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We can simplify the expression:

( 110.7 - 64 ) / ( 0.056 ) ( 0.00216 )

46.7 / 0.00012096

             ______

386078.042328

                           ______

Answer: 386078.042328

1. The area of a triangle is 1/2bh where b stands for base and h stands for height.

Answer: A = 1/2 x b x h

2. The area of an equilateral triangle given only the side length is √3 / 4 x a² where a is the side length.

Answer: A = √ 3 / 4 x a²

3. The area of a triangle given the length of the 3 sides is √ s ( s - a ) ( s - b ) ( s - c ) where s is the semiperimeter, which is ( a + b + c ) / 2, and a, b, and c are the 3 side lengths.

Answer: A =  √ s ( s - a ) ( s - b ) ( s - c )

There are other formulas for the area of a triangle given an angle as well.

Thx, DS2011   !!!!!

Set the y's equal and  simplify as   

 2x^2 +  9x   - c =  0

-2x^2 - 9x + c  =  0

One real solution, discriminant =  0

9^2  - 4 (-2)(c)  = 0

81  + 8c =  0

81  =  -8c

c = - 81 / 8

No real solutions,  discriminant <  0

81 + 8c < 0

81 < -8c   →  -8c > 81                (divide by -8, reverse the inequality sign)

c < -81/8

More than one real solution   c >  -81/8  

c/ sin (105)  = 7/ sin (35)

c  =  7sin (105) / sin (35)  ≈  11.8

a / sin ( 40 )  = 7/sin (35)

a  =  7 sin (40) / sin (35) ≈ 7.8 

Semi-perimeter  of triangle  = (7 + 11.8 + 7.8) /  2  = 13.3 = S

Area of triangle  sqrt [ 13.3 (13.3- 11.8)(13.3 - 7.8) (13.3 - 7) ]   ≈  26.3 =  A

Incircle radius  =     A  /  S  =   26.3 / 13.3   ≈ 1.98

Circumcircle  radius  =   abc   /  ( 4A) =   (7 * 7.8 * 11.8)  /  [4 * 26.3 ]  ≈  6.12

x - y  =   pi ( 6.12^2 - 1.98^2)   ≈  105.35  

We can find the area of triangle PQR without using any of the above information other than the side lengths of PQ, PR, and QR. Heron's Formula can help us find the area of any triangle given its 3 sides. Heron's Formula  is: A = √ s ( s - PQ ) ( s - PR ) ( s - QR ), where s is the semiperimeter, or the perimeter of the triangle divided by 2.

the semiperimeter of triangle PQR is ( PQ + PR + QR ) / 2. Plugging in the values, we get:

s = ( 36 + 22 + 20 ) / 2

s = 78/2

s = 39

Now that we know the semiperimeter, we can plug in the values, and solve for the area:

A = √ 39 ( 39 - 36 ) ( 39 - 22 ) ( 39 - 20 )

A = √ 39 ( 3 ) ( 17 ) ( 19 )

A = √ 37791

A ≈ 194.4

Answer: A = 194.4

Expand the far left side, then multiply the second term by   (3x-4)/3x-4)   and multiply the entire equation by  ( 3x-4)^2 

  and simplify the mess to get 

          80x^2- 96-128 = 0        Quadrtaic formula then shows x = 2 as the largest x 

The sides of the equilateral triangle are equal, and first we should find the side lengths. To find the side length, we can do

(s = side)

( 1/2 s )² + 12² = s²

1/4 s² + 144 = s²

144 = 3/4 s²

144 / 3/4 = s²

144 x 4/3 = s²

192 = s²

s = √ 192

We now know that s = √ 192, so we can now find the area of the equilateral triangle:

A = 1/2 x 12 x √192

A = 6 x √192

A ≈ 83.14 or 6√192

Answer: A = 83.14 units or 6√192

If you want to simplify it, then 

V = 1/3 x 252 x 42

V = 3528

Answer = 3528 units

Two Secants Segments Theorem

3 (3 + 6)  =  4 ( 4 + x)

27 =  16  +   4x

11 =  4x

x = 11 / 4

This diagram seems incorrect.....    How can  0, 0   be between   -3,2   and  -2,1 ?     The x coordinates make no sense to me ...

Anyway...using the numbers given:

     all of the radii are the same length ...so the distance^2 from P to B is equal to the distance^2 from P to O

        then using the distance formula :

(x- -3)^2 + (y-2)^2   =  ( x-0)^2 + (y - 0)^2 

x^2 + 6x + 9     +    y^2 -4y +4 = x ^2 + y^2 

6x - 4y + 13 = 0   

Similarly , the distance^2 between P and A   is the same as distance ^2 from P to O 

resulting in  4x - 2y + 5 = 0 

Solving these two simultaneous equations results in   x = 3/2    y = 11/2    for the center of the circle   ( kinda nonsensical)  . 

To find the volume of this conical frustum, we can use the formula for the volume of the conical frustum which is:

 V = (1/3) x π x h x (r² + R² + (r x R))

Plugging in the values, we get:

V = (1/3) x π x 92 x (25² + 33² + (25 x 33))

V = 92/3 x π x (625 + 1089 + 825)

V = 92/3 x π x 2539

V = 92/3 x π x 2539

V = 244612.781589

V ≈ 244612.78 

Answer: V = 244612.78 units

To find the surface area of this conical frustum, we can use the formula for the surface area of the conical frustum which is:

SA = π x [ r²+ R² + (r + R) x √((r - R)² + h²) ]

Plugging in the values, we get:

SA = π x [ 25²+ 33² + (25 + 33) x √((25 - 33)² + 92²) ]

SA = π x [ 625 + 1089 + 58 x √(64 + 8464) ]

SA = π x [ 1714 + 58 x √8528 ]

SA = π x [ 1714 + 58 x 92.3471710449 ]

SA = π x [ 1714 + 5356.1359206 ]

SA = π x [ 7070.1359206 ]

SA  ≈ 22211.49

Answer: SA = 22211.49 units

AOB is a  central angle....it has the same  measure as its  intercepted arc

See if this  helps  : https://web2.0calc.com/questions/help-with-algebra_96

minor arc CB =  180  - minor arc AC  =  180 -  40 =  140

(1/2) (minor arc AD + minor arc CB)  = angle AED

(1/2) (100 + 140)  =  120° = angle AED

angle AED + angle DEB =  180

120  + angle DEB =  180

angle DEB  = 180 - 120   =   60°

If you do a search , you will find this question ( or one with slightly different numers) has already been posted and answered....  

Will rows    50 m/min * 45 min = 2250 meters    before Grace even starts

     so now there is only   2800 - 2250 = 550 meters between them 

       their closing speed when they are rowing toward each other is 30 + 50 = 80 m / min

           at this rate they will meet in    550 m / 80 m/min = 6.875 minutes after Grace starts       2:45 + 6.875 min = 2:51  and  52.5 seconds 

                                                                                                                         which is about 2:52 PM 

15 m X 60 m =   900 m ^2           <====== area of the wall 

now convert to ft^2 

900 m^2   / ( .3048 m/ft  * .3048 m/ft )  = 9687.5 ft^2 

Now find the paint required .....

  9687.5 ft^2 / 400 ft^2 / gal = 24.22 gallons   ... you will need to buy 25 gallons    

d = distance       s = plane speed       w = wind speed = 70

d/s  = 1.667 hr      ( distance/rate = time.....   this is for one way)     this shows   s = d/1.667

with and without the wind 

d/(s+w)  + d/(s-w) = 3.833 hr       re-arrange

d(s+w) + d(s-w) = 3.833 (s^2 - w^2)       now sub in some values 

d ( s+70) + d(s-70) 

2 ds   = 3.833 s^2 - 18781.7                 Sub in the definition for s (from above)

2d ( d/1.667) = 3.833 d^2/ 2.778 - 18781.7     Continue to simplify and solve for  'd' 

1.38 d^2  - 2d^2/1.667 - 18781.7 = 0  

.1802 d^2 - 18781.7 = 0 

d = 323 miles 

Very similar Q to help you complete this one:

We know that 45 members can paint a wall in 60 minutes, so we can find out that 12 members can paint the same wall in 60 x 45/12 = 60 x 3.75 = 225 minutes.

Answer: 225 minutes

Well, m∠ABR is equal to 90° because the angle formed by a tangent and the radius or diameter has to be a right angle. Since we know that m∠ABR = 90° and m∠CBA = 25°, and m∠CBR = m∠ABR - m∠CBA, then m∠CBR = 90° - 25º = 65º.

Answer: m∠CBR = 65°

We know that 50 members can paint a 3600 square foot wall in 20 minutes.

25 members will take twice as much time because the number of members is halfed, so 25 members can paint a 3600 square foot wall in 20 x 2 = 40 minutes. To paint a 4000 square foot wall, 25 members will paint the wall in 40 x 4000/3600 = 40 x 1.11111 ≈ 44.4 or 44 minutes.

Answer: 44 minutes