There are other ways - this is the easiest.
(4x-9)(x-1)
should the x+1 be in brackets?
$$\\5(10^x+1)=12\\ 10^x+1=12.4\\ 10^x=11.4\\ log10^x=log11.4\\ x=log11.4\\$$
They are two different numbers.
$${{\mathtt{8}}}^{{\mathtt{67}}} = {\mathtt{3\,213\,876\,088\,517\,980\,551\,083\,924\,184\,682\,325\,205\,044\,405\,987\,565\,585\,670\,602\,752}}$$
$${\mathtt{8\times 10^{67}}}$$ equals 8 with 67 zeros after it.
Sorry, It was (7x+1)(x+2) Now use Foil :) You have to factor it to get 7x+14x+1x+2 then use GCF Which earns you 7x(x+2)+1(x+2) Then distrubitive property which becomes (7x+1)(x+2) e.e Sorry.
Whoops Let me update. I didn't see the seven.
^ He's more reliable than I am ... e.e
I only copied it to make sure that I did not miss anything.
FOILing resulted in an incorrect answer. :}
deleted deleted
Copy cat.... :( ^
(x+14)(x+1) I may be wrong e.e Use F.O.I.L (First, Outer, Inner, and Last) To check.
Anonymous
This results in x2+15x+14
Multiply Ac then factor it to get the sum of B, for FYI
$${\mathtt{1\times 10^{21}}}$$
this 1 with 21 zeros after it.
You could Use the factor formula, Multiply AC then factor it to get the sum of B. For heads up.
How many hours did you work?
That was me e,e ^
the sides of a 30 60 90 triangles are
x, x√3 and 2x
the hypotunuse in opposite of the 90.
if hypotunuse = 16 then plug it in 2x and solve for x, you get 8
plug the x=8 in x√3 which equals 8√3, which is one of your sides
the other side is simply 8. solve for the area 1/2(8)(8√3) and you still get 55.43
You are absolutely correct, your teacher done goofed
(7x+1)(x+2)
$${\frac{{\mathtt{238\,502\,845\,295\,826\,395\,942}}}{{\mathtt{2}}}} = {\mathtt{119\,251\,422\,647\,913\,197\,971}}$$
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Yes. If you add 5+5 first, and then multiply by 2, don't you get 20?
My calculator gives me 1 when I ener this directly. What gives?
