All Answers 358547 Answers

the sum of two digits number is 7 and their product is 12. what is the difference between these two digits? how?

You can do this formally if you want.

x+y=7

xy=12

Then solve simultaneously.

But this one is really easy.

If the 2 numbers mult to a positive then they both must be neg or both positive.

They add to a positive so they both must be positive.

3 and 4 is the obvious answer.  :)

the difference between these two is 4-3=1

1+2+22+21=46

3+4+20+19=46

5+6+18+17=46

7+8+16+15=46

9+10+14+13=46

11+12=23

46*5+23=230+23=253

There are of course many ways to do a question like this.

It could be done as the sum of an AP if you know about those. :)

This is a great question!  I have assumed that outside the buiding is all grass. :)

Grassed area = 3/4 of the big circle + the quadrant of the little circle

$$\\grass =\frac{3}{4}\times \pi \times 7^2\;+\;\frac{1}{4}\pi\times 2^2\\\\
grass =\frac{151\pi}{4}\\\\
grass =\frac{151\pi}{4}\\\\
grass =118.6\;m^2\qquad$Correct to 1 decimal place$\\\\$$

If you have any questions just ask :))

You should know that 25% is one quarter.

$$\frac{1}{4}\times\frac{2}{3}=\frac{1\times 2}{4\times 3}=\frac{2}{12}=\frac{1}{6}$$

I often get stubborn about answering questions that are so poorly presented.  

I want to see all the question at once if it is possible and I hate scrolling.  Sorry. 

That is a big number :)

Do it on the calc on the home page :)

x+1*x^2+1

$$x+1*x^2+1=x+x^2+1=x^2+x+1$$

perhaps you really mean

(x+1)*(x^2+1)

$$\\(x+1)*(x^2+1)\\
=x(x^2+1)+1(x^2+1)\\
=x^3+x+x^2+1\\
=x^3+x^2+x+1$$

arc sine is the same as inverse sine  

15/100*5 minutes

then multiply by 60 to turn it into seconds  

Square roots are like brackets or like absolute signs.  You have to simplify what is under them first.  :)

D you mean $19.48 - $6343.00

That equals one big debt!

You can use the site calc on the home page if you want to work out how much you owe!  

I assume you are talking baseball?

This is like a foreign language for me and the interpreters are not working.

So sorry I have no idea what you are talking about.  :(((

It has to be otherwise it would not be a good torture for you!

1,328.5*100 = 132850%       

I wish I could get that interest rate for my money!   LOL

First question.  These graphs might help:

In general, insert the two values into the function.  If the results are of opposite sign there is a zero between them.

Second question

$$\frac{3}{10}\div \frac{1}{5}\\\\
=\frac{3}{10}\times \frac{5}{1}\\\\
=\frac{3}{2}\times \frac{1}{1}\\\\
=\frac{3}{2}\\\\
=1\frac{1}{2}\\\\$$

I am not a all sure what you mean  

You can do this on the site calc

put it in like this :)

(12+1/6)*(4+1/4)/2

Well that depends :)

(-6)^2=-6*-6=36

but

-6^2=-1*6*6=-36

There is your picture. :)

$$\\sin\theta=\frac{\sqrt{40}}{7}\\\\
cosec\theta=\frac{7}{\sqrt{40}}\\\\
cos\theta=\frac{-3}{7}\\\\
sec\theta=\frac{7}{-3}\\\\
tan\theta=\frac{\sqrt{40}}{7}\div \frac{-3}{7}=\frac{\sqrt{40}}{7}\times \frac{7}{-3}=-\frac{\sqrt{40}}{7}\\\\
cot\theta=-\frac{7}{\sqrt{40}}$$

You could clean some of those up a little :)

Use  tangent:  tan(angle) = opposite/adjacent

Here:  tan(41°) = height/1210

so:  height = 1210*tan(41°)

$${\mathtt{height}} = {\mathtt{1\,210}}{\mathtt{\,\times\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}{\left({\mathtt{41}}^\circ\right)} \Rightarrow {\mathtt{height}} = {\mathtt{1\,051.836\: \!952\: \!757\: \!36}}$$

height = 1052 ft to the nearest foot.

.

$$\\(2x + 4)(2x - 4) \\
=(2x)^2-4^2\\
=4x^2-16$$

$$\begin{array}{rll}
2/5(5x-15)&>&4\\
5*[2/5(5x-15)]&>&5*4\\
2(5x-15)&>&20\\
5x-15&>&10\\
5x&>&25\\
x&>&5\\
\end{array}$$

Look here