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Did Anne give 1/2 of her original money to Bernard or 1/2 of the remaining money?

Answer: Skid's salary is 2120.

Solution:

Let s be Skid's salary. Let p be Pump's salary.

s/4 = p/5 + 250

s/2 = 3p/10 + 640

5s = 3p + 6400

5s = 4p + 5000

p = 1400

s = 2120

Answer: He payed $2.50 for one apple pie.

Solution:

The second line elimates the need for curry puffs. I can just right 1/2 apple pie instead. Or, in the case of the first line, 3 curry puffs.

Let m be the original amount of money. Let a be the number of apple pies.

m/3 = 16a

m = 48a

1/6 of the money he kept.

48 * 5/6 = 40

3 of the pies were actually curry puffs.

40 - 3 = 37

92.5 / 37 = 2.50

Answer: A, C and D

Solution:

We have 1 side (PS) and one angle pair (QPS and SPR).

A) works because it would grant SAS

B) doesn't work because SSA is not a valid congruency theorem

C) works because it would grant AAS

D) works because it would grant ASA

Am I going insane or did you already post this?

ADB is congruent to CDB (SSS)

x = 30 degrees

Really is the same as the other one you posted.....

Answer: Kevin sold 63 books.

Solution:

Let J be the number of books Jacob sold. Let K be the number of books Kevin sold. Let M be the number of books Miguel sold. 

J + K + M = 328

M = J + 55

J = K + 42

Substition:

J + K + J + 55 = 328

3K + 139 = 328

3K = 189

K = 63

Answer: Dornetic sold 47 candy bars.

Solution:

Let A be the number of candy bars Antrope sold. Let D be the number of candy bars Dornetic. Let G be the number of candy bars Glaivieur has sold.

A + D + G = 237

G = A  + 30

A = D + 33

Substition:

D + 33 + D + A + 30 = 237

3D + 96 = 237

3D = 141

D = 47

ive solved it already, just realized what i needed to, thank you for anyone who was planning on answering though :)

ive solved it already, just realized what i needed to, thank you for anyone who was planning on answering though :)

If he spent 1/2 of the remainder on a calculator then he still has $18. The entire remainder would then be 36 dollars. Because he spent 1/4 of his money, the remainder is 3/4 of his original money. 4/3 x 36 = 48, so he originally had 48 dollars. Because he kept 18 dollars, he spent 30 dollars. As for a bar graph.... a bar graph of what exactly? 

THIS IS AN ENGLISH QUESTION MY BRAIN IS MELTING BY LOOKING AT IT

10 years later...

Answer: Wesley bought 108 blue pens and Joshua bought 24 black pens.

Solution:

Distribution of the pens after using some of them:

Wesley: Half the blue pens, half the black pens - 3

Joshua: Half the blue pens - 6, half the black pens

Let x be half the number of blue pens. Let y be half the number of black pens (they both got half):

x = 6(y - 3)

x - 6 = 4y

I'll use substitution to solve this:

6(y - 3) - 6 = 4y

6y - 18 - 6 = 4y

2y = 24

y = 12

Putting that back into one of the equations and solving it gives x = 54.

BUT I used the half number as my variables, so I'll double the numbers at this point to get (x, y) = (108, 24) or in the question terms, Wesley bought 108 blue pens and Joshua bought 24 black pens.

n ==6  

6 x 6==36

36 = (1, 2, 3, 4, 6, 9, 12, 18, 36) > 9 (divisors)

Prime divisors of 6n ==2  and  3

F

A

N

N

Y

It's F***y

Answer: F***y (is that just me or does it look like that for everyone?) had 130 at first. 

Solution:

Let F be the amount of money F***y (I can't begin to imagine what goes there) has. Let G be the number of money Grace has.

F + G = 306

4/5 * F = G - 72

I'll solve this system using substitution.

G = 306 - F

4/5 * F = 306 - F - 72

4/5 * F = 234 - F

9/5 * F = 234

F = 130

a) 2/5 + 3/10 = 4/10 + 3/10 = 7/10

b) Derek drank 1/2 of his juice.

1/2 = 5/10

7/10 - 5/10 = 2/10 = 1/5

Answer: 415 cents

Solution:

9 x 5 = 45

5 x 10 = 50

7 x 10 = 70

10 x 25 = 250

250+50+70+45 = 415

You need to work out a logical system

id say  1+1+1+1+5     that is the only one with 4 ones

then     1+1+1+(two that sum to 6 but neither can be 1)

then    1+1+(three that sum to 7 but not including an more ones)

etc

when you exhaust all the possible combinations that inclu....

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thinking about it is is preobably easier to go from the big end.

The biggest number you can have is 5  (there is only the one possible way)

Now look at all possibilities that include fours.

You just need to find a logical system to list them all so that none will get forgotten or duplicated.

No not all.

x = Tom’s money originally

4x = Jack’s money originally

4x + 240 = Kenny’s money originally

x + 80 = Tom’s money now

4x + 300 = Jack’s money now

4x + 240 - 300 - 80 = Kenny’s money now

Jack has twice as much money as Kenny now can be expressed by the equation

4x + 300 = 2 (4x + 240 - 300 - 80)

4x + 300 = 2 (4x - 140)

4x + 300 = 8x - 280

4x = 8x - 580

-4x = -580

x = 145

Tom’s money now is x + 80 = 145 + 80 = 225.

Sorry.   I answered this yesterday but it had been autoblocked and  I did not realize.

Actually, looking again, I do not know.

Certainly all of them can be true whether or not they need to be true is a different matter.

I am withdrawing my earlier assertion that one can be easily removed as the answer. I misread it.

Thinking about it now one at a time.

I think all of them have to be true.   

Do you mean D is the only one that is right or the only one that can easily be dismissed?

All of them?