Straightforward. First, assign variables to the unknown values:
Let H = Henry’s money
Let B = Badminton Racket
Let W = Watch
We are given:
B = 3/8 H
W = 1/8 H
B = W + $14
So:
Substitute B and W:
3/8 H = 1/8 H + $14 [Cost of Badminton racket = $14 more than cost of watch]
Solving:
3/8 H - 1/8 H = $14
(3/8–1/8) H = $14
2/8 H = $14
1/4 H= $14
H = 4 * $14 = $56 [Henry’s total money]
B = 3/8 * $56 = $21 [Cost of badminton racket]
W = 1/8 *$56 = $7 [Cost of watch]
Check:
B = W + $14
$21 =? $7 + $14
Yes!
Henry spent B+W on his items altogether, which is $21+$7 = $28.
Another way of expressing it is:
2/8 H = $14
1/8 H = $7
B+W = 3/8 H + 1/8 H = (3+1)/8 H = 4/8 H = 1/2 H.
H = $56
B+W = 1/2 H = $28