All Answers 359166 Answers

325*ln (2t + e)     and we're sustituting 17 for "t"......so we have

325*ln (2*17 + e) =

325* ln (34 + e)        note, 34 + e = 36.7182818284590452.....so....

325* ln (36.7182818284590452)  and  ln (36.7182818284590452) = 3.603274773493579695 .......so.....

325 * 3.603274773493579695 = 1171.064301385413400875 = 1171

Does that help ???

So...we want to solve

9= c(2)^3 - 9(2) + 3

9 = 8c - 18 + 3

9 = 8c - 15     add 15 to both sides

24 = 8c          divide by 8 on both sides

3 = c

This function is at its max when x = 0......then y = 1, i.e.,  b = 1

As x becomes greater and greater in  both positive and negative diections, the denominator  → ∞ and y → 0 =  a

So the range is (0, 1 ]

Actually, I have three. One is a gift from my grandfather. It’s made from bamboo, and he used it when he was in college and my father did too.

Another is a gift from my cousin who goes to an Amish school in Pennsylvania, where electricity –even from a battery --is not used, so no calculators. He carved this himself, and it is more a work of art than practical.

The third one, my older brother found on eBay. It’s plastic and precise. That is the one I carry to school. It's a little longer than the others so it makes a better back scratcher. :)

_7UP_

Where do you buy a slide rule SevenUp.  Do you have good antiques stores around your place?   LOL

Hi Ms. Melody,

My eyes are young and work well for reading fine print and old text books.:)

315's answers are correct. (IMHO)

The second answer can be reduced.

I was reading a similar question in an ancient text book that uses look up tables and slide rules.

The formula is just a variation on the circumference of a circle.

T= (2pi *L*sin(theta) )/Sqr(L*g*sin(theta)*tan(theta))

Rearranges to

T= 2pi *sqrt(L²*sin²(theta))/(g*L *sin(theta)*tan(theta))

Reduces to

T= 2pi *sqrt(L*cos(theta)/g)

Though mathematically the same, these ancient text books often simplified the equations as much as possible to make the use of a slide rule easer.

As far as I know, I’m the only student in my school who uses a slide rule. They never need batteries and it makes a great back scratcher. Hahaha

_7UP_

x = 7 is just a vertical line through the x axis at, surprise, (7, 0)  !!!

The slope of a vertical line is undefined...there is no y intercept...this line never intersects the y axis....

-3x^2+sqrt(2x)+1/2 ......when x = √2, we have

-3(√2)^2 + √(2√2) + 1/2 =

-3(2) + √(2√2) + 1/2 = about -3.818

Add the coins and currency in with the checks....this will be the gross deposit....doing a quick check with the calculator......this = the net deposit.......so no cash was given back.

$9998.67 is your answer

We have a right triangle where GI is the hypoteneuse and IH is one of the legs.....by the Pythagorean Theorem,

HG = √(52²- 21²)

And we can find angle I by using the tangent inverse

tan^-1 (√(52²- 21²) / 21) = about 66.18°

Hi 315,

This is very difficult to see/ read

I can't answer anyway but I think Alan will have a problem as well.  :)

Anon's answer is correct for the question actually asked

$$(-8 - 4 / -6 - -2)\\
=-8 - 4 / -6 +2\\
=-8 - (4 / -6)+2\\
=-8 - (2 / -3)+2\\
=-8 - (2 / -3) +2\\
$At this point I would do it slightly differently$\\
=-8+2 - (2 / -3) \\
=-6 + (2 / 3) \\
=-5\frac{1}{3}$$

We have

sin(48) = c /3   just multiply both sides by 3....so we have

3 * sin(48)  =  c  

I'll let you evaluate that one !!!

Note, Anonymous 1.3333 is ok, but to be precise......1 + 1/3  (or 4/3) is better !!!

is a 1.333333 or 1 1/3?

Yep.....

so the endpoints are -3/2 and 2/5?

The bit under the square root must be greater or eqal to zero.

the easiest way to do questions like this is to let

$$y=-10x^2-11x+6$$

now you have

$$f(x)=\sqrt{y}$$

$$y\ge0\\$$

I just saw CPhill's answer pop up so there is no point in me continuing.

If you have questions just ask.  :)

Since we can't take the square root of a negative quantity, we need to find where -10x^2 - 11x + 6 = 0

Set  it  = 0  and multiply through by a -1....so we have

10x^2 + 11x - 6 = 0    factor, if possible

(5x - 2)(2x + 3) = 0

Setting each to 0, we have that x = 2/5 and  x = -3/2

Now, we need to find the intervals where -10x^2 - 11x + 6 < 0

This will occur at either  x < -3/2  or     -3/2 < x  < 2/5       or     x > 2/5

Letting x = 0 we see that -3/2 < x  < 2/5  "works"

If you pick any point in the other two intervals, the expression inside the radical will be < 0.

So, our answer is  -3/2 ≤ x ≤ 2/5

g(a)=3a-4

but g(a)=0

so you have to solve

0=3a-4

can you take it from there?

There has to be an end.

The domain of any square root function is D={xER} I dont know what you mean by endpoints when it never ends.

-.- Yea, dont listen to me I completely screwed this up

(-8-4/-6--2)     BEDMAS

-4/-6=2/3       Division

(-8+2/3+2)    

-24/3+2/3+6/3   Addition

-16/3

OK........we have .246 degrees

To find the number of minutes, multiply this by 60 = 14.76 minutes

This says we have 14 minutes and another .76 minutes. And since there are 60 seconds in a minute, we have .76 * 60 = 45.6 seconds

So....

.246 degrees  = 0 degrees 14 minutes 45.6 seconds