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  (-3z^2 - 7z + 4)(6z^2 + 6z - 1).

-7z * -1      +    6z * 4    = ..............

Find the surface ara of a cylinder with a height of 8 inches and bsae diameter of 6 inches.    

Are the ends of this cylinder open (like a drinking straw), or are the ends closed (like a can of vegetables)?  If closed, are the ends flat or hemispherical or what?  

Dont post wrong answers... The correct answer is 15.

hmm, then only A and B

got it! thank you!

1 x³  +   o x³    = 1 x³

fraction = 4/5

The only statements that must be true are A and C.

x = total straws

Al = 1/2 x + 8          leaving   1/2 x - 8

Je =   1/2 ( 1/2x-8) + 8 = 1/4x +4       leaving   1/4 x - 12

La = 1/2 ( 1/4x -12 )  + 9                    summed = x

1/2 x + 8   + 1/4x + 4     + 1/8 x +3   = x

7/8x + 15 = x

x = 120 

Al =  68       leaving 52

Je = 34        leaving  18 

La = 18                                       18 out of 120 = 15 % of the total

m/30 > 1/3

m > 10

m/30 < 3/4

m < 22.5

11    12   13  14  15  16  17  18  19  20  21   22     <====== count them

1+2+3 = 6 parts

180/6 = 30 degrees per part

1 *30

2 * 30

3 * 30 = ........    degrees

Is it 5% per year constantly beginning at 40?   Or is it 5% of the hair they have at the end of each year?

For the former:    (x-40)* .05 =  % hair loss

b) (x-40)(.05)  = .50    

c) (x-40)(.05) = 1.00       solve for 'x'

Try proofreading your question !

I set up a long multiplication.   281 * boxH  boxT  boxU = 31743  (where one digit is wrong.)

I assumed for the moment that the units digit really is 3

3*281=843

four is already in the tens column. So this would mean that BoxT would have to be 0

going a little further I found that this could not work.

So that means that either the units digit or the 10s digit was incorrect.

31700 divided by 281 = 112 and a bit    112 is to small, so I will just try some numbers that are a bit bigger.

113*281=31753

bingo, there is the answer.

The 4 needs to be a 5.

It would be a good idea for you to put your answer so other people can see if their answer agreed  (if they want to I mean)

It is good that you solved it for yourself though  :))

Find the area of triangle ACE.

Hello Guest!

\(A=\int_{0}^{17} \! f(x) \, dx+\int_{17}^{30} \! g(x) \, dx-\int_{0}^{30} \! h(x) \, dx\)

\(m_f=-\frac{4}{17}\\ f(x)=m(x-x_1)+y_1\\ f(x)=-\frac{4}{17}(x-0)+17\\ \color{blue}f(x)= -\frac{4}{17}x+17 \\ m_g=-1\)

\(g(x)=-1(x-17)+13\\ \color{blue}g(x)=-x+30\\ m_h=-\frac{17}{30}\\ h(x)=-\frac{17}{30}(x-0)+17\\ \color{blue}h(x)=-\frac{17}{30}x+17\)

\({ \color{blue}A_f}=\int_{0}^{17} \! ( -\frac{4}{17}x+17) \, dx=\ _0^{17}| -\frac{4}{2\cdot 17}x^2+17x|\color{blue}=255\)

\({\color{blue}A_g}=\int_{17}^{30} \! (-x+30) \, dx=\ _{17}^{30}|-\frac{x^2}{2}+30x|=450-365.5\color{blue}=84.5\)

\({\color{blue}A_h}=\int_{0}^{30} \! (-\frac{17}{30}x+17) \, dx =\ _0^{30}|-\frac{17x^2}{2\cdot 30}+17x| \color{blue}=255\)

\(A=A_f+A_g+A_h=255+84.5-255\)

\(A=84.5\)

The area of triangle ACE.is 84.5 

  !

See https://web2.0calc.com/questions/help-me-to-solve-this-problem_1#r2 

Like so:

Hi TitaniumRome,

It is really good to see you here.  And lovely of you to think about Rosala's birthday. 

I also thought of it but it has been such a long time since she made an appearance....

You are obviously looking on from the sidelines. Why don't you make yourself visible more often than just once a year!

I'd really like that.  I miss all the old crowd.  (no offence to the new people intended)

Anyway, I'm really pleased that you have dropped in and I hope you are doing well.

Also a very big happy birthday to Rosala and I hope life is being kind to you also.   It would be nice to see you here too  

The ratio of the number of cars to the number of vans to the number of

motorbikes at a car park is 5:2:3. Each car and each van had 4 wheels. Each motorbike has 2 wheels.

a)       If there is a total of 816 wheels, find the number of vans at the car park.

b)       If the cars had a total of 224 more wheels than the motorbikes, find the number of cars.

C:V:M = 5:2:3

5x + 2x + 1/2(3x) = 816

x = 96

a/    There are 48 vans

b/    92 cars 

\(\text{Find the invers of }f(x)=x*|x|\)

If x>=0  then  f(x)=x^2  which is a very simple  half concave up parabola in the first quadrant

if X < 0  then  f(x)=-x^2  which is a very simple  half concave down parabola in the third quadrant

To be honest, the first thing I did was sketch this. The inverse is the refection in the line y=x so I can already see where this is going.

But lets look at the algebra

let   y= f(x)  )it is just easier to work with)

If x >=0     then y is also positive

y=x^2

x=+sqrt(y)

so

f^-1(x)=+sqrt(x)

If  x<0   then y is also negative

x=-sqrt(x)

so

f^-1(x)=-sqrt(|x|)

The tricky bit was how to put these together into one function   

|x| / x = 1    if x>0        and    |x| / x = -1    if x<0     so

\(f^{-1}(x)=\frac{|x|*\sqrt{|x|}}{x}\)  

check:

How many stickers did he give away altogether?

Hello Guest!

Mathew owns x.

\(\frac{x}{4}+2\cdot\frac{x-\frac{x}{4}}{2}+24=102\\ \frac{x}{4}+x-\frac{x}{4}+24=102\\x=78\)

78/4=19.5   (78-19.5)/2=29.25

Matthew gave \(19\frac{1}{2}\) stickers to May and \(29\frac{1}{4}\) an Lily.

This is strange, I have to check:

\(x-(\frac{x}{4}+\frac{{x-\frac{x}{4}}}{2})+24=102\)

\(\frac{4x-x-2x+\frac{x}{2}}{4}=102-24\\ 1.5x=312\\ x=208 \)

208/4=52    (208-52)/2=78

Matthew gave 52 stickers to May and 78 an Lily.

  !

Adding up all the coins gives a total of 23 dollars.

He spent 23 dollars.

23 - 14.35 = 8.65

He spent 8.65 dollars on lunch that day.

*Sorry for the brief answer, I'm getting tired

Well, that makes sense.