All Answers 358156 Answers

$${\frac{{\mathtt{4}}}{{\mathtt{5}}}} = {\mathtt{0.8}}$$

$${\mathtt{2}}{\mathtt{\,\small\textbf+\,}}{\mathtt{0.8}} = {\frac{{\mathtt{14}}}{{\mathtt{5}}}} = {\mathtt{2.8}}$$

For a sequence a₁, a₂, a₃, . . . , a_n, . . . a recursive formula is a formula that requires the computation of all previous terms in order to find the value of a_n

NNNAAAWWW!!!

10n²-10n-7n+7

10n(n-1)-7(n-1)

(10n-7)(n-1)

There has to be an easier way.

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If you want to enter pi in the calc you can just write pi

There is no question here.

Hi Cemone. :)

Why don't you join up and then I will learn who you are :)

YES it is !

PEDMAS

Is there something confusing you?

Here is an old post on this topic - it will help you.

the video clip at the end is very good too.  :D

You need to find 2 numbers that multiply to 70 and add to -17   I'll call them A and B

Now   split -17n into  An+Bn  and replace it in the expression  ( there will be some minus signs there)

Now factorise the first 2 terms and the second 2 terms seperately.

then think about it  and maybe tell me what you have and I will talk you through the last step.

It is a decimal.

Well I probably can't but if you do not present it no one else can either.  That is a certainty :))

$${\frac{{\mathtt{7}}}{{\mathtt{100}}}} = {\mathtt{0.07}}$$

$${\frac{{\mathtt{2}}}{{\mathtt{14}}}} = {\frac{{\mathtt{1}}}{{\mathtt{7}}}} = {\mathtt{0.142\: \!857\: \!142\: \!857\: \!142\: \!9}}$$

$${\frac{{\mathtt{63}}}{{\mathtt{54.897\: \!2}}}} = {\mathtt{1.147\: \!599\: \!513\: \!272\: \!079\: \!5}}$$

$${\frac{{\mathtt{3}}}{{\mathtt{4}}}}{\mathtt{\,-\,}}\left({\frac{{\mathtt{2}}}{{\mathtt{7}}}}\right) = {\frac{{\mathtt{13}}}{{\mathtt{28}}}} = {\mathtt{0.464\: \!285\: \!714\: \!285\: \!714\: \!3}}$$

$${\mathtt{0.07}}{\mathtt{\,\times\,}}{\mathtt{9.5}} = {\frac{{\mathtt{133}}}{{\mathtt{200}}}} = {\mathtt{0.665}}$$

2(n-7)+3=9  subtract 3 from both sides

2(n - 7)  = 6   divide both sides by 2

n - 7  =  3      add 7 to both sides

n = 10

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ok thanks for asking

thanks for the feed back and i'm the same girl from the nathan post my name is cemone by the way.

We could do some "math' here....but  let's use some logic

One number must be positive and one must be negative if their product is a negative

Look at the factors of -15

-15  and 1

-1 and 15

-5  and  3

5 and -3

Notice that the last one produces a sum of 2

Those must be the two numbers we need.....!!!

The heights of the hill and the post  (=  the man's eye level ) are irrelevant.

If a 200 foot string is tied is to the base of the tree from the top of the post, this serves as the hypotenuse of a right triangle. And a line drawn from the top of the post to the tree and running parallel to the ground would form one leg of this triangle. Call this distance "D"

And the angle between the string and "D" is 20°

So "D"  = 200cos 20 = 187.94 ft

And the partial height of the tree from the base to the point where "D" interesects the tree forms the remaining leg of this right triangle and is given by 200sin 20  = 68.4 ft

And the rest of the tree's height can be found thusly

187.94*tan 12 = 39.95 ft

So.....the total height of the tree is just 68.4 + 39.95 = 108.35 ft

Thanks to Melody for pointing out my small error!!!

i think i broke myself