All Answers 358524 Answers

0

about 2,000,000,000,000,000,000,000,000,000,000kg
here is the equation: 5+2,000,000,000,000,000,000,000,000,000,000-5

GuestNov 13, 2013

+118725

0

Yes of course, thank you guest for picking that up.

MelodyNov 13, 2013

0

GuestNov 13, 2013

0

You made a small mistake.
4.5333X ¹¹ + 4.5333X - X ¹⁰ = 0

From here out you can exclude x:
X.(4.5333X ¹⁰ + 4.5333 - X ⁹) = 0

So you can conclude that X=0 is one of the possibilities. However the equation is the beginning contained (1/X), so you would have to say that X=0 is not possible. Now you are left with:
4.5333X ¹⁰ + 4.5333 - X ⁹ = 0

GuestNov 13, 2013

+118725

0

4.5333 = 1/x(1-(1/(1+x^10))) ....find x
Multiply both sides by x
subtract 1 from both sides
multiply both sides by (1+10^x)
add 1 to both sides
I think you end up with

4.5333X ¹¹ + 4.5333X - 10 ¹⁰ = 0

And if you can solve this you are doing really well.

MelodyNov 13, 2013

+118725

0

Well, if you've got something like log 6 = x
you would just type in log 6

Yes but you need to know what the base is, your calculator can only handle base 10 (log) and base e ( ln )
Log ₁₀ 6 = 0.77815128....
Log _e 6 = 1.791759469.....
--------------------------------------------------------------------------------

If you'd have something like this
5log6 = x (or log5,6 that depends on country) NO, THESE ARE DIFFERENT THINGS

-------------------------------------------------------------------------------------
5log6 means 5*log6 and that is how you enter it. (could be base 10 or base e or someother base, you need to know which one)

You are talking about change of base
log ₅6 which is worded as log of 6 base 5.
You can't do this on the calculator because it not in base 10 or base e, so you have to change it using change of base.

log ₅6 = log6 / log5 This will give the same answer no matter what base you use, so long as numerator and denominator have the same base.

log ₅6 = log6 / log5 = 1.113282753

I hope this clears things up a little.

This is a interactive web page that would be good for you to work through.
http://www.mathsisfun.com/algebra/logarithms.html

MelodyNov 13, 2013

0

The answer is D. 256.

1 = 1^1 4 = 2² 27 = 3³ 256 = 4^4 3125 = 5^5

GuestNov 13, 2013

0

Seriously? You need help for this? I don't care how bad at math you are, if you make an effort anyone can solve this.

(18/2).3²=9.9=81

[Maybe you meant this (then your description is wrong):

18/(2.3²)=18/(2.9)=18/18=1

]

GuestNov 13, 2013

0

Hm, I think I may have figured it out. Thanks anyway! Please feel free to still post an explanation though as I would like to make sure that I am correct, and, if not, get further explanation.

GuestNov 13, 2013

0

Well, if you've got something like
log 6 = x
you would just type in log 6
If you'd have something like this
5log6 = x (or log5,6 that depends on country)
you type in
log 6 / log 5

GuestNov 13, 2013

+118725

0

Do you mean is y=2 a solution of ....?

Is 2 a solution to the following inequality: 7y + 4 > 20

Left hand side = 7*2+4 = 18
18 is not > 20
therefore y=2 is not a solution.

MelodyNov 13, 2013

+118725

0

T _n = T _n-1 + T _n-2 + T _n-3

MelodyNov 13, 2013

+118725

0

Do you need the same answer twice or would you prefer a different one this time?

MelodyNov 13, 2013

+118725

0

1^1, 2^2, 3^3, 4^4,..........

MelodyNov 13, 2013

+118725

0

http://www.stargazing.net/david/constel/magnitude.html

I think the web page says 1/15

But I will admit to knowing nothing about this stuff.

MelodyNov 13, 2013

+118725

0

Now, that would depend on the question.

MelodyNov 13, 2013

+4

0

Dear If someone deposits $4650 in a bank that gives 3% interest compound annually, how much money will that person have after 8 years?

jacky374Nov 13, 2013

+118725

0

What Is The Square Root Of 20

root4 * root5 = 2root5

or do it on your calculator is an estimate is good enough.

MelodyNov 13, 2013

+118725

0

x/400+x/600+x/60=0

3x/1200 + 2x/1200 + 20x/1200 = 0

25x/1200 = 0

x=0

MelodyNov 13, 2013

+118725

0

Determine whether Point A (-5,8) lies on the circle whose center is Point C (1,2) and which contains the Point P (7,-4).

(x-1) ² + (y-2) ² = r ²

r ² = (distance PC) ²

r ² = (-4-2) ² + (7-1) ² = 36 + 36 = 72

so
(x-1) ² + (y-2) ² = 72

Now just plug in x=-5 and y=8 and see if it makes the equation true.
If it does then A is on the circumference of the circle.

MelodyNov 13, 2013

+118725

0

2x+1^3(6-x)= -3

2x+[ 1^3]*(6-x)= -3

2x+1(6-x)=-3

x+6 = -3

x = -9

Is this the question that you intended to ask?

MelodyNov 13, 2013

+118725

0

Star gave you 2 numbers.

MelodyNov 13, 2013

+18

0

This is "hi"
I'm using a different username btw
Anyways, I need a paired answer (the answer has 2 numbers)
but thanks anyways.

TheBOSSNov 13, 2013

+22

0

Are you trying to find T? If so, here's what you would do:
T3=10-(3)
Simplify first (collect like terms)
T3=7
Divide out the 3
T=7/3
T=2.33333333334 (The 3 never terminates)

I hope this helped!

madisonodysseyNov 13, 2013

+22

0

1+9a-8=8a
First you would have to simplify (in this case, collect like terms)
(-7)+9a=8a
Then you would move your 9a
(-7)=(-1a)
Since you're looking for positive a, you would multiply each side by negative one
7=a
or a=7

Hope this helped!

madisonodysseyNov 13, 2013

1 Online Users