All Answers 358334 Answers

0

I believe that is a 1-step equation and the answer should be correct!

GuestNov 27, 2013

+2

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Me also hate math....................!

Jaquenetta25Nov 27, 2013

+118727

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That depends on how much you borrow
on the interest rate
on how big the repayments are and how often they are made
and very importantly on whether it is simple interest or compound interest.
If it is compound interest you would need to know how often it is componding as well.

Simple interest questions are usually faily easy
Compound interest questions are much harder.

If you borrow a little amount you might pay simple interest but if you borrow a big amount like for a house, it will always be compound (or reducible) interest.

MelodyNov 27, 2013

+118727

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can anyone solve this?
ln(x)-2ln(x^2+1)+1/2ln(3-x^2)

Yes, you can

use
log(x) ⁿ = nlog(x)
log(a) + log(b) = log(a*b)
and
log(a) - log(b) = log(a/b)

MelodyNov 27, 2013

+118727

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sec(x)csc(x)-4csc^2(x)

What am i meant to be proving? there is not equal sign.

MelodyNov 27, 2013

+118727

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a*b=15
b*c=35
a*c=21
a=?
b=?
c=?

first get b in terms of a
now put the new value of b into the second equation and rearraange to get c in terms of a
put new value of c into third equation and solve for a
that should be enough to get you started.

MelodyNov 27, 2013

+118727

0

y-3/x=0

Okay what you meant was
(y-3) / x = 0
The first thing that you need to recognise is that x cannot be equal to zero because you cannot divide by 0
then
multiply both sides by x and you get
y-3 = 0
so
y = 3 (where x is not equal to 0)

If you graphed this it would be a horizonal line through y=3 but there would be an open circle on (0,3) to show tht this point is not included.

MelodyNov 27, 2013

0

example?

sqrt(4/16)

sqrt of 4 is 2 and

sqrt of 16 is 4 so u woud have 2/4 or 1/2

GuestNov 27, 2013

0

Based on the picture all you have to do is multiply x on both sides.
Which would equal. y-3=x then you add 3
which gives you y=x+3.

GuestNov 27, 2013

Nov 26, 2013

0

30
FIRSTSTSTSTD:D:D:D:

GuestNov 26, 2013

+4

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Melody:
y-3/x=0

I am assuming that you mean

y-(3/x)=0

Just add 3/x to both sides

y - 3/x + 3/x = 0 + 3/x

y = 3/x

Is that what you wanted?

Well, i discovered a problem, brackets aint in the problem when i got it... but its hard to write with the computer without brackets since it turns out wonrg... accroding to me

http://gyazo.com/407e19ed0fb481f0a7b1c4d8ebad4944

^^ Paint picture of the problem, amazing paint skills btw

TrisstarNov 26, 2013

0

what is 4 divided by x, subtract one

GuestNov 26, 2013

0

y-3/x=0
y(x/1)-3/x(x/1=0(x/1)
yx-3=0
yx-3(+3)=0(+3)
yx=3
yx(1/x)=3(1/x)
y=3/x

GuestNov 26, 2013

+118727

0

y-3/x=0

I am assuming that you mean

y-(3/x)=0

Just add 3/x to both sides

y - 3/x + 3/x = 0 + 3/x

y = 3/x

Is that what you wanted?

MelodyNov 26, 2013

+4

0

Trisstar:
I have a question, i am 16 years and go 1st year in gymnasium (high school) and I'm stuck trying to get y alone in this thing here...

y-3/x=0

When i try and do it myself i end up always getting that y=3x ... and I dont know what I'm doing wrong..
Help is appriciated

Did not mean to double post this, 1st thing I'm posting, didnt know why i stayed on the edit site...

TrisstarNov 26, 2013

+118727

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find x and y
x-y=3
x^2+y^2=29

If x-y=3 then x=3+y
so
(3+y)^2+y^2=29

now expand the brackets, simplify, bring 29 over to the LHS and then sove as a quadratic.
why don't you have a go a this now.
if you get stuck I'll help some more.

MelodyNov 26, 2013

+118727

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Moving in relation to what?
If it is moving at 20km/hour and the car next to it is also moving at 20km/hour in exactly the same direction then both cars are stationary in relation to each other.

how about that!

MelodyNov 26, 2013

+118727

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Thank you. I love mathematics and I want to share my enthusiasm with others.
If I help others to understand and to enjoy the experience that is all I want.
It is always really nice when you are appreciated even it you are doing what you want to do most.
so again, thank you.

MelodyNov 26, 2013

0

I really appreciate that you took all this time to try and help us.I truly astounded by your publish regards. I really appreciate that you took all this time to try and help us.Your work is carry the information to the other people.

GuestNov 26, 2013

+118727

0

Water from a stream is used to drive a water wheel. The stream provides 6000kg of water per minute to the wheel. The water falls a vertical height of 5 meters.
Show that the maximum power available to the wheel from the water is 5000W. Halp?

okay, I admit it, I don't know about this stuff but
I just googled "what is a watt" and I was told that

1W = 1Kg*m^2 / s^3

So I am just going to use the units and there is a reasonable chance that I will get the right answer.

You have 6000kg/min = 6000/60 Kg/sec = 100Kg/sec
You have gravity which is 9.8m/s^2
You have 5m

Kg/sec * m/s^2 * m = Kg*m^2/sec^3 Well that is the units that I want
100 * 9.8 * 5 = 4900W
If I had rounded gravity off to 10m/s^2 I would have 5000W
This is the maximum because some of the energy will be lost. (eg noise I think but again I don't really know what I am tallking about)

The motto of this story is:

Always use the units to help you

MelodyNov 26, 2013

+118727

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1x2x3x4x5x6x7x8x9x10x11x12x13x14x15x16x17x18x19x20

this question is driving me crazy

19*18 ends it a 2 (9*8=72) I'll come back to 20
so 19*18*17 ends with a 4 (2*7=14)
so 19*18*17*16 ends with a (4*6=24) 4
so 19*18*17*16*14 ends with a (4*4=16) 6 I'll come back to 15
so 19*18*17*16*14*13 ends with a (6*3=18) 8
so 19*18*17*16*14*13*12 ends with a(8*2=16) 6
so 19*18*17*16*14*13*12*11 ends with a (6*1=6) 6
9*8=72
so 19*18*17*16*14*13*12*11*72 ends with (6*2=12) 2 I'll come back to 10
7*6=42
so 19*18*17*16*14*13*12*11*9*8*42 ends with(2*2=4) 4 I'll come back to 5
4*3*2*1 = 24
so 19*18*17*16*14*13*12*11*9*8*24 ends with (4*4=16) 6
Now we haven’t done
5*15*10*20 = 5*20*10*15=15000
So we have at least 3 zeros
5*6=30 so there is the 4th zero.

This is really clutsy - there must be a better way of doing it.

By the way, there is only one 'e' in zeros.

MelodyNov 26, 2013

+118727

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I am really glad that i could help you. I always like getting feedback and it is great when the feedback is so positive.
Thank you.

MelodyNov 26, 2013

+118727

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if john and susie both collected 87 pieces of candy, and susie takes 13%, how many pieces does john have

Do you mean that they collected 87 peices each or 87 pieces altogether?

anyway
All the lollies put together is 100%
If Suzie gets 13% John gets the rest which will be 100-13% = 87%

So if there are 87 lollies altogether, John gets 87% of 87 = 87/100*87 = 75.69 lollies

MelodyNov 26, 2013

-1

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Thanks so much with this fantastic new web site. I'm very fired up to show it to anyone. It makes me so satisfied your vast understanding and wisdom have a new channel on the world.

Vin DieselNov 26, 2013

0

Mathzo:
One of the answers is 0.375 + 0.375

GuestNov 26, 2013

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