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$$one\;more\;time\; // \frac{1}{2}$$after ''that'' i never did //

whats the problem in mine MElody?

Can you work out why it has displayed incorrectly MG ?

$$Ok\:I'll\:try\:that

\frac{1}{2} /// \frac{2}{5}$$

I'm ALWAYS right ! Just kidding.

$$Cool\:I\:didn't\:know\:that!$$

$$Cool\quad I\quad didn't\quad know\quad that$$

$$Cool\;I\;didn't\;know\;that$$

$$Cool\qquad I\qquad didn't\qquad know\qquad that\qquad$$

$$$ I didnt $$$
know that$$$
Melody!$$

is that correct?why is there such a big gap between lines?

• Spirytus Polish Vodka is 96% alcohol by volume.

1. How much cranberry juice would have to be added to 500mL of this vodka  resultant mixture with an alcohol content of 12%

Volume of alcohol= 0.96 x 500mL

Total Volume: 500+C, where C is volume of cranberry juice

0.96 x 500/(500 + C) = 0.12

0.96 x 500 = 0.12 x ( 500 + C)

0.96 x 500/0.12 - 500= 3500

So you must add  3500 mL of cranberry juice

b. How much Smirnoff Vodka with an alcohol content of 37.5% by volume would have to be added to 500mL of Smirnoff Vodka to get a resultant mixture of 55% alcohol.

I see what you are doing MG, you are using the enter button to move to a new line.

Yes that will work,  however if you use fractions afterwards, they stuff up.

So it is better to use  \\   or   \\\\  or  \\\\\\  to go to a new line or to skip lines :)      [corrected]

not much it does!

There are many different ways of doing things in LaTex.

I have never used the $ like rosala just showed you.  Thanks Rosala.

I also do not understand why yours jumped to different lines but Rosala's stayed on the same line.

If I want a break I usually use \;  or  \:  or  \quad    or   \qquad

\; and \: give little breaks, \quad gives a slightly bigger break (maybe 4 units) and \qquad gives a bigger gap again (maybe 8 units)

1 \: 2 \; 3 \quad 4 \qquad5       See how the gaps get bigger :)

$$1\:2\;3\quad 4\qquad5$$

spaces in Latex, using the space bar, are usually meaningless :)

An important thing to know is that the symbol for a new line is \\

If you want to skip a line you would uses \\\\

do u want to say you cnat add in a sign between them

$$$$\frac{2}{3}$$,$$\frac{4}{5}$$$$

is that what you were asking?

$$$$$\frac{1}{2} \frac{2}{5}$$$$$

Nice.

$$$\frac{1}{2} \frac{2}{5}$$$

spacing matters?

$$$$$$$ Any much! $$$$$$

that was to show you ...you can put as many as you want and leaving a gap and writing or not leaving a gap and writing makes no difference!

yes it can be use din fractions!

Oh ok.

So only 3

$$$I'm doing good!$$$

Okay the calc does give you 0

$${\frac{{{\mathtt{35}}}^{{\mathtt{2}}}}{{\left({\mathtt{8.574}}{\mathtt{\,\times\,}}{{\mathtt{10}}}^{{\mathtt{10}}}\right)}^{{\mathtt{2}}}}} = {\mathtt{0}}$$

Lets have a look by breaking it up

$${{\mathtt{35}}}^{{\mathtt{2}}} = {\mathtt{1\,225}}$$

$${{\mathtt{8.574}}}^{{\mathtt{2}}} = {\mathtt{73.513\: \!476}}$$

$$=\frac{1225}{73.513476\times 10^{20}}
=\frac{1225\times 10^{-20}}{73.513476}$$

$${\frac{{\mathtt{1\,225}}}{{\mathtt{73.513\: \!476}}}} = {\mathtt{16.663\: \!611\: \!444\: \!519\: \!369\: \!5}}$$

$$\\=\frac{1225}{73.513476\times 10^{20}}\\
=\frac{1225\times 10^{-20}}{73.513476}\\
=16.6636\times 10^{-20}\\
=1.66636\times 10^{+1}\times 10^{-20}\\
=1.66636\times 10^{-19}\\$$

okay, this is NOT zero  the calculator called it zero because the number is tiny.  Too tiny for the calc to display properly.

$$\frac{1}{2}$$\frac{2}{5}$$

How many dollar signs are needed

Edit

Can it be used on fractions?

$$$\frac{1}{2}and\frac{2}{5}$$$

mathsGod...honestly i take chances in this!

$$$Hi! Wass Up?$$$

so if you want the line to be with spaces....write like this!

Hi Rosala,

Gap?

so like.

$$Hello$$$$I$$$$am$$$$MathsGod1$$

Or just one  $$$Hello$I$Am$MathsGod1$$

as much as ive used latex.....i use $$$$....this sign to give gaps!you can use it to...try?

$$\frac{1}{2}$$

All I know so far is fractions.

$$5\frac{1}{2}$$

The lowest common denominator is 6

thank you Melody!

Good answer Rosala :)

Volume of alcohol = 0.96*500 mL

Total volume = 500 + C   where C is volume of cranberry juice

0.96*500/(500 + C) = 0.12

0.96*500 = 0.12*(500 + C)

0.96*500/0.12 = 500 + C

C = 0.96*500/0.12 - 500

$${\mathtt{C}} = {\frac{{\mathtt{0.96}}{\mathtt{\,\times\,}}{\mathtt{500}}}{{\mathtt{0.12}}}}{\mathtt{\,-\,}}{\mathtt{500}} \Rightarrow {\mathtt{C}} = {\mathtt{3\,500}}$$

So you must add 3500 mL of cranberry juice.

.