001.
Use v = u + at (assuming constant acceleration applied by the bowstring).
127 = 0 + 139t
t = 127/139 s
$${\mathtt{t}} = {\frac{{\mathtt{127}}}{{\mathtt{139}}}} \Rightarrow {\mathtt{t}} = {\mathtt{0.913\: \!669\: \!064\: \!748\: \!201\: \!4}}$$
t ≈ 0.9137 s
002.
Since it doesn't accelerate after it leaves the bow and there is nothing to retard it in space, it continues with the same speed: v = 127 m/s.
003.
distance = speed*time
distance = 127*3.5 m
$${\mathtt{distance}} = {\mathtt{127}}{\mathtt{\,\times\,}}{\mathtt{3.5}} \Rightarrow {\mathtt{distance}} = {\mathtt{444.5}}$$
distance = 444.5m
.