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Something like this?

Corrected.  Thanks to Chris for pointing out the error in my original expression for c.

.

We can set this up as a proportion

(1/5) gallon / (2/3) bin = x gallons / 1 bin      cross-multiply

1/5 = (2/3)x     multiply both sides by the reciprocal of 2/3 = 3/2

(3/2) (1/5) = x =  3/10 gallons fills the entire bin

Look at it this way......each 1/10 of a gallon fills 1/3 of the bin......so 3(1/10) gallons fills 3(1/3)bins....or

3/10 galons fills a whole bin....

Store A is selling the jeans at  85% of $25  = $21.25

Store B is selling them at 75% of $30 = $22.50

I'd go with Store A.....

b(a+e)=x and if this is some joke for what it spells you are pretty stupid yet if its legit plug it in to your variables

Very nice, Melody......

tan(26+24/60)

$$\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{tan}}{\left({\mathtt{26}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{24}}}{{\mathtt{60}}}}\right)} = {\mathtt{0.496\: \!404\: \!310\: \!987}}$$

a)  Profit=1000x+500y

b)  profit > 15000

1000x+500y>15000

divide both sides by 100

10x+5y>150

divide both sides by 5

2x+y>30

I have to draw the line 2x+y=30 first

When x=0 y= 30

When y=0 x=15

plot these points and joint them with a line.

Colour the area to the right of the line.  That is where profit is >30   (as shown in the diagram)

now if you look at parallel lines to this one then you get other lines that represent given profits

Optimal number is 16 large and 14 small  machines

 Profit=1000x+500y

Maximum Profit = 1000*16+500*14

$${\mathtt{1\,000}}{\mathtt{\,\times\,}}{\mathtt{16}}{\mathtt{\,\small\textbf+\,}}{\mathtt{500}}{\mathtt{\,\times\,}}{\mathtt{14}} = {\mathtt{23\,000}}$$  dollars

four

four

four

Move the decimal point five places over in the direction to make the number very small  

Two angles are supplementary angles if their sum = 180 degrees.

Just subtract 1.5 from 100.  Now, multiply 2.25 by that.  I would give you the answer, but that would be cheating.  

We have

40 = 80e^(7.6k)    solve for k

divide both sides by 80

.5 = e^(7.6k)    take the ln of both sides

ln.5 = lne^(7.6k)  and we can write

ln.5 = (7.6k)lne    and lne = 1

ln.5 = 7.6k  divide both sides by 7.6

ln.5/7.6 = k = about -.0912

So, after 12.4 minutes, we have

80e^(12.4 * -.0912) = about 25.82 g

I interpreted this differently, so I don't get the book's answer. I said the production line turns out products of which 20% are defective. We want to test and discard sufficient numbers of defective items from a batch so as to leave the remainder with just 10% defective items. We need to produce sufficient to cover this procedure as well as having 10,000 plus the expected 1000 replacements that will be demanded. (90% quality control, so 10% will be defective, and returned.)

I have not yet allowed for replacements of the replacements.

357.075 I think.

you add or subtract or multiply or divid

36 miles x (5280 ft / 1 mile) x (.3048 m / 1 ft)  = about 57,936 m

$17800 / 52 weeks = about $342.31