All Answers 358180 Answers

Tues 3/3/15

See the sticky note on fractions.  It is on the bottom left of this screen. 

Thanks Alan,

The answer is the x value where y=25 on Alan's graph.

if cos theta = 2/3 find tan theta 

could be  1st or 4th quad

adj = 2

hyp = 3

opp = $${\sqrt{{\mathtt{9}}{\mathtt{\,-\,}}{\mathtt{4}}}} = {\sqrt{{\mathtt{5}}}}$$

$$tan\theta=\frac{opp}{adj}=\pm \frac{\sqrt{5}}{2}$$

However, if n is not an integer we have

$$\\5*2^n=200\\\\
2^n=40\\\\
log 2^n=log 40\\\\
nlog 2=log 40\\\\
n=\frac{log 40}{log 2}\\\\$$

$${\frac{{log}_{10}\left({\mathtt{40}}\right)}{{log}_{10}\left({\mathtt{2}}\right)}} = {\mathtt{5.321\: \!928\: \!094\: \!887\: \!362}}$$

this answer is approximate.

1.03^480

$${{\mathtt{1.03}}}^{{\mathtt{480}}} = {\mathtt{1\,451\,669.855\: \!024\: \!725\: \!862\: \!255\: \!5}}$$

like

5^(1/3)

If I open the maths formual box above and insert 5^(1/3), then the output is shown below.

$${{\mathtt{5}}}^{\left({\frac{{\mathtt{1}}}{{\mathtt{3}}}}\right)}$$

I hope that helps.

Perhaps you mean the 2nd function in the top corner? 

This question does not make much sense.   

1. Change each number to an improper fraction

2 2/7 = 16/7,    3 1/3 = 10/3

2. To divide by a fraction turn the fraction in the denominator upside down and multiply instead:

(16/7)/(10/3) =  (16/7)*(3/10)

$$\left({\frac{{\mathtt{16}}}{{\mathtt{7}}}}\right){\mathtt{\,\times\,}}\left({\frac{{\mathtt{3}}}{{\mathtt{10}}}}\right) = {\frac{{\mathtt{24}}}{{\mathtt{35}}}} = {\mathtt{0.685\: \!714\: \!285\: \!714\: \!285\: \!7}}$$ 

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Assuming no resistance from the air (unrealistic in the case of a football!) the time of flight is given by:

0 = 19.5*sin(45°)*t - (1/2)*9.8*t², taking g = 9.8m/s² (this comes from considering the vertical motion)

$${\mathtt{t}} = {\frac{{\mathtt{19.5}}{\mathtt{\,\times\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{sin}}{\left({\mathtt{45}}^\circ\right)}{\mathtt{\,\times\,}}{\mathtt{2}}}{{\mathtt{9.8}}}} \Rightarrow {\mathtt{t}} = {\mathtt{2.813\: \!996\: \!374\: \!111\: \!530\: \!6}}$$ seconds

The horizontal distance travelled by the ball is  s = 19.5*cos(45°)*t

$${\mathtt{s}} = {\mathtt{19.5}}{\mathtt{\,\times\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}{\left({\mathtt{45}}^\circ\right)}{\mathtt{\,\times\,}}{\mathtt{2.813\: \!996\: \!374\: \!111\: \!530\: \!6}} \Rightarrow {\mathtt{s}} = {\mathtt{38.801\: \!020\: \!408\: \!212\: \!922\: \!5}}$$ metres

The player must therefore run a distance of (55 - s) metres in a time t seconds, so his average speed must be (55 - s)/t m/s

$${\mathtt{v}} = {\frac{\left({\mathtt{55}}{\mathtt{\,-\,}}{\mathtt{38.801}}\right)}{{\mathtt{2.814}}}} \Rightarrow {\mathtt{v}} = {\mathtt{5.756\: \!574\: \!271\: \!499\: \!644\: \!6}}$$ m/s

or v ≈ 5.76 m/s

.

Huh?  Has this been answered somewhere else?

Anon1, you have made an error.  But it was a good try!   

Thanks 2nd anon for saying this - I have just seen CPhill's answer,

It is really time comsuming when people double post. 

And it means other people are more likely to receive no answer at all!

Not if n is an integer:

5*2ⁿ = 200 means 2ⁿ = 40 , but 2⁵ = 32 and 2⁶ = 64.

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Mass is the same wherever you are.

Weight is mass*g, so on Earth weight = 50*9.81 = 490.5 N, and on the Moon weight = 490.5/6 = 81.75 N

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Sure it has an answer!  You can see by drawing a graph:

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Another approach to this is to divide through by the product on the right-hand side of each equation, so that we get:

1/b + 1/a = 4

1/c + 1/b = 5

1/a + 1/c = 3

Now let A = 1/a, B = 1/b and C = 1/c, so the equations become

B + A = 4            (1)

C + B = 5            (2)

A + C = 3            (3)

Subtract (3) from (2) to get B - A = 2

Add this to (1) to get 2B = 6 so B = 3, so b = 1/3

Put B back into (1) to get A = 1, so a = 1

Put B back into (2) to get C = 2, so c  = 1/2

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It has no awnser...

Well search up WheelerDeWitt Equation

waz nin' plus ten' . twenny wun

It is $${\mathtt{9}}{\mathtt{\,\small\textbf+\,}}{\mathtt{10}} = {\mathtt{19}}$$

$${\mathtt{40\,000\,000}}{\mathtt{\,\times\,}}\left({\frac{{\mathtt{31}}}{{\mathtt{100}}}}\right) = {\mathtt{12\,400\,000}}$$

It is 12,400,000

$${\mathtt{window}} = {\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}} \Rightarrow {\mathtt{window}} = {\mathtt{2}}$$

Let me guess... you posted this because you can...

that is if 1+1=2 but it doesnt. 9+10=21

tghen the world would go pop and dinos would come back and r**e the vampires