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Oops.... I made a slight error

It should be

(57/tan15 - 57/tan25) =   about 90.49m

I'll give you a pic in a second......

1. the answer is meant to be 91 m but i dont get how? can someone expain it to me please. thanks

Remember that  we have the co-function identity....

csc(u)  = sec(pi/2 - u)   ....so....

If csc(x)  = 4

Then....sec(pi/2 - x)  also = 4

thank you thank you

Good job, Heather  !!!    (LOL !!!)

there you happy cphill?

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(7-3)+(x-4x-9x)

(4)+(4x-10x)

(4)+(-6x)

4-6x

hehehe i found titanium rome's camp. wait until Brittany comes on and starts getting scared. XD

1 / [ 1 + sinΘ]  + 1 / [1 - sinΘ]  getiing a common denominator, we have

[1 - sinΘ + 1 + sinΘ ] / [ 1 - sin²Θ]  =

2/[1- sin²Θ] =

2/cos²Θ  =

2sec²Θ

If cot(x)  = 5, we have  x/y  = 5/1

So 

r = √[5^2 + 1^2] = √[25 + 1 ] = √26

And csc(x) = r / y = √26  / 1   =  √26

wait, what?

No, Heather....re-read.....

f(t-1)  = (t-1)^3 + 6(t-1)^2 + 12(t-1) + 8  =

[t^3 - 3t^2 + 3t - 1] + [6t^2 - 12t + 6] + [12t - 12 ] + 8 =

t^3 + 3t^2  + 3t + 1     =  (t + 1)^3

So...the coefficients  are  (1,3,3,1 )

lol! wait till titanium comes on!

k x+4x=5x-9x=-4x

7-3=4

overall, this expression in simplest  form would be:

4--4X

(uh, wish titanium rome doesnt come on and starts on his "number thingys")

actually alan did, cphill.

ahhh so this is what my friend's been up to. chattin' with brittany. hehehe

k lets see what titanium romes been up to

i already feel so dumb right now

cosΘ - tanΘ   =0     add tanΘ  to both sides

cosΘ  = tanΘ

The easiest way to solve this - IMHO - is with a graph.......here it is....

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7x+5z=4+8y   subtract 4 from both sides

7x + 5z - 4  = 8y      divide both sides by 8

[7x + 5x - 4] / 8  = y

I think this is supposed to be :

cotΘtanΘ  =

[cosΘ / sinΘ ] [sinΘ / cosΘ]=

1