All Answers 358087 Answers

Indeed, Cupcakes are most delicious.

1000(1+[0.04/12])^(3*12)

Okay Rosala,  I gave you the mod 3 points because I believe you really did try to do it and that you will learn from Heureka's answer. 

You are not going to be untrue to my assumption are you Rosala.  

It is a normal calculator.  It is exact except where rounding is unavoidable.

Thanks Takahiro, I like cup cakes. That is most thoughtful of you.  :)))

I am feeling generous though.

I'll have one, You can have one, and how about we give the other one to CPhill.

what say you???    

Thanks Tetration your way will work well.

Here is another way :)

if $ 85 is put in account that gets 8.5%pa and I add $15 at the end of each year how much will I have at the end of 8 years

the 85$ will grow to  85*(1.085)^8

The first 15 will grow to 15(1.085)^7

The second 15 will grow to 15(1.085)^6

........

The last 15 only just goes in the bank so it will be 15

$$\\15+15(1.085)+15(1.085)^2 .........15(1.085)^7$$

This is a GP  a=15 r=1.085 n=8

$$\\S_n=\frac{a(r^n-1)}{r-1}\\\\
S_8=\frac{15(1.085^8-1)}{1.085-1}\\\\
S_8=\frac{15(1.085^8-1)}{0.085}\\\\$$

so total =  $$85(1.085)^8+\frac{15(1.085^8-1)}{0.085}\\\\$$

$${\mathtt{85}}{\mathtt{\,\times\,}}{\left({\mathtt{1.085}}\right)}^{{\mathtt{8}}}{\mathtt{\,\small\textbf+\,}}{\frac{{\mathtt{15}}{\mathtt{\,\times\,}}\left({{\mathtt{1.085}}}^{{\mathtt{8}}}{\mathtt{\,-\,}}{\mathtt{1}}\right)}{{\mathtt{0.085}}}} = {\mathtt{325.710\: \!957\: \!814\: \!451\: \!144\: \!3}}$$

After 8 years it will be    $325.00

An asteroid has a diameter of 10km and is at a distance of 10^6km, what angle in degrees does it subtend ?

$$\tan{ ( \frac{ \Theta\ensurement{^{\circ}} } {2} ) } = \dfrac{ 5\ km } { 10^6\ km } = 5*10^{-7}\\\\
\frac{ \Theta\ensurement{^{\circ}} } {2} = 0.00002864789\ensurement{^{\circ}}\\\\
\Theta\ensurement{^{\circ}} =0.00005729578\ensurement{^{\circ}}\\\\
\Theta^{'}=\Theta\ensurement{^{\circ}} \times
\dfrac{60^{'}}
{ 1\ensurement{^{\circ}} }
= (0.00005729578 * 60)^{'} = 0.00343774677^{'}\\\\
\Theta^{"}=\Theta^{'}\times
\dfrac{ 60^{"} }
{ 1^{'} }
= (0.00343774677* 60)^{"} = 0.20626480625^{"}$$

Not quite anon, you forgot the x    

Thanks Alan, 

And yes, very amusing Nauseated    

i was reading zegroes's commentsand i started yawning

Whenever you are given a negative exponent, the value is flipped into it's reciporical. In this case, it is flipped back to 2. 

(-1)^-2  =  1/(-1)²  =  1/1  =  1

So:  1 - 4(-1)^-2  =  1 - 4(1)  =  1 - 4  =  -3

If the problem is:  (2p + 3q)/q  =  3/8

cross multiply:  (2p + 3q)(8)  =  (3)(q)

simplify:           16p + 24q  =  3q

subtract 24q from both sides:  16p  =  -21q

divide both sides by q:       (16p)/q  =  -21

divide both sides by 16:           p/q  =  -21/16

If you have an exponent to an exponent, multiply the exponents together:

--->   (5⁴)²  =  5^{4 x 2}  =  5⁸

You can think of it this way:  the first exponent (the 4) tells you how many 5's you have in each group; the second exponent (the 2) tells you that you have 2 groups. When you have 2 groups with 4 in each group, you have 2 x 4 or 8 items; in this case, you have eight 5's multiplied together.

What does that have to do with math -_-

the circumfrence of the sun is  2,713,406 miles and weighs 2,000,000,000,000,000,000,000,000,000,000 kg :D

Easy, take mars weighs 799,374,755,668.4536682379778765kg, then times the moon (2217311939096852668kg + water= 2356506768659814058 kg) which =1883732022428496134697582418031.604044407687837kg -_-

We multiply the numerators by each other. This will be the numerator for the answer.  9 x 1 = 9

We repeat the first step for the denominator.         14 x 6 = 84

Then we put them together.            9/84

Lastly we simplify     3/28

= 3/28

(-1/2)^-4 x (-1/2)^2

16 x (-1/2)^2

16 x 1/4

=4

Use matrix code 39.84 x 30, take the answer and divide it by 83724.234713947129400128743628374 and run the codes in cmd.exe, run notepad to find out or look up matrix code on youtube. XD

I agree XD

116 000 000 x 0.33 (33%) = 38 208 000

38 208 000 x 0.56 (56%) = 21 396 480

21 396 480 = 21.40 million households in the U.S. own at least two cats.