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thanks bro u legend!

$${\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}} = {\mathtt{2}}$$

23-3 is 20

sin^-1 = the inverse sine.....just go to the onsite calculator and hit the"2nd" button, then...hit the "asin" button, key in the value you'd like to find, and hit "enter"

2x-19+19=13+19   simplify this on both sides

2x = 32      divide both sides by 2

x = 16

a)     ³√b  = b^(1/3) ....so we have

b^(1/3) / b^(1/6)   ....remember  a^m / a^n = a^(m-n)...so we have  b^(1/3 - 1/6)  = b^(1/6)

b)  (x^3)^2 * y^(-2) / xy   =    x^6 / [x y^2 *y] = x^5 / y^3      .....remember a^(-n)  = 1 / a^(n)....also (a^m)^n  = a^(m x n)

c) a^3 x b^4 x a ^4 x a^3  = a^10 x b^4  ...  the rule is a^n * a^m = a^(n+m)

668ml per 8 sec   = 83.5ml per second......so multiply this by 60 to get your answer.....

x=16. 2x=32

"i' is an "imaginary" number......it has the property that  i^2 = -1  or, to put it another way, i =√-1

So we have

√(-64) = √[(-1)(64)] = √(-1)*√64  = i*8  or just 8*i  = 8i

Does that make sense??

8.80  =  8 + 80/100  = 8 + 8/10 = 8 + 4/5  = 44/5

Here you go....

Since 1/2 of the cards are red ones, then the chances of draawing a red card is just 1/2 or .50

Tangente inversa de (500/300)

tan-1 (500/300) = tan-1 (5/3) = 59,036243467926 ° .... recuerde, esto también podría ser un ángulo cuadrante tercero = 239,036243467926 °.

(-1,-2) and (2,2)

1st, subtract the x's and square the result...so we have  (-1-2)^2 = (-3)^2 = 9

Now, do the same for the y's  .....(-2-2)^2  = (-4)^2  = 16

(Note that the order in wich we subtract doesn't matter)

Add the two results   = 25

Take the square root of this  ...√25 = 5  ...and that's the distance

SORRY  EDIT IM DUMB I MEANT DO ASIN

edit i meant do atan

you do acos

24 45  76 34 65

The answer is 670000

It all depends on what happened.. You said it spaced out, meaning you can try to clear your history and see if that helps. If it didn't help message me back and I'll try something else..

Np dude

Thx so mutch

Ty :-) :-)