Answer: 53
1. Assign each digit a variable, let's call the 10's digit x, and the 1's digit y.
2. Set up a system of equations.
The first equation is the simplest, it is that (x + y = 8)
The second is tougher, The value of the number in terms of x and y is (10x + y). Assume the digits are 1 and 2, if x = 1 and y = 2 then we know the number is 12, but 1 + 2 is not 12, it is 3. In order to get 12 we must multiply the 10's digit (x) by 10 and add the y digit, since it is a 2 digit number. If it was a 3 digit number then the 100's digit would be multiplied by 100 and so on.
So now this gives us the second equation (10x + y = 11x - 2) the second part comes from the fact that the number is 11 times the 10's digit minus 2.
Now use substitution, from the first equation we get that (x = 8 - y). If we substitute this in for all the x's in the 2nd equation, and simplify we would get (80 - 9y = 86 - 11y). Simplify again and we get (2y = 6).
Now you can do the rest.