, AB = x too.
By 30 60 90 triangle side ratios, BC/AB = sqrt(3).
(x+10)/x = sqrt(3)
x + 10 = xsqrt(3)
10 = x(sqrt(3) - 1)
10/(sqrt(3) - 1) = x
(10sqrt(3) + 10)/2 = x
5sqrt(3) + 5 = x
=^._.^=
Similar:
https://web2.0calc.com/questions/can-someone-help_19