All Answers 358108 Answers

I agree....

It's week-to-week in the NFL......what someone did last week, doesn't necessarily mean they'll do the same thing this week......

my choices are -2.3628

-252.4716

0.8189

and -1.70480

-4x(2x-9)      distribute -4x over the terms in the parentheses

-8x² + 36x

I don't like Dallas much either.....

How should the Chiefs beat the Broncos if the Chiefs can't beat the Raiders???

(BTW....the Cowboys aren't as bad as the Pat's or Panthers)

As much as I hate Dallas....I'm picking them ....(I hope I'm wrong !!!)

I also like the Chiefs over Denver

I agree with all the rest of your picks, h7  !!!

$${\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{\,-\,}}\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{y}}\right) = {\mathtt{700}} \Rightarrow {\mathtt{y}} = {\mathtt{\,-\,}}{\frac{{\mathtt{175}}}{{\mathtt{2}}}} \Rightarrow {\mathtt{y}} = -{\mathtt{87.5}}$$

Here!

(19 - 4) * 6 + 12 * 5 = 150

(19 - 4) * 12 - 6 * 5 = 150

Heureka, your maths are always amazing.

This simple problem demonstrates just how amazing!

_7UP_

As for Aggies and Tigers.....I like LSU....I think they both honestly have a chance of winning...I'm putting the odds 55-45 for LSU  (not score, percent of winning!)

If you go to "Formulary" on the onsite calculator, you will see an applet that will calculate this.......(don't forget to divide the diameter by 2  to get the radius)

80.4052

FWIW.....I hate the Buckeyes, too......!!!

a drinking problem            

I hate the Buckeyes.....but they are playing at State,  and if MSU can't beat them, neither can Michigan

Hate Florida.....just hate em.....and FSU is undefeated, like barely though

Nebraska and Iowa???  Tricky one....like Iowa and Wisconsin.....Wisconsin is another tricky one,  Minnesota is surpsrisingly good

HAHAHA!!!......(not backing the Wolverines this week, h7 ???)

I'm going for an upset with Florida over FSU

I'm also going with Nebraska over Iowa....

I agree with the rest of your picks   (although I'm not too confident that LSU beats the Aggies !!!)

Read 'em and weep, h7   !!!!!

In English:  What amount of oxygen in grams is it to oxidize aluminum 25mol

Use the binomial expansion, which, for (a + x)ⁿ = aⁿ + na^n-1x + n(n-1)a^n-2x²/2! + n(n-1)(n-2)a^n-3x³/3! + ...

Here: a = 4, n = 1/2 (because √(4 + x) = (4 + x)^1/2), and you don't need to go further than the terms written above because these go as far as the x³ term.

.

A + b = 1  →  b = 1 - A 

So, subsituting, we have

A² + (1 - A)² = 2

A² + 1 - 2A  + A² = 2    rearrange

2a² - 2A - 1 = 0      And using the on-site solver and substituting "x" for "A" ......we have....

$${\mathtt{2}}{\mathtt{\,\times\,}}{{\mathtt{x}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{1}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = {\mathtt{\,-\,}}{\frac{\left({\sqrt{{\mathtt{3}}}}{\mathtt{\,-\,}}{\mathtt{1}}\right)}{{\mathtt{2}}}}\\
{\mathtt{x}} = {\frac{\left({\sqrt{{\mathtt{3}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right)}{{\mathtt{2}}}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{x}} = -{\mathtt{0.366\: \!025\: \!403\: \!784\: \!438\: \!6}}\\
{\mathtt{x}} = {\mathtt{1.366\: \!025\: \!403\: \!784\: \!438\: \!6}}\\
\end{array} \right\}$$   

So, b = 1 - (-[√3 - 1 ] /  2)   =  [1 + √3 ] / 2     or  b = 1 - [ [1 + √3 ] / 2] = [1 - √3 ] / 2

So

A³ + b³ = ( [1 - √3] / 2 )³  + ( [1 + √3 ] / 2)³ = ( [1 + √3] / 2 )³  + ( [1 - √3 ] / 2)³ = 2.5

$${\mathtt{\,-\,}}\left({\mathtt{4}}{\mathtt{\,\times\,}}\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{9}}\right)\right) = {\mathtt{\,-\,}}\left({\mathtt{\,-\,}}{\mathtt{36}}{\mathtt{\,\small\textbf+\,}}{\mathtt{4}}{\mathtt{\,\times\,}}{\mathtt{2}}{\mathtt{\,\times\,}}\left(\underset{{\tiny{\text{Error: Unknown Identifier}}}}{{\mathtt{x}}}\right)\right)$$

$${\frac{{\mathtt{150.86}}}{{\mathtt{12}}}} = {\frac{{\mathtt{7\,543}}}{{\mathtt{600}}}} = {\mathtt{12.571\: \!666\: \!666\: \!666\: \!666\: \!7}}$$

I 100000% agree with both of you but there should be a filter that filters ou dumb questions.