> The probability of snow for each of the next three days is 3/4
If we denote the probability of snow on any one day as P(S) then in my working I interpreted the above statement to mean P(S) = 0.75
HOWEVER, it is possible that the 3/4 probability is actually the probability of three consecutive days of snow, i.e., of no snow-free days,
so P(S)*P(S)*P(S) = 3/4
making P(S) = cube_root(0.75) ≈ 0.9086
Therefore, P(no snow) * P(no snow) * P(no snow)
= (1 - cube_root(0.75))^3
This is approx 0.0007645
These are the only 2 interpretations I would entertain.
☝ ☝
The probability of snow for each of the next three days is $\frac{3}{4}$. - See more at: http://web2.0calc.com/questions/the-probability-of-snow-for-each-of-the-next-three-days-is-frac-3-4-what-is-the-probability-that-it-will-not-snow-at-all-during-the-ne#sthash.TXLvkJ4X.dpuf
The probability of snow for each of the next three days is $\frac{3}{4}$. - See more at: http://web2.0calc.com/questions/the-probability-of-snow-for-each-of-the-next-three-days-is-frac-3-4-what-is-the-probability-that-it-will-not-snow-at-all-during-the-ne#sthash.TXLvkJ4X.dpuf
