$${\mathtt{\,-\,}}{\frac{{\mathtt{7}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{6}}}{{\mathtt{7}}}}\right){\mathtt{\,-\,}}{\mathtt{3}}$$

First you distribute the -7/2.

$${\mathtt{\,-\,}}\left({\frac{{\mathtt{7}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}\left({\mathtt{2}}\right)\right) = -{\mathtt{7}}$$

$${\mathtt{\,-\,}}\left({\frac{{\mathtt{7}}}{{\mathtt{2}}}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{6}}}{{\mathtt{7}}}}\right)\right) = -{\mathtt{3}}$$

This makes the equation into something a bit more legible.

$$\left({\mathtt{\,-\,}}{\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{3}}\right){\mathtt{\,-\,}}{\mathtt{3}}$$

Then you just subtract 3.

$$\left({\mathtt{\,-\,}}{\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{3}}{\mathtt{\,-\,}}{\mathtt{3}}\right)$$

$$\left({\mathtt{\,-\,}}{\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{6}}\right)$$

At this point you can drop the parentheses and you have your most simplified answer: -7x - 6

5x + 7 = 42

The goal here is to isolate the 'x'. First, subtract 7 from both sides.

5x + 7 - 7 = 42 - 7

5x = 35

Divide by 5

5x/5 = 35/5

x = 7

The answer is 7.

$$(45.22-73.91)-|65.85-79.15|$$

$$(-28.69)-|-13.3|$$

$$-28.69 - 13.3$$ Negative is dropped from the -13.3 since it was in the absolute value bar.

$$= -41.99$$ This is your final answer

Thanks, rosala......the "Domino's Pizza" one had me laughing for 5 minutes....I'm posting that one on my Facebook page  !!!!

Your humorous posts are THE BEST !!!!

I don't think this is even possible because there is no equal sign

$${\mathtt{y}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}} = {\mathtt{2}}{\mathtt{\,\times\,}}\left({\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{1}}\right)$$

$${\mathtt{y}}{\mathtt{\,\small\textbf+\,}}{\mathtt{3}} = {\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{2}}$$

$${\mathtt{y}} = {\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,-\,}}{\mathtt{3}}$$

$${\mathtt{y}} = {\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{5}}$$

If x = 20

then y = 2 * 20 - 5 = 35

2=2x/5

as you might know the denominator * "the answer equals the numerator.

2*5=10

x=10/2

x=5

It's the answer you get when dividing.

For example. 6/3=2. 2 is the quotient

I assume you mean quotient?

A quotient is the number you get when you divide one number by another. It's sort of the "answer" you get when you divide two numbers:

4/2 = 2;        2 is the quotient

1/4 = 0,25;   0,25 is the quotient

1/11 = 0,090909090....        0,0909090909... is the quotient

The first thing you have to do is to factorize the number 126 (numerator) and 105 (denominator)

Let's start with the numerator:

The last digit in 126 is an even number. Therefor the whole number is divisible with 2:

126/2 = 63 The digit sum of 63 is 9, which is divisible with 3, therefor the whole number is divisible with 3:

63/3 = 21 The digit sum of 21 is 3, which is divisible with 3, therefor the whole number is divisible with 3:

21/3 = 7 This number is a prime number (no divisors other than 1 and itself)

To sum it up: 126 = 2*3*3*7

Now, lets factorize the denominator:

Since the last digit in 105 ends with a zero or a 5, we know that the whole number is divisible with 5:

105/5 = 21 The digit sum of 21 is 3, which is devidable with 3, therefor the whole number is divisible with 3:

21/3 = 7 This number is a prime number (no divisors other than 1 and itself)

We conclude that 105 = 3*5*7

Now that we have factorized both the nomerator and the denominator, we can restate the fraction:

126/105 = (2*3*3*7)/(3*5*7) 

Look for factors that occur in both the nomerator (top) and denominator (bottom). Did you find any?

Yup, 3 and 7!

We devide the numerator and the denominator by 3*7 and get:

(2*3)/5 = 6/5

Melody i wish i lived near you!becoz i would so happy to have a " Math EXPERT" tutoring me!

and anonymous, if u really want a tutor, search on the net telling your location and im sure you'll find some tutors!and on the net you may find the famous " Web2.0calc" tutor!lol!

Thx for your answer!

What I meant with "repunit" is a number where alle the digits are 1, such as 11, 1111 and 111111111111.

-3x + 5 = 8 - 4(x-3)

First get the paranthesis away; be VERY careful when you see double negatives like these: a minus sign outside the paranthesis and a minus sign inside the paranthesis. Rembember that -(-x) = x

-4(x-3)= -[ 4(x-3) ] = -(4x-12) = -4x +12

So the solution for the whole equation is:

-3x + 5 = 8 - 4(x-3)

-3x +5 = 8 -4x + 12          Solve the paranthesis as shown above

-3x + 4x = 8 +12 -5          Get all the X'es on the left, and all the numbers on the right

x = 15                               add (+) and subtract (-) the unknowns and the numbers

If you live near me ill tutor you. Otherwise we'll all help you out for free on the forum.

7x + 8 = 9x + 5  subtract 7x from both sides   and subtract 5 from both sides

3 = 2x      divide both sides by 2

3/2 = x

Check

7(3/2) + 8 = 9(3/2) + 5

21/2 + 8 = 27/2 + 5

8-5 = 27/2 - 21/2

8-5 = 6/2

3 = 3

Nice one, geno !!!

Product means times and decreased means subtract:

-5 · x - 11 = 15

-5x - 11 = 15              To remove - 11 and 11 to both sides.

-5x - 11 + 11 = 15 + 11

-5x = 26                     To remove -5 which is multiplied to x, divide by -5

-5x/-5 = 26/-5

x = -5.2

-5x-11=15

-5x=15+11

-5x=26

x=-26/5

x=-5  1/5

Since you have x^12, take the 12th root of each side:

(x^12) ^ (1/12) = (2^18) ^ (1/12)

When you have an exponent to an exponent (a power to a power), multiply them:

     12 * 1/12 = 1         and          18 * 1/12 = 18/12 = 3/2 = 1 + 1/2

So, you get: x^1 = 2^(3/2)     which is x = 2^(3/2) = 2√2.

How to reduce: 2^(3/2):

2^(3/2) = 2^(1 + 1/2)

To multiply numbers with the same base, you add their exponents; also, if you have a problem with exponents are added, the problem can be split into two numbers that are added.

So, 2^(1 + 1/2) = (2^1) · (2 ^ (1/2) )

2^1 = 2         and         2 ^ (1/2) = √2

The final answer is x = 2√2.

-1(-7-3x) + 2(-12x+3)

7+3x + (-24x)+6

-24x+3x +7+6

-21x+13

-(-7-3x)+2(-12x+3)

7+3x+2(-12x+3)

7+3x-24x+6

-21x+13

Thank you that make sense now. I apreciate that. :)

To reduce a square root, determine if a perfect square (not 1) divides into the number.

Since 4 divides into 8 and since √(4) = 2 :

√(8) = √(4·2) = √(4)·√(2) = 2√(2)