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Here's a very similar problem :

https://web2.0calc.com/questions/counting-problem_27

Recall the geometric sequence formula for the nth term: \(a_n = a_1(r)^{n-1}\)

\(a_1 = 9\)

r = 1/6

n = 10

\(a_{10} = 9({1 \over 6})^9\)\(= {9 \over 6 ^ 9}\)\(= {1 \over 2^2 \cdot 6^7}\)

If you need a decimal form I believe that the calculator on this website should be able to provide you with that.

The first term is 3/2⁰.

The second one is 3/2¹.

The third is 3/2².

The pattern continues, because it is a geometric sequence. The eighth term would be 

3/2⁷ = \(3 \over 128\)

these are just numbers in binary. (base 2)

\(7=4+3+1 = 1*2^2+1*2^1+1 = 211\\ 17=16+1 = 1*2^4+0*2^3+0*2^2+1 = 1001\)

Now I have given you 2 examples you and work out what 12 is in base 2

ohh tysmm

do you have man idea on how to do the second one??

This list satisfies your condition:

       n

1 = 6
2 = 7
3 = 8
4 = 9
5 = 14
6 = 15
7 = 16
8 = 17
9 = 22
10 = 23
11 = 24
12 = 25
13 = 30
14 = 31
15 = 32
16 = 33
17 = 38
18 = 39
19 = 40
20 = 41
21 = 46
22 = 47
23 = 48
24 = 49
25 = 54
26 = 55
27 = 56
28 = 57
29 = 62
30 = 63
31 = 64
32 = 65
33 = 70
34 = 71
35 = 72
36 = 73
37 = 78
38 = 79
39 = 80
 

I did a Repost so there wouldn't be any confuion: Um, okay,  i'll check that out then i still got the same answer, and fyi i didn't copy sooooo....yea 

Also I saw that latest post in here overall and whoever wrote that "WHAT?!" thread is right, it can come across as mean sometimes, but i didn't take it the wrong way just fyi but still someone else could have.

Um, okay,  i'll check that out then i still got the same answer, and fyi i didn't copy sooooo....yea

it's not called copying really, especially if they got the help, And slow down, i never said you were wrong, but just so you wont upset anyone on here just write your way of doing it. because you just never know, you may be wrong sometimes, and you just dont want to just say someone is wrong, they may very well be wrong, but you also need to be careful because no one really knows anyone here and someone can take that very hard or get offended. And i'm just speaking out as an adult and perspective. instead of saying what u said you could have said, "are you sure your d is correct maybe you should double check" or something. 

Recall that \(\sin = {\text{opposite} \over \text{hypotenuse}}\)

Because we applying sin to A, we have \(CB \over AB\).

Can you take it from here?

Also, that isn't a triangle, because \(9^2 + 6^2 ≠ 15^2\). The rule for the triangle side length does not hold true here either, because \(9+6\) is not greater than 15. 

You have not asked a question.  

This function BELONGS to some question, which you have not asked,

The values that lead to non-real solutions are 9 and 10, so the probability is 2/10 = 1/5.

The sum of the exterior angles  = 360

Let  the other two  exterior angles  be equal    and  each measures  (360 - 72) / 2 = 144

So  the  angle  supplemental to one of these is  the  angle we are looking for =  180 - 144  = 36°

You should be able to figure this from  my other answer.....

Suface area =  6 * (edge length)^2

So

150  =  6 * edge length^2

150 / 6 = edge length ^2            take the  square root

sqrt   [ 150 / 6 ]  =   sqrt [ 25 ] =  5   = edge length

Volume =  [edge length ] ^3  =  = 5^3 =   125

And what do you intend to do with that function?

What did you get after simplifying the equation?

You did a pretty good job !!!!

I would shift  the graph to the right by pi/6    so we  get

y = -20cos (pi*x / 6  - pi/6) +  51

It  lines up a little better this way.......the  temps will not be exact for all months  because we don't have constant changes between them,  but  this  is about the  best you can  do with a periodic trig function

See the graph here with a few selected points   : https://www.desmos.com/calculator/zxwgqqtjzl

This triangle is  impossible because

9 +  6    ≠   15

We have  a 30 - 60  -90   right triangle

The side opposite the right angle is    2 /sqrt (3)   times the angle opposite the 60°  angle

So  AC  =  2 / sqrt (3) *  15 =   30/sqrt 3  =  (30/3)sqrt (3)  = 10sqrt 3

And the side oposite the 30° angle = AB   =  (1/2)*10sqrt (3)  =  5 sqrt 3

I't B

We have this property in a right triangle with an altitude drawn to  the right angle

AD / CD = CD / DB

So

4 / 6  = 6 / DB

4DB =  6*6

4DB   =36

DB   = 36 /  4  =   9