All Answers 359166 Answers

nevermind, fixed it, needed to rewrite 1 to 3log3

Great job!!! Not.  This is a dumb running gag.

Aren't you smart?!?!

2+2=4

or.....

2+2=22

Your choice

49528.48666666666666666667

There are infinite possibilities, but here's one:

√(4.7321²) ≈ √22.39277041

I'm making the following assumptions

1) There are 3 spaces for the letters but we can have repeats

2) There are "N" blank spaces

So, the total number of spaces is N + 3

And we want to fill 3 of the spaces with a letter (allowing repeats)......so we have 3³ = 27 ways of choosing the letters.

And the number of arrangements of these blank spaces and letters is just C(n+3, 3),

So the total possibllities are  27*C(n+3, 3)

Let's see how we got that answer.....

"Is" means "equal"

"Of" means "multiply"

"What".....we'll let this be "N"

So we have.....

846 = .76 x N         divide both sides .75

1113.157 ≈ N ≈ 1113.2

13x - 2x = 11x    and this IS a polynomial......it's a line drawn through the origin with a slope of 11....!!!

Cool!  Thanks!

Happy7....if you go to "Formulary" on the onsite calculator. it will actually calculate areas and volumes of various geometric figures.......!!!!

Okay.  Got it.  Thanks for the help!

Happy7, the surface area of a sphere is given by:

S_a = 4 x pi x r²   ...... where r is the radius

The expected value is given by:

(prize amt - cost to play) x (probability of winning)

So, we have three prizes....the probability of winning the $1000 and $500 prizes is 1/1000 and the probability of the $100 prize is 5/1000. So we have:

(1000 - 3)(1/1000) + (500 - 3)(1/1000) + (100 - 3)(5/1000) ≈ $1.98

In theory, you should probably play.

Approx. 1,113.2

I've seen this problem before, and I always liked it too, Melody!!!  It's not too difficult, but it does require a bit of thinking!!!

Nice answer.....

A/A = 1   but A cannot be 0  

Any real number (except 0 ) divided by itself is 1 

the same as a positive one.

eg

6^-3

Thanks Chris

I really must learn this stuff - maybe not tonight though :)

You need an angle as well.

then you can use trigonometry.  

FV=300(1+0.032)^12

You can finish it - use the site calc on the home page.  :)

How do I solve for x?

(a) log4(3) = log5(x) How do I solve for x?

Use the change of base law

 $$\\log_4(3) = log_5(x) \\\\
\dfrac{log_{10}3}{log_{10}4}=\dfrac{log_{10}x}{log_{10}5}\\\\
\dfrac{log_{10}3}{log_{10}4}\times{log_{10}5} =log_{10}x\\\\
10^{log_{10}x}=10^{\frac{log_{10}3}{log_{10}4}\times{log_{10}5}} \\\\
x=10^{\frac{log_{10}3}{log_{10}4}\times{log_{10}5}} \\\\$$

$${{\mathtt{10}}}^{\left({\frac{{log}_{10}\left({\mathtt{3}}\right)}{{log}_{10}\left({\mathtt{4}}\right)}}{\mathtt{\,\times\,}}{log}_{10}\left({\mathtt{5}}\right)\right)} = {\mathtt{3.580\: \!309\: \!929\: \!757\: \!902\: \!4}}$$

I think

There is $2000 worth of prizes and the tickets sell for a total of $3000

Therefore

The expectation is 2/3 of $3 = $2

20log20+15log15

=log400+log225

=log(400*225)

=log(90000)

=log(9*10000)

=log9+log10000

=4+2log3