All Answers 359152 Answers

I have just been looling at Wassily Kandinsky's artwork.  It is quite varied.

Thanks for this thread anon - I like seeing different things in the forum :)

$$\small{\text{
$15500-12\% $
}}
$\\$
\small{\text{
$=15500-(12\%\ of \ 15500) $
}}
$\\$
\small{\text{
$=15500-15500*12\% $
}}
$\\$
\small{\text{
$=15500*1-15500*12\% \quad | \quad 1 = \frac{100}{100}=100*\frac{1}{100}=100\%
$
}}
$\\$
\small{\text{
$=15500*100\%-15500*12\%$
}}
$\\$
\small{\text{
$=15500*(100\%-12\%)$
}}
$\\$
\small{\text{
$=15500*88\% $
}}
$\\$
\small{\text{
$=15500*\frac{88}{100}$
}}
$\\$
\small{\text{
$=155*88 $
}}
$\\$
\small{\text{
$=13640$
}}$$

Hi Kitty  

(1/8) ÷ 4

= (1/8) ÷ (4/1)

Dividing by a fraction is the same as multiplying by its reciprocal:

= (1/8) * (1/4)

= (1*1)/(8*4)

= 1/32

1. Suppose you and a friend are working for a nursery plating trees. Together you can play 8 trees per hour. Qhat is the greatest number of hours that you and your friend would need to plant at most 40 trees?

$$\small{
$ \dfrac{ 40 \text{ trees } } { \dfrac{ 8 \text{ trees } } {1\ h} }
= \dfrac{40}{8} = 5\ h$
}$$

2. The Garcias are putting a brick border along one edge of their flower garden. The garden is no more than 31 ft long. If each brick is 6 in. long, what is the greates number of bricks needed?

$$\dfrac{ 31\ ft * \dfrac{12\ in }{ 1\ ft } }{ 6\ in } = \dfrac{31*12}{6}= 62\text{ bricks}$$

On the website calculator, click on the word "Scientific" (on the right of the answer box).

Choose "Equations" from the drop-down menu that will appear. The calculator should now show the words "Equation Solver."

Then click on the button "1 variable, 1 equation" and change it to however many equations are in your system of equations. (I believe the maximum is 6, at least if you input equations in this way.)

Then, after you have typed in the equations, click "Enter" and the answers should pop up:)

Alternate way:

Type in "solve("

Then type in all your equations in the system.

Close the parentheses and click "Enter"

Using this method you can have more than 6 equations in one system.

That is a very good question anon.  

A dollar times by 0 can be interpreted  as zero lots of a dollar which is certainly nothing (no money anyway)

Now by the same logic 0 times 0 could be said to be zero lots of nothing  which means that you cannot have nothing because I just said I have zero lots of nothing.

 logically this should/could mean that you have something. Because if you don't have nothing then you must have something.

0*0=0  this is what I have always believed to be true but after this logical examination of the situation perhaps another mathematician would like to comment.   

Press (scientific) in the top right corner of the calc

There is a drop down menu - vectors/matrices is one of the choices

when in there - there is a button on the left where you can choose vectors or matrices 

then it is pretty obvious I think   

Thanks anon.

You could do it this way too

$$\\\frac{2}{5}(1a-15)\le4\\\\
\frac{2}{5}\times\frac{5}{2}\times(1a-15)\le4\times\frac{5}{2}\\\\
(1a-15)\le 10\\\\
a-15\le 10\\\\
a-15+15\le 10+15\\\\
a\le 25\\\\$$

Is that an answer you got on your calc?

It   means           $${\mathtt{8.33}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{\left(-{\mathtt{5}}\right)}$$   =   0.0000833

Please note that arc cos [acos] is trhe same as inverse cos     

$$\frac{125}{1000}=\frac{1}{8}$$

 8z^2=6z^2+38

$$\small{\text{
$
\begin{array}{rcl}
8z^2 &=& 6z^2+38 \quad | \quad -6z^2 \\
8z^2-6z^2 &=& 38 \\
(8-6)z^2 &=& 38 \\
2z^2 &=& 38 \quad | \quad :2 \\\\
z^2 &=& \dfrac{38}{2} \\\\
z^2 &=& 19\quad | \quad \pm\sqrt \\
z_{1,2} &=& \pm\sqrt{19} \\
\end{array}
$
}} $\\\\$
\small{\text{
$
z_1 &=& 4.35889894354 $ and $ z_2 &=& -4.35889894354
$
}}$$

Yes,  1296=36*36

9 to the 4th power over 9 to the 6th power

$$\small{\text{
Set $ 9^4 = \dfrac{ 1 }{ 9^{-4} } $. We have
$
\dfrac{ 9^4 }{ 9^6 } = \dfrac{1 }{ 9^6 }*9^4 = \dfrac{1 }{ 9^6 }*\dfrac{ 1 }{ 9^{-4} } = \dfrac{1 }{ 9^{6-4} } = \dfrac{1 }{ 9^{2} } = \dfrac{1}{81} = 0.01234567901
$
}}$$

You guys are awesome! Thank you so much, it helped a lot. I appreciate it!

(2+5j)/(3+j)

$$\small{\text{
$
\dfrac{ (2+5j) } { (3+j) } * \dfrac{ (3-j) } { (3-j) } =
\dfrac{ 6-2j+15j-5j^2 } {9-j^2 } $
}} \\\\
\quad \boxed{j^2=-1}
\\\\
\small{\text{
$
=\dfrac{ (6+13j+5) } { (9+1) }
=\dfrac{ 11+13j } {10 }
=1.1+1.3j $
}}$$

Which equation represents the relationship between h, the number of hours she drives and m the number of miles she completes?

m = 45 * h

Example: m(6) = 45 * 6 = 270  okay!

the variable a would be 25 or lower because when you put it in with 25 as a the left side would equal 4, and any number below 25 would work too. What I did was 2/5(1a-15) less than or equal to 4. then I used the distrubitive property. 2/5a-6 less than or equal to 4. I then added 6 to both sides. That will cancel out the -6.

                                      +6                             +6

2/5a less than or equal to 10. Then I divided 2/5 to both sides.

/2/5                               /2/5

a is less than or equal to 25. 

The full answer is 17.6432876311,

but you could round it to the hundredths place

which would be 17.64

19 

BUT, DON'T YOU KNOW THIS?

ANYTHING TIMES 0 IS ZERO

EX. 

If I have a dollar in my hand and multiply it by 0, won't I still have a dollar? If not, then who took my dollar? 

Let's fix your picture to make it clear where money is coming from. Let's say you're a barber and every customer tips you a dollar. At the end of the day, how much have you made in tips? Multiply a dollar by the number of customers you had. If you had 10 customers, you made $10. If you had 20 customers, you made $20. So, what about the day that your shop was closed because of a blizzard? By your reasoning, you'd still make a buck, even though you had zero customers. No, it's clear that you make $0: $1 times 0 customers is $0. 

1 oz  =  29.5735 ml   (approximately)

So:  1 oz / $20.00  =  29.5735 ml / $20.00

You can set up a proportion:

--->    29.5735 ml / $20.00  =  1 ml / x

cross multiply:  29.5735 · x  =  20.00 · 1

--->                                  x  =  $0.68

What does iqual mean?  plus you need to use brackets

Is this what you mean ?

(3x)/(x-5 )=( 1+15)/(x-5)

$$\frac{3x}{x-5} =\frac{1+15}{x-5}$$