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F = G m1m2/r^2

   m1 = m2 = .8kg    

   r = .25 m

   G = gravitational constant = 6.67408 x 10^-11   m³ kg^-1 s^-2  

                       Plug in the numbers and calculate the force in Newtons

If the baseball "just fits" in the box and the diameter of the baseball is 3 inches,

both the width and the height of each side is 3 inches.

This makes the area of each side  3 x 3  =  9 square inches.

Since there are six sides, the total area is  6 x 9  =  54 square inches.

The only faces with 2 red faces are the edge pieces. There are \(\color{brown}\boxed{12}\) of them, just like Guest found. 

Twelve   have two faces painted

6  have one face painted

8 have three faces painted

(2 *40  +   33   )  * 1.065    +   7.85        = total charge       

                  ( assuming the two shirst cost $ 33    and NOT $ 33 EACH)

The quadratic formula is :

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)               b^2 - 4ac is the discriminant 

IF discriminant = 0       =====>  only one root (double root)

 IF discriminat < 0               only imaginary roots

   IF discriminat > 0           two roots

This is ALMOST the equation of a circle.... if + 73 was smaller or it was -73   it WOULD be a circle...

   as it is, there are no lattice points in the equation.

The following gives a possible solution, subject to some assumptions:

Thanks Hectictar,

I really like that \phantom one !  

And the \hspace{3cm}b  looks like it would be really useful.

It is good to have seome more commands that actually do work here  

I will add an a link to this thread, to the Latex thread that is found in the sticky notes.

60 hours   =   48 hours  +  12 hours

Total pay for the week   =   $17.25 * 48   +   1.5 * $17.25 * 12   =   $1138.50

It looks like just making a box with the \hspace command makes a narrower box like this:

\(\boxed{\hspace{10cm}}\)

And I tried to use the \vspace command to make it taller but it seems like that doesn't work in math mode :\

Another code I like to use to make things invisible is  \phantom{}

It will makes whatever you put inside invisible! I sometimes use it for spacing

Also there is the  \hspace  command which can be used to make a horizontal space of a specified length.

For example, the code:  a\hspace{3cm}b

makes this:

\(a\hspace{3cm}b\)

So there are 3 cm of space between the a and the b.

While you are waiting to register, put your username at the bottom of your posts so that you can already start becoming known to other members.    

I don't know how to fix it but you can lodge a error using the flag.  

Make sure you describe the problem (as you have here) and say the country, city or area that you live in.  (don't give your address)

The owner of the site certainly can't do anything if he doesn't have all the basic information that people with problems can give him.

Hint:

SPACING AND EMPTY BOXES

How to make an empty box of various horizontal length 

\boxed{\color{white}ABCDEF  }

\(\boxed{\color{white}ABCDEF  }\)

There are more spacing ideas from Hectictar here

When you see a number folllowed by a letter, without anything inbetween, there is really an invisable times sign between them.

so

8x  means  8 * x

The x is used instead of a box.

so you can think of 

 \(8*x=8*\boxed{\color{white}af}=-32\\ 8*\boxed{\color{white}df}=-32 \)

So what times by 8 = -32 ?        The answer will be what x equals

--------------------

Hope this helped! :)

Hello Fellow Guest! The answer to this problem is rather simple. First we can do 20-14(The reasonining for this is that we already know how many people are taking both courses and the rest of the 8 players taking only biology. Secondly solving this we get 6 so the answer to your problem is 6! 6 players are taking chemistry :) 

There are 8 different combinations possible.

Actually

\(\mathbf{P} = \begin{pmatrix} 2 & -1 \\ 3 & 1 \end{pmatrix}\)