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I knew it. I knew that whoever answered this actually answered in binary. Good job. Have a thumbs-up.

If you just change the poor dogs name to something better, like Spot or Rover, then the dogs self-esteem will improve and he will not need to eat so much to “medicate” his depression.

If that doesn’t work, find him a new mistress.

If that  doesn’t work, just change his name to Porky.

01000001 01101110 01110011 01110111 01100101 01110010 00100000 01110111 01101001 01110100 01101000 00100000 01111010 01100101 01110010 01101111 00100000 01101111 01110010 00100000 01101111 01101110 01100101 00101100 00100000 01111001 01101111 01110101 00100000 01100110 01110101 01100011 01101011 01101001 01101110 01100111 00100000 01101101 01101111 01110010 01101111 01101110 00100001

Plot the real parts against the imaginary parts:

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4.34 x 10^-1

what is the explicit equation for the terms (1,6) (2,18) (3,54)

$$\boxed{y=ax^2+bx+c}\\
\begin{array}{lrcl}
(1): & \quad 6 &=& a*1^2+b*1 +c \\
(2): & \quad 18 &=& a*2^2+b*2 +c \quad | \quad : 2 \\
(3): & \quad 54 &=& a*3^2+b*3 +c \quad | \quad : 3 \\
\hline
(1): & \quad 6 &=& 1a+b + c \\
(2): & \quad 9 &=& 2a+b +\frac{1}{2} c \\
(3): & \quad 18 &=& 3a+b +\frac{1}{3} c \\
\hline
I: (2)-(1): & 9-6=3 &=& 2a+b +\frac{1}{2}c-(1a+b+c) = a -\frac{1}{2} c\\
II: (3)-(2): & 18-9=9 &=& 3a+b +\frac{1}{3}c-(2a+b+\frac{1}{2}c)= a -\frac{1}{6}c\\
\hline
II-I: & 9-3=6 &=& a-\frac{1}{6}c-(a-\frac{1}{2}c) = \frac{1}{3}c \\
\textcolor[rgb]{1,0,0}{c} &\textcolor[rgb]{1,0,0}{=}& \textcolor[rgb]{1,0,0}{18}\\
\hline
I: & 3 &=& a - \frac{1}{2}18 = a-9 \\
\textcolor[rgb]{1,0,0}{a} &\textcolor[rgb]{1,0,0}{=}& \textcolor[rgb]{1,0,0}{12}\\
\hline
(1): & 6 &=& 12 + b + 18 = 30 + b \\
\textcolor[rgb]{1,0,0}{b} &\textcolor[rgb]{1,0,0}{=}& \textcolor[rgb]{1,0,0}{-24}\\
\end{array}
\\
\boxed{y=12x^2-24 x+18 }\\$$

y = (2)3^x    where x in an integer > 0

3x-4y=-15 and 5x+y=-2

We can write the second equation as y = -2-5x   ......and substituting this into the first equation for y, we have

3x -4(-2-5x)  = -15   simplify

3x + 8 + 20x   = -15

23x + 8  = -15     subtract 8 from both sides

23x  = - 23          divide both sides by 23

x = -1      and y = -2 -5(-1)  =  -2 + 5  = 3

So (x, y)  = (-1, 3)

normalcdf(-2.7,1.3)

normalcdf (-2.7, 1.3, 0, 1 ) =  0.89973254161135

Not if you don't ask a question.  

Thanks Geno,

What ever happened to please anon ??    Maybe it is under the bed.  Maybe you should look :)

just use the minus sign   

2.07088 x 10²¹

This is found by counting the number of places that you must move the decimal point from the end of the number to the location immediately after the first (left-most) digit.

I'm assuming that the problem is:  y  = 2x² + 5x - 3

This problem can be factored:                (2x - 1)(x + 3)  =  0

                  --->                                       2x - 1  =  0          or          x + 3  =  0

                  --->                                              x  =  1/2       or                 x  =  -3

This problem can also be solved by using the quadratic formula or by completing the square.

By the manner that you asked the question, are you supposed to complete the square?

A formula to find the x-value of the vertex of a quadratic function is:  x = -b/(2a)

In  f(x)  =  2x² + 36x + 170     --->     a = 2,  b = 36,  and  c = 170

x  =  -b/(2a)   --->   x  =  -36/(2·2)  =  -36/4  =  -9

f(-9)  =  2(-9)² + 36(-9) + 170  =  8

Since the value of a > 0, this is a rising parabola, so the point (-9, 8) is a minimum.

The minimum f-value is 8.

Let m represent the number of minutes.

Amount of water in Karla's tank:  100 + 5m

Amount of water in Jake's tank:  50 + 10m

Same amount of water:  100 + 5m  =  50 + 10 m

--->                                         100  =  50 + 5m

--->                                            50  =  5m

--->                                            10 = m

In ten minutes, Karla's tank will have 100 + 5(10)  =  100 + 50  =  150 gallons.

In ten minutes, Jake's tank will have 50 + 10(10)  =  50 + 100  =  150 gallons.

I am not sure what you mean but

you have to remember the word Hyptenuse.  That is the longest side it is opposite the right angle.

The house opposite yours is the one across the road - it is not touching. There is no common fence.

It is the same with triangles.  The side opposite an angle is not touching the angle at all.  It is across (opposite) it.

That is all you need to know for the names in pythagoras' theorem.

The sqare on the the hypostenuse (longest side which is opposite the right angle) is equal to the sum of the squares on the other 2 sides.

$$h^2=a^2+b^2$$     

hit insert

then from the dropdown menu choose 'special character'

The degrees symbol is on the second line 5th from the end :)

Saseflower is right but the symbol is diferent in differerent counties.

$$\\0.333333=0.\dot3\qquad $In Australia.$\\\\
0.333333=0.\bar3\qquad $In some other countries$\\\\\\
0.2345345345...=0.2\dot3 4\dot 5\qquad $In Australia.$\\\\
0.2345345345...=0.2\bar3 \bar4 \bar5\qquad $In some other countries$\\\\
$ In the last example the bars are meant to be all joined together :)$$$

Hi Anon,

I teach little kids these concepts on a 1 to 1 basis and I have extremely good results.

What Geno has done is absolutely correct (and maybe your daughter can handle an explanation like that) but it is not really aimed at helping a ten year old to understand the concepts involved.  

My favourite tool when I teach ten-year-olds fraction concepts is an empty egg carton and some lego blocks.

The carton is the whole.  Get your daughter to put blocks in a quarter, a half, a third, a sixth, 5 twelths etc.

Then start using the carton to work out some addition problems.  (use different coloured blocks to help with addition)  You can show on paper what you are doing with the carton. But the initial emphasis should be with the visual hands on carton and blocks. 

Take it easy, your daughter is little.  She will learn much better if you give her time to process her 'play'.  

There are a lot of concepts involved in the problem you have presented.  You also need to see if she understands how to turn decimals into fractions.

If this is homework and she is at a level where she can understand with just minimal 'leading' by you then that is great.

If not then don't push it.  Spend time on developing the understanding of the concepts.  It will make math fun and it will lead to a much fuller understanding in the long term. 

It is extremely important that primary children develope the concept of numbers and how they fit together. 

Good luck to both of you :)))

Thanks Alan,

I think I have got my head around that.  :)

How would you do that integration by hand?

Let  log_1/4(32^-18)  =  y 

Then, writing this in exponential form:  (1/4)^y  =  32^-18

(1/4)  =  2^-2   --->   (1/4)^y  =  (2^-2)^y  =  2^-2y                                    

32^-18 =  (2⁵)^-18   --->   2^-90

So:   (1/4)^y  =  32^-18    --->    2^-2y  = 2^-90   --->   -2y  =  -90   --->   y  =  45