Find the perimeter of a trapezoid with vertices located at L(1,4), M(-2,0), N(7,0), and Q(3,4).
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\(P=\sqrt{y_L^2+(x_L-x_M)^2}+x_Q-x_L\\ \ +\sqrt{y_Q^2+(x_N-x_Q)^2}+x_N-x_M\\\)
\(P=\sqrt{4^2+(1-(-2))^2}+3-1\\ \ +\sqrt{4^2+(7-3)^2}+7-(-2)\\\)
\(P=5+2+\sqrt{32}+9=\color{blue}21.65685\)
The perimeter of the trapezoid is 21.66.
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