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Average speed = total distance / total time          total distance = 4

50 m/hr     =     4 m /  ( 2 m / 30 m/hr   +  2 m/ x m/hr)

4 / 50 - 2/30 = 2/x

x = 150 m/hr    for the final 2 miles <=====Pretty fast!          See what you find for the next two !

Once you have the equations for two lines, the point of intersection (a,b) satisfies both equations ....so if you equate the line equations

   you can solve for the point x, which is 'a'

2x-10 = -4x+36  

6x = 46

x = 46/6    = 'a'      now use this value in one of the equations to calculate y (which is the 'b' value) .....then add them together to answer your Q

Hello? Mr.Electric Pavlov

the last part of it

Probably so....which part?

Remember    tan = sin/cos

2 sin = 5 cos

sin / cos = 5/2  = tan A 

it is still confusing to me

First, you will have to find the equation of the line between the two given points...  slope, m = rise/run = 8/-2 = -4

line equation is then y = -4x +36

Now equate the two line equations

2x-10 = -4x+36      now solve this  for the 'x' coordinate  which is 'a'   

                                   use this value in either of the line equations to calculate the 'y' coordinate....which is 'b' 

p = 2q

q=2r   so    p=4r

p+r = 5   so  4r+r=5  so   5r=5  so      r=1

so

q=2

p=4

It covers 110 out of 360 degrees of the ENTIRE circumference

circumference = pi * d = 2 pi * r = 10 pi

110 / 360  * 10 pi =110/36 pi  = 9.599 ~~ 9.6 cm

That is assuming I kept the ones I took from you . 

But I didn't keep them.  I gave them to the needy of Sherwood Forest because I am Robin Hood..  

In disguise, obviously.

If I take away 15 from you..... I have 15  PLUS whatever amount I had before I robbed YOU!

There are only two possible areas for the intersection of all 4 circles. ( assuming that is what the question means.)

0 or pi  units squared.

Maybe this is not what the question means.  What is the area between the 4 circles????  Really I do not know what area is being referred to.

Find positive integers a,b and c such that
\(\dfrac{3}{11} = \frac {1} {a+ \frac1{b+ \frac1c}} \).

\(\begin{array}{|r|rcl|rcl|} \hline \dfrac{3}{11} = \frac {1} {a+ \frac1{b+ \frac1c}} &\dfrac{11}{3} &=& a+ \frac1{b+ \frac1c} \\\\ &{\color{red}3}+\dfrac{2}{3} &=& {\color{red}a}+ \frac1{b+ \frac1c}~\Rightarrow \mathbf{a=3} \\\\ &\dfrac{2}{3} &=& \frac1{b+ \frac1c} &\dfrac{3}{2} &=& b+ \frac1c \\\\ &&&&{\color{red}1}+\dfrac{1}{2} &=& {\color{red}b}+ \frac1c ~\Rightarrow \mathbf{b=1} \\\\ &&&&\dfrac{1}{2} &=& \dfrac1c \\\\ &&&& \mathbf{2} &=& \mathbf{c} \\ \hline \end{array}\)

\(\dfrac{3}{11} = \frac {1} {3+ \frac1{1+ \frac12}}.\)

Well, I do not know how many I have but you have 85.

I guess I have as many as I started out with.

https://www.youtube.com/watch?v=UcYbFN49uGc

I did 100 - 85 = 15 durians, but when I entered that it didn't work :/ so can someone explain why?

(55 / 18)  pi hope that helps!

That's wrong. Please someone give me the correct answer.

(p,q,r) = (24/5, 12/5, 6/5).  Hope this helps!

The area of the graph is 3/2.

The minimum is 11200/7, so the answer is 11207.

**** edit ****   typo.....answer does not change

n = 6      day 6          day1=  6   ,  12 ,   24 ,   48 ,  96  ,   day 6 = 192

Triangle ABC has circumcenter O. If AB = 10 and [OAB] = 50 find the circumradius of triangle ABC.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Let ΔABC be an isosceles triangle with base AB = 10.

Let the midpoint of AB be M

 OM = (2 * 50) / 10 = 10

Circumradius    R = sqrt(OM² + AM²)

R = √125

Answer: \(17.56\)

Solution:

I believe that this is just the subtraction of 38.48 from 56.04. 

\(56.04-38.48=17.56\)