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Never mind, I got it!!!

144 * 12  = 1728 notes

1728 notes  / 560 (notes/min)   =  108/35  min

(108/35)min * 60 sec / 1 min   ≈   185 seconds

What histogram?

3m + 4n =  47     (1)

m + n =  15-2m   →  3m + n  =  15  →  n = 15 - 3m    (2)

Sub (2)  into (1)

3m + 4 (15 - 3m)  =  47

3m + 60 -  12m =  47

-9m =  47 - 60

-9m = -13

m = 13 /  9

9.   

4*6*15*17*1=6120

At what value of x  is y = -1  ???

That x value =  c

Rearrange as

x^2 + 14x - 16  = 0

Sum of roots  =  a + b =  -14

Product of roots  = ab  =  -16

(2a - 3) ( 4b - 6)  =

12ab - 12a - 12b + 18 =

12ab -12 (a + b) + 18 =

12 (-16) - 12 (-14) + 18 =

-192 + 168 + 18  =

-6

Yep...I agree, nerdiest  !!!!

This was literally posted yesterday.

https://web2.0calc.com/questions/help-please_74857#r4

Find BuilderBoi's answer. And, I think CPhill will give you one also!

OH MY GOD! DID YOU KNOW I DON'T READ JIBBERISH???!!!

Can you just upload the picture and not copy and paste the latex or whatever???

P of choosing the correct floor = ( 3/5 )

P of choosing the correct room on one of these floors = (3/10)

P ( choosing the correct floor and correct room )  =  (3/5) (3/10) =  9 / 50

could you please explain further, and what is x in x/3

f(y)  =   1/(y - 2)  + 1/(y - 8)

No denominator can =  0

So...the domain  is    (-inf , 2) u (2 , 8) U (8, inf )

Apply the sales tax to the $5, and compare the price. 

See the image below :

The length of the midsegment = (sum of bases ) / 2  =  (14 + 8)  / 2  =   11

For convenience, let the height of the trapezoid =  8    (it could be any height ....it works out the same)

Note that  DEC is similar to triangle BEA

Therefore  the height of triangle DEC =  (8/14)  =  of triangle BEA

So...the height of triangle  DEC  =  8 / (8 + 14) * (8)  =   (8/22)(8)  = 64/22 = 32/11

So  the height of triangle QEP =  4  - (32/11)  = 12/11 

And triangles DEC and QEP are similar

So  PQ =  (12/32)(8)  = 96/32  =  3

And, by symmetery , PQ = QN =  (11 - PQ) / 2  =   (11 - 3) / 2   =  8/2 =  4

Think about a week. How many days are in a week? How many hours are in each day? How many minutes are in each hour? How many seconds are in each minute?

6 on top

6 in top section

6 in bigger sections

that is 18

it is correct.   

domain  [1 , 2)

On my first try I got 16. But then I counted the triangles containing the smaller group!

The inequality is x + y - 5 > 0.

So do you still want help or not?

hint

The roots will be at       \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

the axis of symentry will be the half way point between these roots.  

What will that be, as fa as the formula is concerned ?  

Sketch it if you are confused.  

the vertex is on the axis of symmetry.  so x=-4

Try taking it from here.

Noah will have 18 dollars.

x^2  + 3x  + c - 7x + x^2   =  -2

2x^2 - 4x + c  =  -2

[2x^2 - 4x + 2] + c  =  0

The  parabola  2x^2 - 4x + 2   has its vertex at  [ 4] / [ 2*2 ] =  1

And the y value here is  0

So  c =  0

Let  the altitude of 1/3 be drawn to side A  

Let the altitude of 1/4 be drawn to side B   

Let the altitude of 1/6 be drawn to side C   

Equating areas

(1/2) (A) (1/3)  = (1/2)(B)(1/4)  →   B = (4/3)A

(1/2)(A) (1/3)  = (1/2)(C)(1/6)  →   C =  (2)A

The semi-perimeter  =  (A + (4/3)A + (2)A )  / 2  =     (13/6) A  

Using Heron's Formula

Area =  sqrt  [   (13/6)A *  [ (13/6)A - A ] * [ (13/6)A - (4/3)A ] * [ (13/6)A - 2A ]  ]  =

sqrt  [  A^4  (13/6)  (7/6) (5/6) ( 1/6)  ]   =

A^2 sqrt  [ 455 ]  /  36 

Equating areas

(1/2)A (1/3)  =  A^2  sqrt [ 455]  / 36

(1/6)A  = A^2 sqrt [ 455] / 36

(1/6)  = A sqrt [ 455 ]  / 36

6  /sqrt [ 455]  =  A

The area is   (1/2) (6 / sqrt [455])  ( 1/3)  =     1/ sqrt 455 units^2  ≈   .0468 units^2