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okay    

Australia is really hot, so the more the sun rotates the hotter.

LOL

How does the sun rotate 10 times in a day?  I suppose it could rotate on its own axis.

That would be really fast!

I cannot find a question in there???

Two sides of a parallelogram are 30 and 20.  One diagonal has a length of 40. What is the length of the other diagonal?

Use the cosine rule to find cos(theta)   then get back to me.      [ note:I want cos(theta), not  theta ]

If you have cos(theta), what is the value of cos(180-(theta)) ?\(\)

f(2)  =  5

f²(2)  = f(5)  =  8

f³(2)  =  f(8)  =  11

f⁴(2)  =  f(11)  =  14

f⁵(2)  =  f(14)  =  42

f⁶(2)  =  f(42)  =  2

f⁷(2)  =  5

Try to reduce the maximum nuber of 9" sides

Who is the mother of the daughter of the mother of Lia´s daughter?   

Work backwards.  

The mother of Lia's daughter   =  Lia  

The daughter of Lia                 =  daughter   (If Lia has two daughters, the next step still works.) 

The mother of the daughter     =  Lia  

_.

See answer #2 here:  https://web2.0calc.com/questions/the-powers-of-coffee-in-mathematicians

I will DM the admin for ya....

Volume of a sphere = 4/3 pi r^3

                                = 4/3  *  pi  *  (3.5)³    in³

p * n <= 24

n <= 24/p

Lia.

Solve:  3·_nC₄  =  5·_n-1C₅  

--->     3 · n! / [ 4! · (n - 4)! ]  =  5 · (n - 1)! / [ 5! · ( (n - 1) - 5 )! ]

--->     3 · n! / [ 4! · (n - 4)! ]  =  5 · (n - 1)! / [ 5! · ( n - 6 )! ]

--->     Divide both sides by (n - 1)!:

           3 · n / [ 4! · (n - 4)! ]  =  5 · 1 / [ 5! · ( n - 6 )! ]

--->     On the right side, cancel the 5 into 5!:              [ 5 / 5!  =  1 / 4! ]

           3 · n / [ 4! · (n - 4)! ]  =  1 / [ 4! · ( n - 6 )! ]

--->     Multiply both sides by 4!:

           3 · n / (n - 4)!  =  1 / ( n - 6 )!

--->     Multiply both sides by (n - 6)!:

           3 · n / [ (n - 4) · (n - 5) ]  =  1 

--->     3 · n  =  (n - 4) · (n - 5)

--->        3n  =  n² - 9n + 20

--->          0  =  n² - 12n + 20

--->          0  =  (n - 10)(n - 2)

--->     Either  n = 10  or  n = 2  [2 is imposible]

if you're talking about gas milage then it depends on a lot of things. the type of car, whether you're on the highway or driving through the city. as an example I will use a car that gets 20 mpg on the highway. that's 150 / 20 which is 7.5 so you'd need 7.5 gallons to travel 150 miles on the highway driving a car that gets 20 mpg.

We aren't here to do your work for you. 

This is standard form: \(ax^2 + bx + c = 0 \) In the quadratic formula: \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\) and \(b^2-4ac\) is the discriminant. If it is positive, there are 2 real solutions. If it is 0, there is 1 real solution. If it is negative, there are 2 imaginary solutions. 

https://www.desmos.com/calculator/xaxoqyxzyn

You will need to know   m / gal    (mpg)    ....    then  150 / (mpg) = gallons needed

hi  hlep me with math

gallons of what?

YOU need to work out the ' full answers '

I'll do example one....you do the rest

a = 7    b = - 9    c = 0

 discriminant    b^2 - 4ac =        

                       (-9)^2 - 4 (7)(0) =   81     this is > 0    there will be two solutions

Now , if you cannot do the others, you are in a math class which is above your level of understanding/knowlwedge and you need some remedial work ...or studying of your class materials. 

   We are not her to "GIVE" you ANSWERS for the most part....just here to HELP YOU learn the math methods to do it yourself .   ~EP

11 c 3  = 165 ways             =   11 ! / ( 8! 3 ! )

Factors of 60       1  2    3   4    5   6  10  12   15   20  30  60         11 out of 12 are less than 35