All Answers 358149 Answers

Nice pic Chris :)

I don't know Melancholy, your original equations are different from the ones in the question. 

2 minutes  = 120 seconds   ...  so ....

48.5 / 120  =   485 / 1200 = about 40.4%

Yeah...I got the same answer, Melody.....I believe this is correct because one box looks like another....and all the b***s look the same.....

6x^2 + 8x - 128 = 0    divide everything by 2

3x^2 + 4x - 64 = 0       factor...  and set each factor to 0

(3x + 16) (x - 4) = 0

One solution is x = 4

The other is x = -16/3

I think Geno may have answered for if everything is distinguishable.

If the b***s and the boxes are not distinguishable   (the same)  then

the only difference is how many are in the boxes.

5,0,0

4,1,0

3,2,0

3,1,1

2,2,1

I think that is it.

5 possibilities     

(8b^(2/3)*9t^(1/5)) (8b^(5/3)*9t^(3/5)) ......  rearrange.......

[8b^(2/3) * 8b^(5/3)] * [ 9t^(1/5) * 9t^(3/5) ] =

[64 b^(7/3)] * [ 81 t^(4/5) ] =

5184* b^(7/3)* t^(4/5)

And that's it.....!!!!

If SinB = -3/4   ....then....

cosB  =  -√(16 - 9) / 4 =   -√7/4

So

sin (90- B)  =

sin 90 cos B - sin B cos 90  =

sin  90 cos B  =

1 * cos B =

(1)  (-√7/4)  = 

 -√7/4

This could also be  $249 + $12.36  = $261.36   ......who knows ???

(sec^2x)(cot^2x)(sinx)

(1/cos^2 x ) (cos^2 x / sin^2 x) (sin x) =

(cos^2x / cos^2x) (sin x / sin^2x) =

1 / sin x =

csc x

Welll, MG1....there wasn't any "factorizing" in the second one.....just multiplying and  "cancelling"

In the first......is see that (6x - 12) can be factored by taking out the greatest common factor between 6 and 12, which is 6....so..... that leaves us with 6(x - 2).....and as I said, the "x - 2" factors "cancel" in both numerator and denominator.....

Does that make sense ???

Nice answer, MG1...!!!!

Note....if you wanted to  add   21/36  + 20/36  in one step.....use parentheses like this.....

(21 + 20) / 36   =  41/36

Thanks, Alan....that explanation is very clear......

Nauseated......could you explain your answer???.....like Melody, I'm curious to see how you arrived at that......(even though it's correct)

If you are a member.....your points will add up......we give points for good answers as well as  "good tries".....some questions (particularly, the "counting" problems) are sometimes subject to different interpretations - to say the least.....LOL!!!!

Yep.....after reconsidering....I don't like my answer at all..I realize there might be some double - if not "triple" counting in mine....I'll look at Melody's  answer in more detail......but.....just not right now.....

Yep - looks good to me :)

write an equation passing through the point and parallel to the given line (-2, 3);      y= -1x + 4

Well the gradient will be 1.

so ther are lots of ways to do it now.

I like  to say

gradient = gradient

$$1=\frac{y-3}{x--2}$$

etc

If the density of methane gas is 0.66kg/m3, then what is the density of methane in cm3 ?

$$0.66\ \dfrac{ \rm{kg} } { \rm{m^3} } \\\\
=0.66\ \dfrac{ \rm{kg} } { \rm{m}\cdot\rm{m}\cdot\rm{m} } \\\\
=0.66\ \dfrac{ \rm{kg} } { \rm{m}\cdot\rm{m}\cdot\rm{m} }
\cdot \dfrac{ 1\ \rm{m} }{ 100\ \rm{cm }}
\cdot \dfrac{ 1\ \rm{m} }{ 100\ \rm{cm }}
\cdot \dfrac{ 1\ \rm{m} }{ 100\ \rm{cm }}\\\\
=0.66\ \dfrac{ \rm{kg} } { \rm{\not{m}}\cdot\rm{\not{m}}\cdot\rm{\not{m}} }
\cdot \dfrac{ 1\ \rm{\not{m}} }{ 100\ \rm{cm}}
\cdot \dfrac{ 1\ \rm{\not{m}} }{ 100\ \rm{cm}}
\cdot \dfrac{ 1\ \rm{\not{m}} }{ 100\ \rm{cm}}\\\\
=0.66\ \dfrac{ \rm{kg} } { 100\ \rm{cm } \cdot 100\ \rm{cm} \cdot 100\ \rm{cm} } \\\\
=0.66\ \dfrac{ \rm{kg} } { 100\cdot 100\cdot 100\cdot \rm{cm}\cdot \rm{cm}\cdot \rm{cm}} \\\\
=0.66\ \dfrac{ \rm{kg} } { 100\cdot 100\cdot 100\cdot \rm{cm^3}} \\\\
=\dfrac{0.66\ }{100\cdot 100\cdot 100}\cdot \dfrac{ \rm{kg} } { \rm{cm^3}} \\\\
=\dfrac{0.66\ }{10^2\cdot 10^2\cdot 10^2}\cdot \dfrac{ \rm{kg} } { \rm{cm^3}} \\\\
=\dfrac{0.66\ }{ 10^6 } \cdot \dfrac{ \rm{kg} } { \rm{cm^3}} \\\\
=0.66\cdot 10^{-6} \cdot \dfrac{ \rm{kg} } { \rm{cm^3}}$$

$$\\=6.6 \cdot 10^{-1} \cdot 10^{-6} \cdot \dfrac{ \rm{kg} } { \rm{cm^3} }\\\\
=6.6 \cdot 10^{-7}\cdot \dfrac{ \rm{kg} } { \rm{cm^3} }\\\\$$

Thanks Geno,

I would not have thought of that. :)

its near the numbers on the plus - ctrl

The ugly and scruffy work is the best work.

(Unless you write it out again LOL)

thanks Alan